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关于SQL的查询统计的疑问，仅请大大们细看。。。在线等。。。。
CREATE table Card(日期 DATETIME, 卡号 CHAR(10), 姓名 CHAR(20))
CREATE table chuqiao(日期 DATETIME, 卡号 CHAR(10), 存款金额 INT)
CREATE table xf(日期 DATETIME, 卡号 CHAR(10), 消费产品 CHAR(10), 结帐方式 CHAR(10), 数量 INT, 单价 INT, 金额 INT)
INSERT INTO Card VALUES('2008-2-9','392332', 'Wangxiaoyan')
INSERT INTO Card VALUES('2008-2-11','444330', 'Wangmss')
INSERT INTO Card VALUES('2008-2-15','392411', 'Guomoruo')
INSERT INTO Card VALUES('2008-2-18','392833', 'Lidake')
INSERT INTO Card VALUES('2008-2-27','492129', 'Wangyiguang')
INSERT INTO Card VALUES('2008-2-27','623356', 'Dengzhuzhu')
INSERT INTO chuqiao VALUES('2008-2-11','392332', 300)
INSERT INTO chuqiao VALUES('2008-2-15','392332', 300)
INSERT INTO chuqiao VALUES('2008-2-15','392411', 150)
INSERT INTO chuqiao VALUES('2008-2-16','392332', 100)
INSERT INTO chuqiao VALUES('2008-2-20','392411', 450)
INSERT INTO chuqiao VALUES('2008-2-21','392823', 100)
INSERT INTO chuqiao VALUES('2008-2-27','392129', 400)
INSERT INTO chuqiao VALUES('2008-2-27','392332', 120)
INSERT INTO xf VALUES('2008-2-9', '392233', 'AAA','现金', 1,12,12)
INSERT INTO xf VALUES('2008-2-11', '392233', 'BBB','现金', 1,12,12)
INSERT INTO xf VALUES('2008-2-15', '392233', 'AAA','扣存款', 1,12,12)
INSERT INTO xf VALUES('2008-2-15', '------', 'BBB','现金', 1,30,30)
INSERT INTO xf VALUES('2008-2-16', '392411', 'BBB','扣存款', 2,5,10)
INSERT INTO xf VALUES('2008-2-16', '392332', 'AAA','扣存款', 2,12,24)
INSERT INTO xf VALUES('2008-2-20', '------', 'DDD','现金', 1,30,30)
INSERT INTO xf VALUES('2008-2-23', '------', 'DDD','现金', 1,30,30)
INSERT INTO xf VALUES('2008-2-23', '392233', 'CCC','信用卡', 3,10,30)
INSERT INTO xf VALUES('2008-2-25', '392233', 'CCC','扣存款', 3,10,30)
INSERT INTO xf VALUES('2008-2-27', '392233', 'EEE','现金', 9,1,9)
INSERT INTO xf VALUES('2008-2-27', '392233', 'AAA','现金', 1,11,11)
INSERT INTO xf VALUES('2008-2-27', '392233', 'AAA','扣存款', 1,11,11)
INSERT INTO xf VALUES('2008-2-27', '392233', 'BBB','现金', 3,5,18)
INSERT INTO xf VALUES('2008-2-27', '392233', 'BBB','信用卡', 2,5,10)
select isnull(isnull(t1.dt,t2.dt),t3.dt) dt , t1.开卡数 ,t2.存款数 ,t2.存款金额 ,
t3.消费单数,t3.消费金额,(t2.存款金额+t3.现金结帐金额) as 当天全部现金,
t3.现金结帐数,t3.现金结帐金额,t3.扣存款结帐数,t3.扣存款结帐金额,t3.信用卡结帐数,t3.信用卡结帐金额,
t3.AAA消费数量,t3.AAA消费金额,t3.BBB消费数量,t3.BBB消费金额,t3.全部产品数,t3.全部消费金额
from --这里的t1.*,t2.*,t3.*要去掉dt，自己把他写全。
(
select dt = convert(varchar(10),日期,120) , 开卡数 = count(*) from card group by convert(varchar(10),日期,120)
) t1
full join
(
select dt = convert(varchar(10),日期,120) , 存款数 = count(*) , 存款金额 = sum(存款金额) from chuqiao group by convert(varchar(10),日期,120)
) t2 on t1.dt = t2.dt
full join
(
select dt = convert(varchar(10),日期,120) , 消费单数 = count(*) , 消费金额 = sum(金额) ,
现金结帐数 = sum(case 结帐方式 when '现金' then 1 else 0 end),
现金结帐金额 = sum(case 结帐方式 when '现金' then 金额 else 0 end),
