谁来帮我看看我这个简单的shell代码错在哪里了?

[hepeng19861212]

初学linux编程。谁来帮我看看我这个shell代码错在哪里了?
#!/bin/bash
#用户输入一个分数，程序给出相应的等级
echo "input a score of student:"

read score
if [$socre -gt 100] ;then
echo "the score is invalidate!"
elif [$socre -ge 90]
echo "Excellent!"
elif [$score -ge 80]
echo "Good!"
elif [$score -ge 70]
echo "Medium!"
elif [$score -ge 60]
echo "Passed"
else
echo "Failed"
fi
exit 0
请直接给出你修改后认为正确的代码。

[老腊肉泡酒]

我都是一问就是50分第二天加分的。

[explore_knight]

echo "input a score of student:"
read score
if [ $score -gt 100 ];then
echo "the score is invalidate!"
elif [ $score -ge 90 ];then
echo "Excellent!"
elif [ $score -ge 80 ];then
echo "Good!"
elif [ $score -ge 70 ];then
echo "Medium!"
elif [ $score -ge 60 ];then
echo "Passed"
else
echo "Failed"
fi
exit 0

给我加分啊 ！ 我急需。

[UltraBejing]

有点难度哦

[kuyesuifeng]

[Quote=引用 2 楼 explore_knight 的回复:]
echo "input a score of student:"
read score
if [ $score -gt 100 ];then
echo "the score is invalidate!"
elif [ $score -ge 90 ];then
echo "Excellent!"
elif [ $score -ge 80 ];then
echo "Good!"
elif [ $score -ge 70 ];then
echo "Medium!"
elif [ $score -ge 60 ];then
echo "Passed"
else
echo "Failed"
fi
exit 0

给我加分啊 ！…
[/Quote]

正解，只要在每个elif后加上;then即可

[Chdefender]

#!/bin/bash
#用户输入一个分数，程序给出相应的等级
echo "input a score of student:"
read score
echo
if [ "$socre" -gt 100]
then
echo "the score is invalidate!"
elif ["$socre" -ge 90]
then
echo "Excellent!"
elif ["$score" -ge 80]
then
echo "Good!"
elif [ "$score" -ge 70]
then
echo "Medium!"
elif ["$score" -ge 60]
then
echo "Passed"
else
echo "Failed"
fi
exit 0

[hepeng19861212]

忽忽~~
2楼才是正解
错误1:见4楼
错误二:["$score" -ge 80]是错的,[ "$score" -ge 80 ] 是对的.看到他们什么区别了吧?
忽忽~~