关于XML文件用XSD验证出错的问题

anyoneking 2008-05-08 02:12:01

其中我的XML文件为:

<?xml version="1.0" encoding="UTF-8"?>

<birthdate>

<month>January</month>

<day>21</day>

<year>1983</year>

<name>aaa</name>

</birthdate>

对应的XSD文件为:

<?xml version="1.0" encoding="UTF-8"?>

<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema">

<xs:element name="birthdate">

<xs:complexType>

<xs:sequence>

<xs:element name="month" type="xs:string" />

<xs:element name="day" type="xs:int" />

<xs:element name="year" type="xs:int" />

<xs:any minOccurs="0"/>

</xs:sequence>

</xs:complexType>

</xs:element>

</xs:schema>

我写的java程序为:

public class XMLParse {

	public static void main(String[] args) 

    throws SAXException, IOException, ParserConfigurationException {

     SchemaFactory factory 

       = SchemaFactory.newInstance("http://www.w3.org/2001/XMLSchema");

      File schemaLocation = new File("D:\\tmp\\test.xsd");

      File xmlFile = new File("D:\\tmp\\test.xml");

      Schema schema = factory.newSchema(schemaLocation);

      Validator validator = schema.newValidator();

      DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance();

      domFactory.setNamespaceAware(true);

      DocumentBuilder builder = domFactory.newDocumentBuilder();

      Document doc = builder.parse(xmlFile);

      DOMSource source = new DOMSource(doc);

      DOMResult result = new DOMResult();

      try {

          validator.validate(source, result);

          Document augmented = (Document) result.getNode();

      }

      catch (SAXException ex) {

          System.out.println(ex.getMessage());

      }  

  }

}

在执行的时候,总是提示:cvc-complex-type.2.4.c：严格输入了匹配通配符，但还是找不到元素“name”的声明。
但是我在XSD中,已经声明了一个<xs:any minOccurs="0"/>的任意类型,支持扩展,但是确总是不正确.
希望个位大虾能给出解决方法.备注:这里由于是工作中的需要,必须使用xs:any任意类型支持.

...全文