扣存款结帐数 = sum(case 结帐方式 when '扣存款' then 1 else 0 end),
扣存款结帐金额 = sum(case 结帐方式 when '扣存款' then 金额 else 0 end),
信用卡结帐数 = sum(case 结帐方式 when '信用卡' then 1 else 0 end),
信用卡结帐金额 = sum(case 结帐方式 when '信用卡' then 金额 else 0 end),
AAA消费数量 = sum(case 消费产品 when 'AAA' then 1 else 0 end),
AAA消费金额 = sum(case 结帐方式 when 'AAA' then 金额 else 0 end),
BBB消费数量 = sum(case 消费产品 when 'BBB' then 1 else 0 end),
BBB消费金额 = sum(case 结帐方式 when 'BBB' then 金额 else 0 end),
全部产品数 = sum(数量),
全部消费金额 = sum(金额)
from xf group by convert(varchar(10),日期,120)
) t3 on t2.dt = t3.dt ORDER BY dt
/**
运行结果如下:
2008-02-09 NULL NULL NULL 1 12 NULL 1 12 0 0 0 0 1 0 0 0 1 12
2008-02-09 1 NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL
2008-02-11 1 1 300 1 12 312 1 12 0 0 0 0 0 0 1 0 1 12
2008-02-15 1 2 450 2 42 480 1 30 1 12 0 0 1 0 1 0 2 42
2008-02-16 NULL 1 100 2 34 100 0 0 2 34 0 0 1 0 1 0 4 34
2008-02-18 1 NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL
2008-02-20 NULL 1 450 1 30 480 1 30 0 0 0 0 0 0 0 0 1 30
2008-02-21 NULL 1 100 NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL
2008-02-23 NULL NULL NULL 2 60 NULL 1 30 0 0 1 30 0 0 0 0 4 60
2008-02-25 NULL NULL NULL 1 30 NULL 0 0 1 30 0 0 0 0 0 0 3 30
2008-02-27 2 2 520 5 59 558 3 38 1 11 1 10 2 0 2 0 16 59
**/
想请问的是,为什么2008-02-09会有两行呢?我想将每天的统计放在一行就行了。
是不是isnull(isnull(t1.dt,t2.dt),t3.dt) dt 这里有问题呢？请大大细看。。。。在线等。。。。
CREATE table chuqiao(日期 DATETIME, 卡号 CHAR(10), 存款金额 INT)
CREATE table xf(日期 DATETIME, 卡号 CHAR(10), 消费产品 CHAR(10), 结帐方式 CHAR(10), 数量 INT, 单价 INT, 金额 INT)
INSERT INTO Card VALUES('2008-2-9','392332', 'Wangxiaoyan')
INSERT INTO Card VALUES('2008-2-11','444330', 'Wangmss')
INSERT INTO Card VALUES('2008-2-15','392411', 'Guomoruo')
INSERT INTO Card VALUES('2008-2-18','392833', 'Lidake')
INSERT INTO Card VALUES('2008-2-27','492129', 'Wangyiguang')
INSERT INTO Card VALUES('2008-2-27','623356', 'Dengzhuzhu')
INSERT INTO chuqiao VALUES('2008-2-11','392332', 300)
INSERT INTO chuqiao VALUES('2008-2-15','392332', 300)
INSERT INTO chuqiao VALUES('2008-2-15','392411', 150)
INSERT INTO chuqiao VALUES('2008-2-16','392332', 100)
INSERT INTO chuqiao VALUES('2008-2-20','392411', 450)
INSERT INTO chuqiao VALUES('2008-2-21','392823', 100)
INSERT INTO chuqiao VALUES('2008-2-27','392129', 400)
INSERT INTO chuqiao VALUES('2008-2-27','392332', 120)
INSERT INTO xf VALUES('2008-2-9', '392233', 'AAA','现金', 1,12,12)
INSERT INTO xf VALUES('2008-2-11', '392233', 'BBB','现金', 1,12,12)
INSERT INTO xf VALUES('2008-2-15', '392233', 'AAA','扣存款', 1,12,12)
INSERT INTO xf VALUES('2008-2-15', '------', 'BBB','现金', 1,30,30)
INSERT INTO xf VALUES('2008-2-16', '392411', 'BBB','扣存款', 2,5,10)
INSERT INTO xf VALUES('2008-2-16', '392332', 'AAA','扣存款', 2,12,24)
INSERT INTO xf VALUES('2008-2-20', '------', 'DDD','现金', 1,30,30)
INSERT INTO xf VALUES('2008-2-23', '------', 'DDD','现金', 1,30,30)
