很搞的SQL语句，父子关系查询，100分在线等！

[xiajianfeng]

当前存在的表=>
父零件代码 零件代码
A A1
A1 A11
A1 A12
A12 A121
A A2
B B1
B1 B11
B1 B12
B B2


需要得到的结果=>
顶层零件 父零件代码 零件代码 层次
A A A1 1
A A1 A11 2
A A1 A12 2
A A12 A121 3
A A A2 1
B B B1 1
B B1 B11 2
B B1 B12 2
B B B2 1

说明得到的结果：遍历所有顶层的零件，将其下面所有隶属的零件按照父子关系列出来

[孔方发发]

--测试数据
CREATE TABLE tb(ID char(3),PID char(3),Name nvarchar(10))
INSERT tb SELECT '001',NULL ,'山东省'
UNION ALL SELECT '002','001','烟台市'
UNION ALL SELECT '004','002','招远市'
UNION ALL SELECT '003','001','青岛市'
UNION ALL SELECT '005',NULL ,'四会市'
UNION ALL SELECT '006','005','清远市'
UNION ALL SELECT '007','006','小分市'
GO

--查询指定节点及其所有子节点的函数
CREATE FUNCTION f_Cid(@ID char(3))
RETURNS @t_Level TABLE(ID char(3),Level int)
AS
BEGIN
DECLARE @Level int
SET @Level=1
INSERT @t_Level SELECT @ID,@Level
WHILE @@ROWCOUNT>0
BEGIN
SET @Level=@Level+1
INSERT @t_Level SELECT a.ID,@Level
FROM tb a,@t_Level b
WHERE a.PID=b.ID
AND b.Level=@Level-1
END
RETURN
END
GO

--调用函数查询002及其所有子节点
SELECT a.*
FROM tb a,f_Cid('002') b
WHERE a.ID=b.ID
/*--结果
ID PID Name
------ ------- ----------
002 001 烟台市
004 002 招远市
--*/

[liangCK]

--示例数据:
CREATE TABLE BomSub(Parent_item varchar(10),Sub_item varchar(10))
INSERT BomSub SELECT 'A' ,'AA'
UNION ALL SELECT 'A' ,'AB'
UNION ALL SELECT 'AA' ,'AAA'
UNION ALL SELECT 'AA' ,'AAB'
GO

问题描述:
Parent_item是父项，Sub_item是子项，根据根据父子关系排序，并生成每个项目的层次。对于示例数据，要求结果如下：
Parent_item LEVEL
----------- -------
A 0
|-AA 1
|--AAA 2
|--AAB 2
|-AB 1

（所影响的行数为 5 行）

--查询处理的存储过程
CREATE PROC P_QRY
AS
DECLARE @t TABLE(Parent_item varchar(10),Level int,Path varchar(8000))
DECLARE @l int
SET @l=0
INSERT @t SELECT DISTINCT Parent_item,@l,RIGHT(SPACE(20)+Parent_item,20)
FROM BomSub a
WHERE NOT EXISTS(
SELECT * FROM BomSub WHERE Sub_item=a.Parent_item)
WHILE @@ROWCOUNT>0
BEGIN
SET @l=@l+1
INSERT @t SELECT a.Sub_item,@l,b.Path+RIGHT(SPACE(20)+a.Sub_item,20)
FROM BomSub a,@t b
WHERE a.Parent_item=b.Parent_item AND b.Level=@l-1
END
SELECT Parent_item=CASE Level WHEN 0 THEN '' ELSE '|'+REPLICATE('-',Level) END+Parent_item,
Level
FROM @t
ORDER BY Path
GO

--调用
EXEC P_QRY

[-狙击手-]

--生成测试数据
create table BOM(ID INT,PID INT,MSG VARCHAR(1000))
insert into BOM select 1,0,NULL
insert into BOM select 2,1,NULL
insert into BOM select 3,1,NULL
insert into BOM select 4,2,NULL
insert into BOM select 5,3,NULL
insert into BOM select 6,5,NULL
insert into BOM select 7,6,NULL
go

--创建用户定义函数用于取每个父节点下子节点的采购配置信息
create function f_getChild(@ID VARCHAR(10))
returns @t table(ID VARCHAR(10),PID VARCHAR(10),Level INT)
as
begin
    declare @i int
    set @i = 1
    insert into @t select ID,PID,@i from BOM where PID = @ID
    
    while @@rowcount<>0
    begin
        set @i = @i + 1
        
        insert into @t 
        select 
            a.ID,a.PID,@i 
        from 
            BOM a,@t b 
        where 
            a.PID=b.ID and b.Level = @i-1
    end
    return
end
go

--执行查询
select ID from dbo.f_getChild(3)
go

--输出结果
/*
ID
----
5
6
7
*/

--删除测试数据
drop function f_getChild
drop table BOM





创建用户定义函数,每个子节点de父节点的信息


--生成测试数据
create table BOM(ID int,parentID int,sClassName varchar(10))
insert into BOM values(1,0,'1111'      )
insert into BOM values(2,1,'1111_1'    )
insert into BOM values(3,2,'1111-1-1'  )
insert into BOM values(4,3,'1111-1-1-1') 
insert into BOM values(5,1,'1111-2'    )

go

--创建用户定义函数,每个子节点de父节点的信息
create function f_getParent(@ID int)
returns varchar(40)
as
begin
    declare @ret varchar(40)

    while exists(select 1 from BOM where ID=@ID and parentID<>0)
    begin
        select @ID=b.ID,@ret=','+rtrim(b.ID)+isnull(@ret,'')
        from
            BOM a,BOM b
        where
            a.ID=@ID and b.ID=a.parentID
    end
    
    set @ret=stuff(@ret,1,1,'')
    return @ret
end
go

--执行查询
select ID,isnull(dbo.f_getParent(ID),'') as parentID from BOM
go

--输出结果
/*
ID          parentID                                 
----------- ---------------------------------------- 
1           
2           1
3           1,2
4           1,2,3
5           1   
*/

