[求助]为什么程序不输出run()方法内容?

[Steve_Samuelson]

同一个包下有如下2个类：
为什么程序的输出没有
m0m1m2m3m4m5m6m7m8m9
m10m11m12m13m14m15m16m17m18m19
m0m1m2m3m4m5m6m7m8m9
m10m11m12m13m14m15m16m17m18m19
而只是输出：
主线程的优先级是3
线程t1的优先级是5
线程t2的优先级是5

public class Machine implements Runnable{
	static StringBuffer log = new StringBuffer();
	public void run() {
		// TODO Auto-generated method stub
		int count =0;
		for(int i=0;i<20;i++){
			log.append("m"+i);
			if(++count%10==0){log.append("\n");}
		}
	}
}

public class Test implements Runnable{
	static StringBuffer log = new StringBuffer();
	public void run() {
		// TODO Auto-generated method stub
		int count =0;
		for(int i=0;i<20;i++){
			log.append(Thread.currentThread().getName()+":m"+i);
			if(++count%10==0){log.append("\n");}
		}
	}
	
	public static void main(String[] args) throws InterruptedException {
		Machine machine1 = new Machine();
		Machine machine2 = new Machine();
		Thread t1 = new Thread(machine1);
		Thread t2 = new Thread(machine2);
		t1.setName("t1");
		t2.setName("t2");
		Thread main = Thread.currentThread();
		main.setPriority(3);
		System.out.println("主线程的优先级是"+main.getPriority());
		System.out.println("线程t1的优先级是"+t1.getPriority());
		System.out.println("线程t2的优先级是"+t2.getPriority());
		t1.setPriority(Thread.MIN_PRIORITY);
		t2.setPriority(Thread.MAX_PRIORITY);
		t1.start();
		t2.start();
		Thread.sleep(500);
		System.out.println(log);
	}
}

[Shine_Panda]

因为你的 log 是 Test 中
static StringBuffer log = new StringBuffer();
的log 所以为空啊。

[wangshikang_it]

学习

[Shine_Panda]

你在 Machine 中
int count =0;
for(int i=0;i<20;i++){
log.append("m"+i);
System.out.println(("m"+i);
if(++count%10==0){log.append("\n");}
}

就会有输出。。

[Steve_Samuelson]

[Quote=引用 1 楼 caoyinghui1986 的回复:]
因为你的 log 是 Test 中
static StringBuffer log = new StringBuffer();
的log 所以为空啊。
[/Quote]
为什么StringBuffer为空？我append了啊？不会保存吗？