INSERT INTO xf VALUES('2008-2-23', '392233', 'CCC','信用卡', 3,10,30)
INSERT INTO xf VALUES('2008-2-25', '392233', 'CCC','扣存款', 3,10,30)
INSERT INTO xf VALUES('2008-2-27', '392233', 'EEE','现金', 9,1,9)
INSERT INTO xf VALUES('2008-2-27', '392233', 'AAA','现金', 1,11,11)
INSERT INTO xf VALUES('2008-2-27', '392233', 'AAA','扣存款', 1,11,11)
INSERT INTO xf VALUES('2008-2-27', '392233', 'BBB','现金', 3,5,18)
INSERT INTO xf VALUES('2008-2-27', '392233', 'BBB','信用卡', 2,5,10)
select isnull(isnull(t1.dt,t2.dt),t3.dt) dt , t1.开卡数 ,t2.存款数 ,t2.存款金额 ,
t3.消费单数,t3.消费金额,(t2.存款金额+t3.现金结帐金额) as 当天全部现金,
t3.现金结帐数,t3.现金结帐金额,t3.扣存款结帐数,t3.扣存款结帐金额,t3.信用卡结帐数,t3.信用卡结帐金额,
t3.AAA消费数量,t3.AAA消费金额,t3.BBB消费数量,t3.BBB消费金额,t3.全部产品数,t3.全部消费金额
from --这里的t1.*,t2.*,t3.*要去掉dt，自己把他写全。
(
select dt = convert(varchar(10),日期,120) , 开卡数 = count(*) from card group by convert(varchar(10),日期,120)
) t1
full join
(
select dt = convert(varchar(10),日期,120) , 存款数 = count(*) , 存款金额 = sum(存款金额) from chuqiao group by convert(varchar(10),日期,120)
) t2 on t1.dt = t2.dt
full join
(
select dt = convert(varchar(10),日期,120) , 消费单数 = count(*) , 消费金额 = sum(金额) ,
现金结帐数 = sum(case 结帐方式 when '现金' then 1 else 0 end),
现金结帐金额 = sum(case 结帐方式 when '现金' then 金额 else 0 end),
扣存款结帐数 = sum(case 结帐方式 when '扣存款' then 1 else 0 end),
扣存款结帐金额 = sum(case 结帐方式 when '扣存款' then 金额 else 0 end),
信用卡结帐数 = sum(case 结帐方式 when '信用卡' then 1 else 0 end),
信用卡结帐金额 = sum(case 结帐方式 when '信用卡' then 金额 else 0 end),
AAA消费数量 = sum(case 消费产品 when 'AAA' then 1 else 0 end),
AAA消费金额 = sum(case 结帐方式 when 'AAA' then 金额 else 0 end),
BBB消费数量 = sum(case 消费产品 when 'BBB' then 1 else 0 end),
BBB消费金额 = sum(case 结帐方式 when 'BBB' then 金额 else 0 end),
全部产品数 = sum(数量),
全部消费金额 = sum(金额)
from xf group by convert(varchar(10),日期,120)
) t3 on t2.dt = t3.dt ORDER BY dt
/**
运行结果如下:
2008-02-09 NULL NULL NULL 1 12 NULL 1 12 0 0 0 0 1 0 0 0 1 12
2008-02-09 1 NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL
2008-02-11 1 1 300 1 12 312 1 12 0 0 0 0 0 0 1 0 1 12
2008-02-15 1 2 450 2 42 480 1 30 1 12 0 0 1 0 1 0 2 42
2008-02-16 NULL 1 100 2 34 100 0 0 2 34 0 0 1 0 1 0 4 34
2008-02-18 1 NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL
2008-02-20 NULL 1 450 1 30 480 1 30 0 0 0 0 0 0 0 0 1 30
2008-02-21 NULL 1 100 NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL
2008-02-23 NULL NULL NULL 2 60 NULL 1 30 0 0 1 30 0 0 0 0 4 60
2008-02-25 NULL NULL NULL 1 30 NULL 0 0 1 30 0 0 0 0 0 0 3 30
2008-02-27 2 2 520 5 59 558 3 38 1 11 1 10 2 0 2 0 16 59
**/
想请问的是,为什么2008-02-09会有两行呢?我想将每天的统计放在一行就行了。
是不是isnull(isnull(t1.dt,t2.dt),t3.dt) dt 这里有问题呢？请大大细看。。。。在线等。。。。
...全文
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bqb 2008-03-27
CREATE table Card(日期 DATETIME, 卡号 CHAR(10), 姓名 CHAR(20))
CREATE table chuqiao(日期 DATETIME, 卡号 CHAR(10), 存款金额 INT)
