为什么总提示Cannot find bean: "UserForm" in any scope

[bingxuecai]

配置文件中是这样的：
<form-bean name="UserForm" type="com.liukai.struts.form.UserForm" />
<action
name="UserForm"
path="/test"
type="com.liukai.struts.action.TestAction">
<forward name="success" path="MyTest.jsp" />
</action>

Action代码是：

public class TestAction extends Action {

	public ActionForward execute(ActionMapping mapping, ActionForm form,
			HttpServletRequest request, HttpServletResponse response) throws InstantiationException, IllegalAccessException, SQLException {
		ActionErrors errors=new ActionErrors();
		HttpSession session=request.getSession();
		//LoginForm Loginuser=(LoginForm)session.getAttribute("Loginuser");
		//String username=Loginuser.getUsername();
		String username="liukai";
		UserForm user=new UserForm();
		ArrayList users = new ArrayList();
		DB db = new DB();
		String sql="select user_password,user_truename,user_useable,user_branch from "+Content.TB_USER+" where "+Content.USERNAME+"='"+username+"'";
		ResultSet rs=(ResultSet) db.getRs(sql);
		while(rs.next()){
			user.setUsertruename(rs.getString("user_truename"));
			user.setUserable(rs.getInt("user_useable"));
			user.setUserbranch(rs.getString("user_branch"));
		}
		users.add(user);
		request.setAttribute("users",users);
		return mapping.findForward("success");
	}
}

jsp中代码是

<logic:iterate id="users" name="UserForm">
    		<tr>
    			<td><bean:write name="user" property="usertruename"/></td>
    			<td><bean:write name="user" property="userable"/></td>
    			<td><bean:write name="user" property="userbranch"/></td>
    		</tr>
    	</logic:iterate>

为什么提示：Cannot find bean: "UserForm" in any scope
我建立了UserForm这个bean啊 而且大小写没有问题！！
请指点 ！！！！！！！！

[dd121011]

配置文件的问题。。。。request.setAttribute("UserForm",users);

[dd121011]

提交的时候提到action里去的 action = "Action"

[bingxuecai]

我在jsp页面中 加了一段
<html:form action="test">
..../之前jsp代码
</html:form >
现在的问题是：
Cannot create iterator for this collection
org.apache.jasper.runtime.PageContextImpl.doHandlePageException( pageContextImpl.java:850)
org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:779)
org.apache.jsp.MyJsp001_jsp._jspService(MyJsp001_jsp.java:197)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:393)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)

这是什么原因呢？
3q！！！

[bingxuecai]

siyue_qi ,zhuyl_wind ,天天happy
我按你们说的改了，现在还是提示相同的错误啊！！！！！！！

[bingxuecai]

求解啊 ！！！

[siyue_qi]

缕缕思路先，楼主。

Action中：

ArrayList users = new ArrayList();
DB db = new DB();
String sql="select user_password,user_truename,user_useable,user_branch from "+Content.TB_USER+" where "+Content.USERNAME+"='"+username+"'";
ResultSet rs=(ResultSet) db.getRs(sql);
while(rs.next()){
user.setUsertruename(rs.getString("user_truename"));
user.setUserable(rs.getInt("user_useable"));
user.setUserbranch(rs.getString("user_branch"));
}
users.add(user);
request.setAttribute("users",users);

那么jsp中：

<logic:iterate id="user" name="users">
<tr>
<td><bean:write name="user" property="usertruename"/></td>
<td><bean:write name="user" property="userable"/></td>
<td><bean:write name="user" property="userbranch"/></td>
</tr>
</logic:iterate>

[KingRat525]

UserForm user=new UserForm();
这个地方，我感觉应该用成UserForm user=(UserForm)form;而不是new一个UserForm对象，而是将请求中的
form转换成UserForm

[bingxuecai]

我已经按以上各位所说的该了
为什么还是提示相同的错误呢！！！！！！！！！！！！！！！

[bingxuecai]

各位指点一下！！
我现在真搞不懂问题在哪了？

[bingxuecai]

唉，烦恼啊

[xiaozhang0731]

你怎么这么笨啊！这么多人都说了你还不清楚吗？
我帮你再说一下
是你在action 里写的
这个request.setAttribute("users",users);东东
和jsp里的这个东东
<logic:iterate id="users" name="UserForm">
牛头不对马尾啊！
你给了张三钱却让李四去干活
你说行吗
应该这样在jsp里这样写
<logic:iterate id="user" name="users">

