ajax 中类型不匹配

gpdfk 2008-05-27 06:33:21

var req;
function creatxmlhttprequest()
{
if(window.ActiveXObject)
{
req=new ActiveXObject('Microsoft.XMLHTTP');

}else if(window.XMLHttpRequest)
{

req=new XMLHttpRequest;

}

}
function createQueryString()
{
var firstname=document.getElementById("firstname").value;
var secondname=document.getElementById("secondname").value;

var queryString ="firstname="+firstname+"secondname="+secondname;

return queryString;

}
function postrequest()
{

creatxmlhttprequest();

var url="Server";
var queryString=createQueryString();

alert(queryString);

req.open("post",url,true); /////////////此行报类型不匹配，为什么？？？？
req.onreadystatechange=callback();

req.send(null);

}

function callback()
{
if(req.readyState==4)
{
if(req.status==200)
{

parseResults();

}

}

}

function parseResults()
{

var responseDiv=document.getElementById("serverResponse");
if(responseDiv.hasChildNodes())
{

responseDiv.removeChild(responseDiv.childNodes[0]);

}

var responseText=req.responseText;

document.createTextNode(responseText);

alert(responseText);

responseDiv.appendChild(responseText);

}

</script>

<body>
<h1>Enter your first name and so on</h1>
<table>
<tr>
<td>First Name: </td>
<td><input type=text id="firstname"> </td>

</tr>
<tr>
<td>Second Name: </td>
<td><input type=text id=secondname> </td>

</tr>

</table>
<input type=button value="send using get" onclick="getrequest();"><br>

<input type=button value="send using post" onclick="postrequest();"><br>

<h2>Server Response:</h2>
<div id=serverResponse></div>

</body>

...全文

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Bj_junxia 2011-07-18

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req.open("get",url,false);

zhanlaohu 2008-05-28

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req.send(null)--->req.send(queryString)

gpdfk 2008-05-28

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多谢

gpdfk 2008-05-28

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function postrequest()
{

creatxmlhttprequest();

var firstname=document.getElementById("firstname").value;
var url='Server?firstname='+firstname;

alert(firstname);

alert(url);

req.open('post',url,true);
req.onreadystatechange=callback;

req.send(null);

}
我该成这样没错。但是没显示结果

Go 旅城通票 2008-05-28

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req.open("post",url,true);    

//req.onreadystatechange=callback(); //========是这里报错

//======>

req.onreadystatechange=callback;

而且你querystring是不是创建错了??

function createQueryString()
{
var firstname=document.getElementById("firstname").value;
var secondname=document.getElementById("secondname").value;

var queryString ="firstname="+firstname+"&secondname="+secondname;

return queryString;

}

也没有发送数据...同1楼