CREATE table xf(日期 DATETIME, 卡号 CHAR(10), 消费产品 CHAR(10), 结帐方式 CHAR(10), 数量 INT, 单价 INT, 金额 INT)
INSERT INTO Card VALUES('2008-2-9','392332', 'Wangxiaoyan')
INSERT INTO Card VALUES('2008-2-11','444330', 'Wangmss')
INSERT INTO Card VALUES('2008-2-15','392411', 'Guomoruo')
INSERT INTO Card VALUES('2008-2-18','392833', 'Lidake')
INSERT INTO Card VALUES('2008-2-27','492129', 'Wangyiguang')
INSERT INTO Card VALUES('2008-2-27','623356', 'Dengzhuzhu')
INSERT INTO chuqiao VALUES('2008-2-11','392332', 300)
INSERT INTO chuqiao VALUES('2008-2-15','392332', 300)
INSERT INTO chuqiao VALUES('2008-2-15','392411', 150)
INSERT INTO chuqiao VALUES('2008-2-16','392332', 100)
INSERT INTO chuqiao VALUES('2008-2-20','392411', 450)
INSERT INTO chuqiao VALUES('2008-2-21','392823', 100)
INSERT INTO chuqiao VALUES('2008-2-27','392129', 400)
INSERT INTO chuqiao VALUES('2008-2-27','392332', 120)
INSERT INTO xf VALUES('2008-2-9', '392233', 'AAA','现金', 1,12,12)
INSERT INTO xf VALUES('2008-2-11', '392233', 'BBB','现金', 1,12,12)
INSERT INTO xf VALUES('2008-2-15', '392233', 'AAA','扣存款', 1,12,12)
INSERT INTO xf VALUES('2008-2-15', '------', 'BBB','现金', 1,30,30)
INSERT INTO xf VALUES('2008-2-16', '392411', 'BBB','扣存款', 2,5,10)
INSERT INTO xf VALUES('2008-2-16', '392332', 'AAA','扣存款', 2,12,24)
INSERT INTO xf VALUES('2008-2-20', '------', 'DDD','现金', 1,30,30)
INSERT INTO xf VALUES('2008-2-23', '------', 'DDD','现金', 1,30,30)
INSERT INTO xf VALUES('2008-2-23', '392233', 'CCC','信用卡', 3,10,30)
INSERT INTO xf VALUES('2008-2-25', '392233', 'CCC','扣存款', 3,10,30)
INSERT INTO xf VALUES('2008-2-27', '392233', 'EEE','现金', 9,1,9)
INSERT INTO xf VALUES('2008-2-27', '392233', 'AAA','现金', 1,11,11)
INSERT INTO xf VALUES('2008-2-27', '392233', 'AAA','扣存款', 1,11,11)
INSERT INTO xf VALUES('2008-2-27', '392233', 'BBB','现金', 3,5,18)
INSERT INTO xf VALUES('2008-2-27', '392233', 'BBB','信用卡', 2,5,10)
select t0.dt, t1.开卡数 ,t2.存款数 ,t2.存款金额 ,
t3.消费单数,t3.消费金额,(t2.存款金额+t3.现金结帐金额) as 当天全部现金,
t3.现金结帐数,t3.现金结帐金额,t3.扣存款结帐数,t3.扣存款结帐金额,t3.信用卡结帐数,t3.信用卡结帐金额,
t3.AAA消费数量,t3.AAA消费金额,t3.BBB消费数量,t3.BBB消费金额,t3.全部产品数,t3.全部消费金额
from --这里的t1.*,t2.*,t3.*要去掉dt，自己把他写全。
(
select convert(varchar(10),日期,120) dt from card
union
select convert(varchar(10),日期,120) from chuqiao
union
select convert(varchar(10),日期,120) from xf
) t0
left join
(
select dt = convert(varchar(10),日期,120) , 开卡数 = count(*) from card group by convert(varchar(10),日期,120)
) t1 on t0.dt=t1.dt
left join
(
select dt = convert(varchar(10),日期,120) , 存款数 = count(*) , 存款金额 = sum(存款金额) from chuqiao group by convert(varchar(10),日期,120)
) t2 on t0.dt = t2.dt
left join
(
select dt = convert(varchar(10),日期,120) , 消费单数 = count(*) , 消费金额 = sum(金额) ,
现金结帐数 = sum(case 结帐方式 when '现金' then 1 else 0 end),
现金结帐金额 = sum(case 结帐方式 when '现金' then 金额 else 0 end),
扣存款结帐数 = sum(case 结帐方式 when '扣存款' then 1 else 0 end),
