怎样提取这种格式的数据并给变量

[飞扬残月]

数据格式：3-2-1
int a,b,c
怎样提取数据使
a=3
b=2
c=1
asp中使用

[文盲老顾]

a = "3-2-1"

b = split(a,"-")

' ---------------------

a = "1,2-3/4_55=66"

b = ExpStr(a,"[\d]+","$$")

Function ExpStr(vStr,vReg,sStr)
	Dim Re,Matchs,Item,tStr
	tStr = ""
	Set Re = New RegExp
	Re.Pattern = vReg
	Re.IgnoreCase = True
	Re.Global = True
	If Re.Test(vStr) Then
		Set Matchs = Re.Execute(vStr)
		For Each Item In Matchs
			tStr = tStr & Item.Value & sStr
		Next
		tStr = Split(Left(tStr,Len(tStr) - Len(sStr)),sStr)
	End If
	Set Re = Nothing
	ExpStr = tStr
End Function

[toury]

VBS:
a=split("3-2-1")(0)
b=split("3-2-1")(1)
c=split("3-2-1")(2)

[ymle1228]

MARK

[ymle1228]

string[] A;

string B = "abcd@@efg@@sdff;";
string C=abcde@efgasdfl@sdlfjs;

如果要分割C很容易，只需如此即可：
A = C.Split('@');
结果：
A[0] = "abcde";
A[1] = "efgasdfl";
A[2] = "sdlfjs";

如果要分割B呢?最简单的办法就是先把@@替换为单字符串了。

A = B.Replace("@@","$").Split('$');

A[0] = "abcd";
A[1] = "efg";
A[2] = "sdff";

[苍白之月]

[Quote=引用 2 楼 toury 的回复:]
VBS:
a=split("3-2-1")(0)
b=split("3-2-1")(1)
c=split("3-2-1")(2)
[/Quote]
正解