--删除测试数据
drop function f_getParent
drop table BOM
go

[zccmy22]

select left(父零件代码,1) as 顶层零件, 父零件代码 , 零件代码, (len(零件代码）- 1) as 零件代码 from tb

[zccmy22]

select left(父零件代码,1) as 顶层零件, 父零件代码 , 零件代码, (len(零件代码）- 1) as 层次 from tb

是不是有点偷机取巧啊。呵。

[dawugui]

create table tb(pid varchar(10), cid varchar(10))
insert into tb values('A'   ,       'A1') 
insert into tb values('A1'  ,       'A11') 
insert into tb values('A1'  ,       'A12') 
insert into tb values('A12' ,       'A121') 
insert into tb values('A'   ,       'A2') 
insert into tb values('B'   ,       'B1') 
insert into tb values('B1'  ,       'B11') 
insert into tb values('B1'  ,       'B12') 
insert into tb values('B'   ,       'B2') 
go

create function f_pid(@cid varchar(10)) returns int
as
begin
  declare @re_str as varchar(10)
  set @re_str = ''
  declare @level as int
  set @level = 0
  select @re_str = pid from tb where cid = @cid
  while exists (select 1 from tb where cid = @re_str)
    begin
      select @re_str = pid from tb where cid = @re_str
      set @level = @level + 1
    end
  return @level + 1
end
go

select * , dbo.f_pid(cid) 层次 from tb

drop table tb
drop function dbo.f_pid

/*
pid        cid        层次          
---------- ---------- ----------- 
A          A1         1
A1         A11        2
A1         A12        2
A12        A121       3
A          A2         1
B          B1         1
B1         B11        2
B1         B12        2
B          B2         1

（所影响的行数为 9 行）
*/

[utpcb]

看你这个应该直接用 substring之类的 或者 效率应该最高吧 如 zccmy22

select left(父零件代码,1) as 顶层零件, 父零件代码 , 零件代码, (len(零件代码）- 1) as 层次 from tb

是不是有点偷机取巧啊。呵。

[dawugui]

create table tb(pid varchar(10), cid varchar(10))
insert into tb values('A'   ,       'A1') 
insert into tb values('A1'  ,       'A11') 
insert into tb values('A1'  ,       'A12') 
insert into tb values('A12' ,       'A121') 
insert into tb values('A'   ,       'A2') 
insert into tb values('B'   ,       'B1') 
insert into tb values('B1'  ,       'B11') 
insert into tb values('B1'  ,       'B12') 
insert into tb values('B'   ,       'B2') 
go

create function f_pid(@cid varchar(10)) returns varchar(20)
as
begin
  declare @re_str as varchar(10)
  set @re_str = ''
  declare @level as int
  set @level = 0
  select @re_str = pid from tb where cid = @cid
  while exists (select 1 from tb where cid = @re_str)
    begin
      select @re_str = pid from tb where cid = @re_str
      set @level = @level + 1
    end
  return @re_str + ',' + cast(@level + 1 as varchar)
end
go

select 顶层零件 = left(dbo.f_pid(cid),charindex(',',dbo.f_pid(cid))-1) , 
       父零件代码 = pid ,
       零件代码   = cid , 
       substring(dbo.f_pid(cid),charindex(',',dbo.f_pid(cid))+1 , len(dbo.f_pid(cid))) 层次 from tb

drop table tb

drop function dbo.f_pid

/*
顶层零件                 父零件代码      零件代码       层次                   
-------------------- ---------- ---------- -------------------- 
A                    A          A1         1
A                    A1         A11        2
A                    A1         A12        2
A                    A12        A121       3
A                    A          A2         1
B                    B          B1         1
B                    B1         B11        2
B                    B1         B12        2
B                    B          B2         1

（所影响的行数为 9 行）
*/

[flairsky]

create table #tb(pid varchar(10), cid varchar(10))
insert into #tb values('A'   ,       'A1') 
insert into #tb values('A1'  ,       'A11') 
insert into #tb values('A1'  ,       'A12') 
insert into #tb values('A12' ,       'A121') 
insert into #tb values('A'   ,       'A2') 
insert into #tb values('B'   ,       'B1') 
insert into #tb values('B1'  ,       'B11') 
insert into #tb values('B1'  ,       'B12') 
insert into #tb values('B'   ,       'B2') 
go

select substring(pid,1,1) as 顶层零件,pid as 父零件代码,cid as 零件代码,层次=len(pid) from #tb
drop table #tb
/*
A	A	A1	1
A	A1	A11	2
A	A1	A12	2
A	A12	A121	3
A	A	A2	1
B	B	B1	1
B	B1	B11	2
B	B1	B12	2
B	B	B2	1
*/

我就觉得可以这么解决……

[knowledge_Is_Life]

不会,帮顶

[meiZiNick]

什么呀