扣存款结帐金额 = sum(case 结帐方式 when '扣存款' then 金额 else 0 end),
信用卡结帐数 = sum(case 结帐方式 when '信用卡' then 1 else 0 end),
信用卡结帐金额 = sum(case 结帐方式 when '信用卡' then 金额 else 0 end),
AAA消费数量 = sum(case 消费产品 when 'AAA' then 1 else 0 end),
AAA消费金额 = sum(case 结帐方式 when 'AAA' then 金额 else 0 end),
BBB消费数量 = sum(case 消费产品 when 'BBB' then 1 else 0 end),
BBB消费金额 = sum(case 结帐方式 when 'BBB' then 金额 else 0 end),
全部产品数 = sum(数量),
全部消费金额 = sum(金额)
from xf group by convert(varchar(10),日期,120)
) t3 on t0.dt = t3.dt ORDER BY t0.dt
/*
dt 开卡数 存款数 存款金额 消费单数 消费金额 当天全部现金 现金结帐数 现金结帐金额 扣存款结帐数 扣存款结帐金额 信用卡结帐数 信用卡结帐金额 AAA消费数量 AAA消费金额 BBB消费数量 BBB消费金额 全部产品数 全部消费金额
---------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- -----------
2008-02-09 1 NULL NULL 1 12 NULL 1 12 0 0 0 0 1 0 0 0 1 12
2008-02-11 1 1 300 1 12 312 1 12 0 0 0 0 0 0 1 0 1 12
2008-02-15 1 2 450 2 42 480 1 30 1 12 0 0 1 0 1 0 2 42
2008-02-16 NULL 1 100 2 34 100 0 0 2 34 0 0 1 0 1 0 4 34
2008-02-18 1 NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL
2008-02-20 NULL 1 450 1 30 480 1 30 0 0 0 0 0 0 0 0 1 30
2008-02-21 NULL 1 100 NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL
2008-02-23 NULL NULL NULL 2 60 NULL 1 30 0 0 1 30 0 0 0 0 4 60
2008-02-25 NULL NULL NULL 1 30 NULL 0 0 1 30 0 0 0 0 0 0 3 30
2008-02-27 2 2 520 5 59 558 3 38 1 11 1 10 2 0 2 0 16 59
*/
drop table card,chuqiao,xfrings2000 2008-03-27
高人,,真是高人,,,,
dawugui 2008-03-27
CREATE table Card(日期 DATETIME, 卡号 CHAR(10), 姓名 CHAR(20))
CREATE table chuqiao(日期 DATETIME, 卡号 CHAR(10), 存款金额 INT)
CREATE table xf(日期 DATETIME, 卡号 CHAR(10), 消费产品 CHAR(10), 结帐方式 CHAR(10), 数量 INT, 单价 INT, 金额 INT)
INSERT INTO Card VALUES('2008-2-9','392332', 'Wangxiaoyan')
INSERT INTO Card VALUES('2008-2-11','444330', 'Wangmss')
INSERT INTO Card VALUES('2008-2-15','392411', 'Guomoruo')
INSERT INTO Card VALUES('2008-2-18','392833', 'Lidake')
INSERT INTO Card VALUES('2008-2-27','492129', 'Wangyiguang')
INSERT INTO Card VALUES('2008-2-27','623356', 'Dengzhuzhu')
INSERT INTO chuqiao VALUES('2008-2-11','392332', 300)
INSERT INTO chuqiao VALUES('2008-2-15','392332', 300)
INSERT INTO chuqiao VALUES('2008-2-15','392411', 150)
INSERT INTO chuqiao VALUES('2008-2-16','392332', 100)
INSERT INTO chuqiao VALUES('2008-2-20','392411', 450)
INSERT INTO chuqiao VALUES('2008-2-21','392823', 100)
INSERT INTO chuqiao VALUES('2008-2-27','392129', 400)
INSERT INTO chuqiao VALUES('2008-2-27','392332', 120)
INSERT INTO xf VALUES('2008-2-9', '392233', 'AAA','现金', 1,12,12)
INSERT INTO xf VALUES('2008-2-11', '392233', 'BBB','现金', 1,12,12)
INSERT INTO xf VALUES('2008-2-15', '392233', 'AAA','扣存款', 1,12,12)
INSERT INTO xf VALUES('2008-2-15', '------', 'BBB','现金', 1,30,30)
INSERT INTO xf VALUES('2008-2-16', '392411', 'BBB','扣存款', 2,5,10)
INSERT INTO xf VALUES('2008-2-16', '392332', 'AAA','扣存款', 2,12,24)
INSERT INTO xf VALUES('2008-2-20', '------', 'DDD','现金', 1,30,30)
