访问基类的私有成员－探索更好的方法

[raincross98]

修改程序，我是加了两个函数，想知道有没有更好的修改方法
修改前：
#include <iostream.h>
class base
{
private:
int n1;
protected:
int k1;
public:
base(){n1=0;k1=1;}
void fun1(){cout < <n1 < <k1 < <endl;}
};
class d1:public base
{
private:
int n2;
protected:
int k2;
public:
d1(){n2=10;k1=11;}
void fun2(){cout < <n1 < <k1 < <endl; cout < <n2 < <k2 < <endl;}//
};


class d2:public d1
{
private:
int n3;
protected:
int k3;
public:
d2(){n3=20;k3=21;}
void fun3(){cout < <n1 < <k1 < <endl;cout < <n2 < <k2 < <endl; cout < <n3 < <k3 < <endl;}
};
void main()
{
base baseobj;
d1 d1obj;
d2 d2obj;
baseobj.fun1();
d1obj.fun2();
d2obj.fun3();
}
修改后：
#include <iostream.h>
class base
{
private:
int n1;
protected:
int k1;
public:
base(){n1=0;k1=1;}
int get_n1(){return n1;}
void fun1(){cout < <"class base:" < <endl;
cout < <"n1=" < <n1 < <"," < <"k1=" < <k1 < <endl;}

};


class d1:public base
{
private:
int n2;
protected:
int k2;
public:
d1(){n2=10;k2=11;}
int get_n2(){return n2;}
void fun2(){cout < <"class d1:" < <endl;
cout < <"n1=" < <base::get_n1() < <"," < <"k1=" < <k1 < <endl;
cout < <"n2=" < <n2 < <"," < <"k2=" < <k2 < <endl;}

};


class d2:public d1
{
private:
int n3;
protected:
int k3;
public:
d2(){n3=20;k3=21;}
void fun3(){cout < <"class d2:" < <endl;
cout < <"n1=" < <base::get_n1() < <"," < <"k1=" < <k1 < <endl;
cout < <"n2=" < <d1::get_n2() < <"," < <"k2=" < <k2 < <endl;
cout < <"n3=" < <n3 < <"," < <"k3=" < <k3 < <endl;}
};
void main()
{
base baseobj;
d1 d1obj;
d2 d2obj;
baseobj.fun1();
d1obj.fun2();
d2obj.fun3();
}

[FortunateK]

写一个函数，传入一个base类型，重载输出操作符

[FortunateK]

print (const & base)
{
      cout<< base.print<<endl;
}

然后在每个类里面写print函数；

或者
print (const & base,size_t size)
{
if (size == sizeof(base))
then cout<<"base"
else if....
}

不太肯定是否好用

[raincross98]

找到好方法了，刚开始没想起来，直接在派生类中访问fun函数就可以了！结贴喽！