<tr>
<td> <bean:write name="user" property="usertruename"/> </td>
<td> <bean:write name="user" property="userable"/> </td>
<td> <bean:write name="user" property="userbranch"/> </td>
</tr>
</logic:iterate>

[siyue_qi]

public class TestAction extends Action {

    public ActionForward execute(ActionMapping mapping, ActionForm form,
            HttpServletRequest request, HttpServletResponse response) throws InstantiationException, IllegalAccessException, SQLException {
        ActionErrors errors=new ActionErrors();
        HttpSession session=request.getSession();
        //LoginForm Loginuser=(LoginForm)session.getAttribute("Loginuser");
        //String username=Loginuser.getUsername();
        String username="liukai";
        UserForm user=new UserForm();
        ArrayList users = new ArrayList();
        DB db = new DB();
        String sql="select user_password,user_truename,user_useable,user_branch from "+Content.TB_USER+" where "+Content.USERNAME+"='"+username+"'";
        ResultSet rs=(ResultSet) db.getRs(sql);
        while(rs.next()){
            UserForm user=new UserForm();
            user.setUsertruename(rs.getString("user_truename"));
            user.setUserable(rs.getInt("user_useable"));
            user.setUserbranch(rs.getString("user_branch"));
            users.add(user);
        }
        users.add(user);
        request.setAttribute("users",users);
        return mapping.findForward("success");
    }
}

<logic:iterate id="user" name="users">
            <tr>
                <td><bean:write name="user" property="usertruename"/></td>
                <td><bean:write name="user" property="userable"/></td>
                <td><bean:write name="user" property="userbranch"/></td>
            </tr>
</logic:iterate>

[siyue_qi]

public class TestAction extends Action {

public ActionForward execute(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response) throws InstantiationException, IllegalAccessException, SQLException {
ActionErrors errors=new ActionErrors();
HttpSession session=request.getSession();
//LoginForm Loginuser=(LoginForm)session.getAttribute("Loginuser");
//String username=Loginuser.getUsername();
String username="liukai";
UserForm user=new UserForm();
ArrayList users = new ArrayList();
DB db = new DB();
String sql="select user_password,user_truename,user_useable,user_branch from "+Content.TB_USER+" where "+Content.USERNAME+"='"+username+"'";
ResultSet rs=(ResultSet) db.getRs(sql);
while(rs.next()){
UserForm user=new UserForm();
user.setUsertruename(rs.getString("user_truename"));
user.setUserable(rs.getInt("user_useable"));
user.setUserbranch(rs.getString("user_branch"));
users.add(user);
}
users.add(user);
request.setAttribute("users",users);
return mapping.findForward("success");
}
}

[siyue_qi]

<logic:iterate id="user" name="users">
<tr>
<td><bean:write name="user" property="usertruename"/></td>
<td><bean:write name="user" property="userable"/></td>
<td><bean:write name="user" property="userbranch"/></td>
</tr>
</logic:iterate>

[bingxuecai]

我按照以上各位指出的错误都改正过来了
最后还是提示原来的错误

后来我用EL表达式改写了输出语句

   <c:forEach items="aa" var="user">
  		<tr>
    		<td>${user.usertruename}</td>
    		<td>${user.userable}</td>
    		<td>${user.userbranch}</td>
    		<td>${user.useremail}</td>
  		</tr>
	</c:forEach>

就没有出现问题了
我tomcat用的是6.0是不是服务器的问题呢？

[lifanfly]

UserForm user=new UserForm();
修改为
UserForm user = (UserForm)form;

[zhangronghua309]

你的forward标签中的path属性写错了，必须以“/”开头，不然你这样肯定就找到错误的页面，当然也就不会找到这个form啦

[zhangronghua309]

如果你要转入的页面是就在WEB-INF下那么就直接在你的转入页面名字之前加上“/”，如果是转入WEB-INF下的test文件夹下的MyTest.jsp页面的话，那么在path这个参数就设置为"/test/MyTest.jsp".这样就可以了

[zhangronghua309]

还有就是你的form-bean应该配置在form-beans里面，action应该配置在action-mappings里面吧

[简单才是美]

楼主给你一个建议，要么把分给几个重点的回答，要么最后给出正确的解决方法，这样让后来有同样错误的人看得好纠结啊