Ajax错误...

fonvey 2008-06-01 02:20:14

<%@LANGUAGE="VBSCRIPT" CODEPAGE="936"%>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html xmlns="http://www.w3.org/1999/xhtml">

<head>

<meta http-equiv="Content-Type" content="text/html; charset=gb2312" />

<title>无标题文档</title>

</head>

<script language="javascript">

var http_request	= false;



function ajax_v2_postdata(url) {



	//REFORMAT QUERYDATA TO AVOID ERRORS IN POST FORMATTING

	//querydata	= querydata.replace(/ /g, "+");

	//querydata	= querydata.replace(/&/g, "%3C");

	

   http_request = false;

   if (window.XMLHttpRequest) { // Mozilla, Safari,...

      http_request = new XMLHttpRequest();

      if (http_request.overrideMimeType) {

         http_request.overrideMimeType('text/html');

      }

   } else if (window.ActiveXObject) { // IE

      try {

         http_request = new ActiveXObject("Msxml2.XMLHTTP");

      } catch (e) {

         try {

            http_request = new ActiveXObject("Microsoft.XMLHTTP");

         } catch (e) {}

      }

   }

   if (!http_request) {

      alert('Cannot create XMLHTTP instance');

      return false;

   }

//var my="goo";

	http_request.onreadystatechange =ajax_processReply("goo");//提示出错

	http_request.open('POST', url, true);

	http_request.setRequestHeader("Content-type", "application/x-www-form-urlencoded");

	//http_request.setRequestHeader("Content-length", querydata.length);

	http_request.setRequestHeader("Connection", "close");

	http_request.send(null);



}



function ajax_processReply(myspace) {

//var myspace="goo";

	if (http_request.readyState == 4) {

		if (http_request.status == 200) {

			result = http_request.responseText;

			document.getElementById(myspace).innerHTML = result;

		} else {

			alert('There was a problem with the request.');

		}

	}

}



</script>

<body>



<table width="407" height="82" border="1">

  <tr>

    <td width="35">用户</td>

    <td width="168">

      <input type="text" name="username" onblur="ajax_v2_postdata('goog.asp?username=good')" />

   

    </td>

    <td width="182"><input type="text" name="goog" /></td>

  </tr>

  <tr>

    <td> </td>

    <td><div id="goo"></div></td>

    <td><div id="gooh"></div></td>

	

  </tr>

</table><div id="myspace"></div>

</body>

</html>

请高手看看,,不知为什么这行提示出错:
http_request.onreadystatechange =ajax_processReply("goo");//提示出错

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孟子E章 2008-06-02

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语法就是这样的，





<script language="javascript">

var http_request    = false;

function ajax_v2_postdata(url) {



    //REFORMAT QUERYDATA TO AVOID ERRORS IN POST FORMATTING

    //querydata    = querydata.replace(/ /g, "+");

    //querydata    = querydata.replace(/&/g, "%3C");

    

   http_request = false;

   if (window.XMLHttpRequest) { // Mozilla, Safari,...

      http_request = new XMLHttpRequest();

      if (http_request.overrideMimeType) {

         http_request.overrideMimeType('text/html');

      }

   } else if (window.ActiveXObject) { // IE

      try {

         http_request = new ActiveXObject("Msxml2.XMLHTTP");

      } catch (e) {

         try {

            http_request = new ActiveXObject("Microsoft.XMLHTTP");

         } catch (e) {}

      }

   }

   if (!http_request) {

      alert('Cannot create XMLHTTP instance');

      return false;

   }

var my="goo";

    querydata = "xx"

    http_request.open('POST', url, true);

    http_request.onreadystatechange = function(){ ajax_processReply(http_request,my) }

    http_request.setRequestHeader("Content-type", "application/x-www-form-urlencoded");

    http_request.setRequestHeader("Content-length", querydata.length);

    http_request.setRequestHeader("Connection", "close");

    http_request.send(null);



}



function ajax_processReply(req,myspace) {  

    if (req.readyState == 4) {

        if (req.status == 200) {

            result = req.responseText;

            document.getElementById(myspace).innerHTML = result;

        } else {

            alert('There was a problem with the request.');

        }

    }

}



</script>

CodingApplication 2008-06-02

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试试：

function ajax_processReply(myspace) {
return function () {
//var myspace="goo";
if (http_request.readyState == 4) {
if (http_request.status == 200) {
result = http_request.responseText;
document.getElementById(myspace).innerHTML = result;
} else {
alert('There was a problem with the request.');
}
}
}
}

fonvey 2008-06-01

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因为我想写一个可以带参数,,然后把这个ajax封装成一个js的类

fonvey 2008-06-01

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我知道这样是可以的
http_request.onreadystatechange = ajax_processReply

但是为什么不可以带参数的啊

孟子E章 2008-06-01

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<%@LANGUAGE="VBSCRIPT"%>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html xmlns="http://www.w3.org/1999/xhtml">

<head>

<meta http-equiv="Content-Type" content="text/html; charset=gb2312" />

<title>无标题文档</title>

</head>

<script language="javascript">

var http_request    = false;



function ajax_v2_postdata(url) {



    //REFORMAT QUERYDATA TO AVOID ERRORS IN POST FORMATTING

    //querydata    = querydata.replace(/ /g, "+");

    //querydata    = querydata.replace(/&/g, "%3C");

    

   http_request = false;

   if (window.XMLHttpRequest) { // Mozilla, Safari,...

      http_request = new XMLHttpRequest();

      if (http_request.overrideMimeType) {

         http_request.overrideMimeType('text/html');

      }

   } else if (window.ActiveXObject) { // IE

      try {

         http_request = new ActiveXObject("Msxml2.XMLHTTP");

      } catch (e) {

         try {

            http_request = new ActiveXObject("Microsoft.XMLHTTP");

         } catch (e) {}

      }

   }

   if (!http_request) {

      alert('Cannot create XMLHTTP instance');

      return false;

   }

//var my="goo";

    querydata = "xx"

    http_request.open('POST', url, true);

    http_request.onreadystatechange = ajax_processReply

    http_request.setRequestHeader("Content-type", "application/x-www-form-urlencoded");

    http_request.setRequestHeader("Content-length", querydata.length);

    http_request.setRequestHeader("Connection", "close");

    http_request.send(null);



}



function ajax_processReply(myspace) {

   var myspace="goo";

    if (http_request.readyState == 4) {

        if (http_request.status == 200) {

            result = http_request.responseText;

            document.getElementById(myspace).innerHTML = result;

        } else {

            alert('There was a problem with the request.');

        }

    }

}



</script>

<body>



<table width="407" height="82" border="1">

  <tr>

    <td width="35">用户</td>

    <td width="168">

      <input type="text" name="username" onblur="ajax_v2_postdata('goog.asp?username=good')" />

   

    </td>

    <td width="182"><input type="text" name="goog" /></td>

  </tr>

  <tr>

    <td> </td>

    <td><div id="goo"></div></td>

    <td><div id="gooh"></div></td>

    

  </tr>

</table><div id="myspace"></div>

</body>

</html>