INSERT INTO xf VALUES('2008-2-23', '------', 'DDD','现金', 1,30,30)
INSERT INTO xf VALUES('2008-2-23', '392233', 'CCC','信用卡', 3,10,30)
INSERT INTO xf VALUES('2008-2-25', '392233', 'CCC','扣存款', 3,10,30)
INSERT INTO xf VALUES('2008-2-27', '392233', 'EEE','现金', 9,1,9)
INSERT INTO xf VALUES('2008-2-27', '392233', 'AAA','现金', 1,11,11)
INSERT INTO xf VALUES('2008-2-27', '392233', 'AAA','扣存款', 1,11,11)
INSERT INTO xf VALUES('2008-2-27', '392233', 'BBB','现金', 3,5,18)
INSERT INTO xf VALUES('2008-2-27', '392233', 'BBB','信用卡', 2,5,10)
select isnull(m.dt , t3.dt) dt , m.开卡数 ,m.存款数 ,m.存款金额,
t3.消费单数,t3.消费金额,(m.存款金额+t3.现金结帐金额) as 当天全部现金,
t3.现金结帐数,t3.现金结帐金额,t3.扣存款结帐数,t3.扣存款结帐金额,t3.信用卡结帐数,t3.信用卡结帐金额,
t3.AAA消费数量,t3.AAA消费金额,t3.BBB消费数量,t3.BBB消费金额,t3.全部产品数,t3.全部消费金额
from
(
select isnull(t1.dt,t2.dt) dt , t1.开卡数 ,t2.存款数 ,t2.存款金额 from
(
select dt = convert(varchar(10),日期,120) , 开卡数 = count(*) from card group by convert(varchar(10),日期,120)
) t1
full join
(
select dt = convert(varchar(10),日期,120) , 存款数 = count(*) , 存款金额 = sum(存款金额) from chuqiao group by convert(varchar(10),日期,120)
) t2 on t1.dt = t2.dt
) m
full join
(
select dt = convert(varchar(10),日期,120) , 消费单数 = count(*) , 消费金额 = sum(金额) ,
现金结帐数 = sum(case 结帐方式 when '现金' then 1 else 0 end),
现金结帐金额 = sum(case 结帐方式 when '现金' then 金额 else 0 end),
扣存款结帐数 = sum(case 结帐方式 when '扣存款' then 1 else 0 end),
扣存款结帐金额 = sum(case 结帐方式 when '扣存款' then 金额 else 0 end),
信用卡结帐数 = sum(case 结帐方式 when '信用卡' then 1 else 0 end),
信用卡结帐金额 = sum(case 结帐方式 when '信用卡' then 金额 else 0 end),
AAA消费数量 = sum(case 消费产品 when 'AAA' then 1 else 0 end),
AAA消费金额 = sum(case 结帐方式 when 'AAA' then 金额 else 0 end),
BBB消费数量 = sum(case 消费产品 when 'BBB' then 1 else 0 end),
BBB消费金额 = sum(case 结帐方式 when 'BBB' then 金额 else 0 end),
全部产品数 = sum(数量),
全部消费金额 = sum(金额)
from xf group by convert(varchar(10),日期,120)
) t3
on m.dt = t3.dt ORDER BY dt
drop table card,chuqiao,xf
/*
dt 开卡数 存款数 存款金额 消费单数 消费金额 当天全部现金 现金结帐数 现金结帐金额 扣存款结帐数 扣存款结帐金额 信用卡结帐数 信用卡结帐金额 AAA消费数量 AAA消费金额 BBB消费数量 BBB消费金额 全部产品数 全部消费金额
---------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- -----------
2008-02-09 1 NULL NULL 1 12 NULL 1 12 0 0 0 0 1 0 0 0 1 12
2008-02-11 1 1 300 1 12 312 1 12 0 0 0 0 0 0 1 0 1 12
2008-02-15 1 2 450 2 42 480 1 30 1 12 0 0 1 0 1 0 2 42
2008-02-16 NULL 1 100 2 34 100 0 0 2 34 0 0 1 0 1 0 4 34
2008-02-18 1 NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL
2008-02-20 NULL 1 450 1 30 480 1 30 0 0 0 0 0 0 0 0 1 30
2008-02-21 NULL 1 100 NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL
2008-02-23 NULL NULL NULL 2 60 NULL 1 30 0 0 1 30 0 0 0 0 4 60
2008-02-25 NULL NULL NULL 1 30 NULL 0 0 1 30 0 0 0 0 0 0 3 30
2008-02-27 2 2 520 5 59 558 3 38 1 11 1 10 2 0 2 0 16 59
（所影响的行数为 10 行）
*/rings2000 2008-03-27
怎么写呀？
dawugui 2008-03-27
那就先两个union all,然后再union all最后一个.
