如何获取文件完整路径

kangnasi 2008-07-13 10:02:03

用OpenFileDialog openFileDialog1 = new OpenFileDialog()...打开文件后，如何获取当前文件的完整路径？？

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baihe_591 2008-07-14

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FileName

bbbbbb888888 2008-07-14

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Nod

痒痒挠儿 2008-07-14

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m_OpenFileDialog.FileName

suyiming 2008-07-14

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[Quote=引用 3 楼 xrascal 的回复:]
OpenFileDialog m_OpenFileDialog = new OpenFileDialog();
m_OpenFileDialog.Title = "打开文件";
m_OpenFileDialog.Filter = "所有文件 (*.*) ¦*.*";
m_OpenFileDialog.FilterIndex = 1;
m_OpenFileDialog.RestoreDirectory = true;
m_OpenFileDialog.Multiselect = false;

if( DialogResult.OK == m_OpenFileDialog.ShowDialog() )
{
tbFilePath.Text = m_OpenFileDialog.FileName…
[/Quote]

fengf840621 2008-07-14

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string fullname = openFileDialog1.FileName;
string path = System.IO.Path.GetDirectoryName( fullname );

JamesZou89 2008-07-14

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用 System.IO.Path类的
GetDirectoryName()方法就可以做到获取文件路径

贫僧又回来了 2008-07-14

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[Quote=引用 1 楼 zhlu880516 的回复:]
openFileDialog1.FileName;
[/Quote]

JustLovePro 2008-07-14

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[Quote=引用 1 楼 zhlu880516 的回复:]
openFileDialog1.FileName;
[/Quote]

暗石绿 2008-07-14

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OpenFileDialog m_OpenFileDialog = new OpenFileDialog();
m_OpenFileDialog.Title = "打开文件";
m_OpenFileDialog.Filter = "所有文件 (*.*)|*.*";
m_OpenFileDialog.FilterIndex = 1;
m_OpenFileDialog.RestoreDirectory = true;
m_OpenFileDialog.Multiselect = false;

if( DialogResult.OK == m_OpenFileDialog.ShowDialog() )
{
tbFilePath.Text = m_OpenFileDialog.FileName;
}