如何修改这句语句？

[chybaby]

public class m
{
private string a1;
private string a2;
private string a3;

public string A1
{
get {return a1;}
set {a1 = value;}
}

public string A2
{
get {return a2;}
set {a2 = value;}
}

public string A3
{
get {return a3;}
set {a3 = value;}
}
}

/*===============================*/
C＃中如何修改成下面的方式：
for (int i = 0; i < 2; i++)
{
s = s + m.A(i); //这里怎么修改。。
}

[zzyhuian06142]

只能用反射了

[coldwinter_stone]

参见我的Blog.
http://blog.csdn.net/coldwinter_stone/archive/2008/07/10/2632873.aspx

[gomoku]

另外一种考虑方式：

public class m
{
private string[] a = new string[3];

public string this[int i]
{
get {return a[i];}
set {a[i] = value;}
}
}

for (int i = 0; i < 2; i++)
{
s = s + m[i];
}

[GhostAdai]

[Quote=引用 4 楼 gomoku 的回复:]
另外一种考虑方式：

public class m
{
private string[] a = new string[3];

public string this[int i]
{
get {return a[i];}
set {a[i] = value;}
}
}

for (int i = 0; i < 2; i++)
{
s = s + m[i];
}
[/Quote]

用索引也不错，要不就反射。

[心晴Sunheart]

已经给解答了
帮顶一下

[chaye12]

4楼的正解！

[shadowgreen]

JF
顶起···

[JeffChung]

[Quote=引用 4 楼 gomoku 的回复:]
另外一种考虑方式：

public class m
{
private string[] a = new string[3];

public string this[int i]
{
get {return a[i];}
set {a[i] = value;}
}
}

for (int i = 0; i < 2; i++)
{
s = s + m[i];
}
[/Quote]