高手进来帮忙一下，C++的，其他语言不要

[ironyouth]

/*
7. Write a program that allows the user to enter the last names of five candidates
in a local election and the number of votes received by each candidate.
The program should then output each candidate’s name, the number of votes received,
and the percentage of the total votes received by the candidate.

Use a minimum of 2 functions (in addition to main).
At least one of those functions must pass an array and its size as parameters.

Your program should also output the winner of the election. A sample output is:

Candidate Votes Received % of Total Votes
Johnson 5000 25.91
Miller 4000 20.73
Duffy 6000 31.09
Robinson 2500 12.95
Ashtony 1800 9.33
Total 19300


The Winner of the Election is Duffy.

*/

#include <iostream>
#include <string>
using namespace std;

// must have 2 function using void function and pass by reference &

int main ()
{
string lastName1,lastName2,lastName3,lastName4,lastName5; // last names of five candidates.
int votesL1, votesL2,votedL3,votesL4,votesL5,total; // votes received
double percent1vote,percent2Vote,percent3Vote, percent4Vote, percent5Vote; // % of Total votes

cout << "Please Enter the Five Candidates' Last name" << endl;
cin >> lastName1 //怎么样可以一起把5个名字一起输入进去还是要一个一个来？


return 0;
}

void function ( )
{


return 0;
}

void function ( )
{



return 0;
}

[p0303230]

一个个来
输一个要清一次缓冲区

[mtcat]

你这样的写法要一个一个来了。
你可以写成数组，用一个循环来做。

string lastName[5];
for(int i = 0; i < 5; ++i)
{
cin >> lastName[i];
}

[cx36001390]

cin >> lastName1 >> lastName2 >> lastName3 >> lastName4 >> lastName5;

[珍惜生命远离CPP]

俺不是高手，误入进来

[qmm161]

cin >> lastName1 //怎么样可以一起把5个名字一起输入进去还是要一个一个来？

cin >> lastName1 >> lastName2 >> lastName3 >> ...

[c_spark]

输入数据是一个字符串,一个整数,而且规定了变量名,只有一个一个输入
然后统计输出就行,不知道你的两个function要做什么用?
如果是输入,输出,还得将所有参数的引用传过去,太麻烦点啊
程序挺简单就是对votes求和,记录votes最多的获胜
输出以两位小数的百分比(控制精度)
使用cout<<lastName1<<" "<<setiosflags(ios::fixed)<<setprecision(2)<<percent1vote<<endl;
就行啊,具体实现还是你自己写吧...