一个c++程序题急需解答，有点难理解哦！高手指点！

[xuhuan881207]

（航空订票系统）航空公司购买了一台用于航空订票系统的计算机，要求对新系统编程，对每个航班订座（每班20位）。
程序显示下列菜单选项：Please type 1 for "smoking"和Please type 2 for "no smoking"。如果输入1，则程序指定吸烟舱位（座位1到10）；如果输入2，则程序指定非吸烟舱位（座位11到20）。程序应输出一个登机牌，表示座位号和是否为吸烟舱位。
用一个一维数组表示飞机的座位图。将数组的所有元素初始化为0，表示所有座位都是空的。订每个座位是，将数组相应元素设置为1，表示该座位已订。
程序不能再订已经订过的座位。吸烟舱位已满，应询问可否订非吸烟舱位；同样，非吸烟舱位已满时，应询问可否订吸烟舱位。如果同意，再相应订座，否则输出消息"Next flight leaves in 5 hours"。



<说明：只利用数组与函数的知识编写程序，输出、输入用标准流cout、cin。>

[clhposs]

<说明：只利用数组与函数的知识编写程序，输出、输入用标准流cout、cin。>
这叫C++吗？ 这只能说是C外加C++的IO

[xuhuan881207]

哎，管它是不是C++啊，反正就是希望高手能编出来！

[lily604]

这叫基础的C++
这是在aboslute C++上看的吧

[mengde007]

晕，你太懒了吧！

[kitcaii]

#include <iostream>
using namespace std;
int order(int, int [], int);
void print(int, int);
int main()
{
	const int SIZE = 20;
	int t;
	int n;
	int seat[SIZE] = {0};
	char s='a';
	for(; (s = cin.get()) != 'c'; )  // 按任意键继续，按C键结束查询
	{
	cout << "Please type 1 for \"smoking\" and 2 for \"no smoking\" :_\b";
	cin >> t;
	if(t != 1 && t != 2)
	{
		cout << "your input is incorrect!\n";
		continue;
	}
	n = order(t, seat, SIZE);
	print(n, t);
	for(int i = 0; i < SIZE; i++)
		cout << seat[i];
    cout << endl;
	s = cin.get();
	}
	return 0 ;
}



int order(int tag, int st[], int n)
{
	int num;
	if(tag == 1)
	{
		for(num= 0; num < 10; num++)
		{
			if(st[num] == 0)
			{
				break;
			}
		}
	}
	else
	{
		for(num=10; num < n; num++)
		{
			if(st[num] == 0)
			{
				break;
			} 
		}
	}
	st[num] = 1;
	return num+1;
}

void print(int x, int y)
{
	if(y == 1)
	{
		cout << "Your seat number is " << x << " with \"smoking\" " << endl;
	}
	else
	{
		cout << "Your seat number is " << x << " with \"no smoking\" " << endl;
	}
}

[kitcaii]

#include <iostream>
using namespace std;
int order(int, int [], int);
void print(int, int);
int main()
{
	const int SIZE = 20;
	int t;
	int n;
	int seat[SIZE] = {0};
	char s='a';
	for(; (s = cin.get()) != 'c'; )  // 按任意键继续，按C键结束查询
	{
	cout << "Please type 1 for \"smoking\" and 2 for \"no smoking\" :_\b";
	cin >> t;
	if(t != 1 && t != 2)
	{
		cout << "your input is incorrect!\n";
		continue;
	}
	n = order(t, seat, SIZE);
	print(n, t);
	for(int i = 0; i < SIZE; i++)
		cout << seat[i];
    cout << endl;
	s = cin.get();
	}
	return 0 ;
}



int order(int tag, int st[], int n)
{
	int num;
	if(tag == 1)
	{
		for(num= 0; num < 10; num++)
		{
			if(st[num] == 0)
			{
				break;
			}
		}
	}
	else
	{
		for(num=10; num < n; num++)
		{
			if(st[num] == 0)
			{
				break;
			} 
		}
	}
	st[num] = 1;
	return num+1;
}

void print(int x, int y)
{
	if(y == 1)
	{
		cout << "Your seat number is " << x << " with \"smoking\" " << endl;
	}
	else
	{
		cout << "Your seat number is " << x << " with \"no smoking\" " << endl;
	}
}

[kitcaii]

#include <iostream>
using namespace std;
int order(int, int [], int);
void print(int, int);
int main()
{
	const int SIZE = 20;
	int t;
	int n;
	int seat[SIZE] = {0};
	char s='a';
	for(; (s = cin.get()) != 'c'; )  // 按任意键继续，按C键结束查询
	{
	cout << "Please type 1 for \"smoking\" and 2 for \"no smoking\" :_\b";
	cin >> t;
	if(t != 1 && t != 2)
	{
		cout << "your input is incorrect!\n";
		continue;
	}
	n = order(t, seat, SIZE);
	print(n, t);
	for(int i = 0; i < SIZE; i++)
		cout << seat[i];
    cout << endl;
	s = cin.get();
	}
	return 0 ;
}



int order(int tag, int st[], int n)
{
	int num;
	if(tag == 1)
	{
		for(num= 0; num < 10; num++)
		{
			if(st[num] == 0)
			{
				break;
			}
		}
	}
	else
	{
		for(num=10; num < n; num++)
		{
			if(st[num] == 0)
			{
				break;
			} 
		}
	}
	st[num] = 1;
	return num+1;
}

void print(int x, int y)
{
	if(y == 1)
	{
		cout << "Your seat number is " << x << " with \"smoking\" " << endl;
	}
	else
	{
		cout << "Your seat number is " << x << " with \"no smoking\" " << endl;
	}
}

[xuhuan881207]

我是初学者啊，还请高手赐教呀！