rings2000 2008-03-27
如果将
on t1.dt = t3.dt ORDER BY dt
改为:
on t1.dt = t3.dt and t2.dt = t3.dt ORDER BY dt
的话，2008-02-09，2008-02-16都有两条了....怎么办？
on t1.dt = t3.dt ORDER BY dt
改为:
on t1.dt = t3.dt and t2.dt = t3.dt ORDER BY dt
的话，2008-02-09，2008-02-16都有两条了....怎么办？
rings2000 2008-03-27
已经将
,(t2.存款金额+t3.现金结帐金额) as 当天全部现金
改为:
,(isnull(t2.存款金额,0)+isnull(t3.现金结帐金额,0)) as 当天全部现金
,(t2.存款金额+t3.现金结帐金额) as 当天全部现金
改为:
,(isnull(t2.存款金额,0)+isnull(t3.现金结帐金额,0)) as 当天全部现金
rings2000 2008-03-27
这样的话，2008-02-16又有两条了。。。。怎么办?
dawugui 2008-03-27
--不好意思,把最后的t2.dt = t3.dt 该为 t1.dt = t3.dt.
CREATE table Card(日期 DATETIME, 卡号 CHAR(10), 姓名 CHAR(20))
CREATE table chuqiao(日期 DATETIME, 卡号 CHAR(10), 存款金额 INT)
CREATE table xf(日期 DATETIME, 卡号 CHAR(10), 消费产品 CHAR(10), 结帐方式 CHAR(10), 数量 INT, 单价 INT, 金额 INT)
INSERT INTO Card VALUES('2008-2-9','392332', 'Wangxiaoyan')
INSERT INTO Card VALUES('2008-2-11','444330', 'Wangmss')
INSERT INTO Card VALUES('2008-2-15','392411', 'Guomoruo')
INSERT INTO Card VALUES('2008-2-18','392833', 'Lidake')
INSERT INTO Card VALUES('2008-2-27','492129', 'Wangyiguang')
INSERT INTO Card VALUES('2008-2-27','623356', 'Dengzhuzhu')
INSERT INTO chuqiao VALUES('2008-2-11','392332', 300)
INSERT INTO chuqiao VALUES('2008-2-15','392332', 300)
INSERT INTO chuqiao VALUES('2008-2-15','392411', 150)
INSERT INTO chuqiao VALUES('2008-2-16','392332', 100)
INSERT INTO chuqiao VALUES('2008-2-20','392411', 450)
INSERT INTO chuqiao VALUES('2008-2-21','392823', 100)
INSERT INTO chuqiao VALUES('2008-2-27','392129', 400)
INSERT INTO chuqiao VALUES('2008-2-27','392332', 120)
INSERT INTO xf VALUES('2008-2-9', '392233', 'AAA','现金', 1,12,12)
INSERT INTO xf VALUES('2008-2-11', '392233', 'BBB','现金', 1,12,12)
INSERT INTO xf VALUES('2008-2-15', '392233', 'AAA','扣存款', 1,12,12)
INSERT INTO xf VALUES('2008-2-15', '------', 'BBB','现金', 1,30,30)
INSERT INTO xf VALUES('2008-2-16', '392411', 'BBB','扣存款', 2,5,10)
INSERT INTO xf VALUES('2008-2-16', '392332', 'AAA','扣存款', 2,12,24)
INSERT INTO xf VALUES('2008-2-20', '------', 'DDD','现金', 1,30,30)
INSERT INTO xf VALUES('2008-2-23', '------', 'DDD','现金', 1,30,30)
INSERT INTO xf VALUES('2008-2-23', '392233', 'CCC','信用卡', 3,10,30)
INSERT INTO xf VALUES('2008-2-25', '392233', 'CCC','扣存款', 3,10,30)
INSERT INTO xf VALUES('2008-2-27', '392233', 'EEE','现金', 9,1,9)
INSERT INTO xf VALUES('2008-2-27', '392233', 'AAA','现金', 1,11,11)
INSERT INTO xf VALUES('2008-2-27', '392233', 'AAA','扣存款', 1,11,11)
INSERT INTO xf VALUES('2008-2-27', '392233', 'BBB','现金', 3,5,18)
INSERT INTO xf VALUES('2008-2-27', '392233', 'BBB','信用卡', 2,5,10)
select isnull(isnull(t1.dt,t2.dt),t3.dt) dt , t1.开卡数 ,t2.存款数 ,t2.存款金额 ,
t3.消费单数,t3.消费金额,(t2.存款金额+t3.现金结帐金额) as 当天全部现金,
t3.现金结帐数,t3.现金结帐金额,t3.扣存款结帐数,t3.扣存款结帐金额,t3.信用卡结帐数,t3.信用卡结帐金额,
t3.AAA消费数量,t3.AAA消费金额,t3.BBB消费数量,t3.BBB消费金额,t3.全部产品数,t3.全部消费金额
from --这里的t1.*,t2.*,t3.*要去掉dt，自己把他写全。
(
select dt = convert(varchar(10),日期,120) , 开卡数 = count(*) from card group by convert(varchar(10),日期,120)
) t1
full join
(
select dt = convert(varchar(10),日期,120) , 存款数 = count(*) , 存款金额 = sum(存款金额) from chuqiao group by convert(varchar(10),日期,120)
) t2 on t1.dt = t2.dt
full join
(
