问tadom大妈关于缓冲区的问题

[jieao111]

1)
cin.clear();
cin.sync();//一直对sync()不是特别清楚，昨晚查了msdn，一大段英文，迷迷糊糊。。

2)
cin.clear();
cin.ignore( numeric_limits<streamsize>::max(), '\n' );
ignore是读取一个然后忽略到，是从哪读取啊，是从缓冲中吗，为什么下面那个还可以输出i

void main(){
	int i;
cin>>i;   
cin.ignore(); 
cout<<"Please enter a double"<<i;
}  

3)这个里的cin.get()也是从缓冲里读字符的把，读的不是'\n'就continue;

while (!(cin>>i))
            {
                cin.clear();            //重置输入
                while (cin.get() != '\n')
                    continue;            //解除错误的输入
                cout<<"Please enter a double"<<"("<<(i+1)<<")"<<": ";
            }

[baihacker]

和stdin同步

[hityct1]

顶

[taodm]

sync就是清空现有输入。
ignore是忽略输入，试下还没输入的时候是啥反应就知道了。
get、getline当然可以实现忽略输入功能，不过，语意不正确了。另外，VC6对这2个接口实现上有bug。

[jinwei1984]

向taodm学习！

[visame]

首先告诉你：学好英文很重要哦！
istream::sync 	public member function

int sync ( );

Synchronize input buffer with source of characters

Synchronizes the buffer associated with the stream to its controlled input sequence. This effectively means that the unread characters in the buffer are discarded.
这里的sync就是英文单词Synchronize的缩写，意思是“v. 使同时,同时发生”。
就是把输入缓冲区内没有被读取的全部都扔掉，这样才能“同步”。
Example:
// read a file into memory
#include <iostream>
using namespace std;

int main () {
  char first, second;

  cout << "Please, enter a word: ";
  first=cin.get();
  cin.sync();

  cout << "Please, enter another word: ";
  second=cin.get();

  cout << "The first word began by " << first << endl;
  cout << "The second word began by " << second << endl;

  return 0;

[grellen]

mark