求一个去掉标签内字符串的首尾空格的正则表达式.

[lengue]

public class ReplaceStr {

	/**
	 * @param args
	 */
	public static void main(String[] args) {
		String xmlIn = "<?xml version='1.0' encoding='UTF-8'?><info>"
                             + "<cond><c1> 004</c1><c2>002 </c2></cond></info>";
		String pattern = "<(.*?)>(^\\s*)|(\\s*$)<\\/\\1>";
		Pattern p = Pattern.compile(pattern);
		Matcher m = p.matcher(xmlIn);
		/*
		 * 通过正则表达式,把"<cond><c1> 004</c1><c2>002 </c2></cond></info>"这样的XML串替换成"<cond><c1>004</c1><c2>002</c2></cond></info>";
		 */
		xmlIn = m.replaceAll("<$1></$1>");
		System.out.println("**"+xmlIn+"**");
	}

}

但我这个代码不行.请指教.

[lawrendc]

	var str="<cond><c1> 004</c1><c2>002 </c2></cond></info>";
	var reg=/(<[^>]*>)(?:\s*)(.*)(<[^>]*>)/g;		
	alert(str.replace(reg,"$1$2$3"));

[lawrendc]

不好意思 刚没测试

	var str="<cond><c1>       004</c1><c2>002    </c2></cond></info>";
	var reg=/(>)(\s*)(.*?)(\s)*(<)/g;		
	alert(str.replace(reg,"$1$3$5"));

[lengue]

太强大了....