select dt = convert(varchar(10),日期,120) , 消费单数 = count(*) , 消费金额 = sum(金额) ,
现金结帐数 = sum(case 结帐方式 when '现金' then 1 else 0 end),
现金结帐金额 = sum(case 结帐方式 when '现金' then 金额 else 0 end),
扣存款结帐数 = sum(case 结帐方式 when '扣存款' then 1 else 0 end),
扣存款结帐金额 = sum(case 结帐方式 when '扣存款' then 金额 else 0 end),
信用卡结帐数 = sum(case 结帐方式 when '信用卡' then 1 else 0 end),
信用卡结帐金额 = sum(case 结帐方式 when '信用卡' then 金额 else 0 end),
AAA消费数量 = sum(case 消费产品 when 'AAA' then 1 else 0 end),
AAA消费金额 = sum(case 结帐方式 when 'AAA' then 金额 else 0 end),
BBB消费数量 = sum(case 消费产品 when 'BBB' then 1 else 0 end),
BBB消费金额 = sum(case 结帐方式 when 'BBB' then 金额 else 0 end),
全部产品数 = sum(数量),
全部消费金额 = sum(金额)
from xf group by convert(varchar(10),日期,120)
) t3 on t1.dt = t3.dt ORDER BY dt
drop table card,chuqiao,xf
/*
dt 开卡数 存款数 存款金额 消费单数 消费金额 当天全部现金 现金结帐数 现金结帐金额 扣存款结帐数 扣存款结帐金额 信用卡结帐数 信用卡结帐金额 AAA消费数量 AAA消费金额 BBB消费数量 BBB消费金额 全部产品数 全部消费金额
---------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- ----------- -----------
2008-02-09 1 NULL NULL 1 12 NULL 1 12 0 0 0 0 1 0 0 0 1 12
2008-02-11 1 1 300 1 12 312 1 12 0 0 0 0 0 0 1 0 1 12
2008-02-15 1 2 450 2 42 480 1 30 1 12 0 0 1 0 1 0 2 42
2008-02-16 NULL 1 100 NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL
2008-02-16 NULL NULL NULL 2 34 NULL 0 0 2 34 0 0 1 0 1 0 4 34
2008-02-18 1 NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL
2008-02-20 NULL 1 450 NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL
2008-02-20 NULL NULL NULL 1 30 NULL 1 30 0 0 0 0 0 0 0 0 1 30
2008-02-21 NULL 1 100 NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL
2008-02-23 NULL NULL NULL 2 60 NULL 1 30 0 0 1 30 0 0 0 0 4 60
2008-02-25 NULL NULL NULL 1 30 NULL 0 0 1 30 0 0 0 0 0 0 3 30
2008-02-27 2 2 520 5 59 558 3 38 1 11 1 10 2 0 2 0 16 59
（所影响的行数为 12 行）
*/基于java的企业人事管理系统设计--软件工程课程设计（含源码与论文设计）.rar 1 引言 4
1.1 课程设计目标 4
1.2 编程工具（编程环境）介绍 4
1.3 实施时间及主要实施步骤 4
2 需求分析 5
3 系统总体设计 6
4 数据库设计 6
5 主要功能模块的设计与实现 10
5.1 功能模块1详细设计（综合查询员工信息）..........................................................10
5.1.1 详细设计.......................................................................................................10
5.1.2 算法流程........................................................................................................15
5.1.3 界面设计及测试结果.....................................................................................15
6 调试分析 15
7 用户手册 16
8 测试结果 17
8.1 员工信息的添加...................................................................................................17
8.2 员工信息的修改...................................................................................................17
8.3 员工信息的删除...................................................................................................18
8.4 员工信息的综合查询...........................................................................................18
8.5 员工信息按性别统计的结果................................................................................19
8.6 员工信息按状态统计的结果...............................................................................19
8.7 员工信息按职称统计的结果................................................................................20
9 结论 20
10 参考文献 20
