map的用法

[sunmoonfly]

我想实现一个一对多的map关系
也就是一个用户名对应多条信息
typedef std::list<std::string> StringList;
map<string,StringList>map_roster;
map<string,StringList>::iterator iter;

map_roster["mingfei"].push_back("1Message");
map_roster["mingfei"].push_back("Message");

map_roster["ydp"].push_back("1Message");
map_roster["ydp"].push_back("2Message");
map_roster["ydp"].push_back("3Message");

iter=map_roster.find("ydp");

如何进行遍历

[rocker9527]

再用list的方法来遍历

[sunmoonfly]

自己解决了


typedef std::list<std::string> StringList;
map<string,StringList>map_roster;
map<string,StringList>::iterator iter;

StringList slMing;

slMing.push_back("mingfei1ÌõÏûÏ¢");
slMing.push_back("mingfei2ÌõÏûÏ¢");
map_roster["mingfei"]=slMing;

slMing.erase(slMing.begin(),slMing.end());

slMing.push_back("1ÌõÏûÏ¢");
slMing.push_back("2ÌõÏûÏ¢");
slMing.push_back("3ÌõÏûÏ¢");

map_roster["ydp"]=slMing;

iter=map_roster.find("mingfei");
// for (;iter!=map_roster.end(); iter++)
// {
cout<<iter->first<<endl;
StringList::const_iterator g = (*iter).second.begin();
for (;g!=(*iter).second.end();g++)
{
cout<<(*g).c_str()<<endl;
}