请教正则表达式的写法

[zyb_8022]

2008-08-19 10:40:36| 5 7_199258 -- 200->1219113635970-1219113636234=264
要结果为：
group(1)=2008-08-19
group(2)=10:40:36
group(3)=5
group(4)=7_199258
group(5)=200
group(6)=264
应该怎么写呢？日期不必严格要求
写到这里(\d{4}\-\d{2}\-\d{2})\s(\d{2}:\d{2}:\d{2})|\s(\d)实在写不下去了，请高手指导

还有这个
2008-08-18 16:56:09| 5 X123 1_301 -- 第一次调用：5 X123 1_301->1219049769696-1219049769916=220 beans.service.out
结果为
group(1)=2008-08-18
group(2)=16:56:09
group(3)=5
group(4)=X123
group(5)=1_301
group(6)=第一次调用：5
group(7)=220

[HW_zxc_003]

up

[zhuyx808]

正则表达式

[xq_zhang]

(\d{4}\-\d{2}\-\d{2})\s(\d{2}:\d{2}:\d{2}) ¦\s(\d)\s(.+)\s(.+)--\s(.+\d)\s.+\s.+\->\d+\-\d+\=(\d+)

[xq_zhang]

2008-08-19 10:40:36 ¦ 5 7_199258 -- 200->1219113635970-1219113636234=264
(\d{4}\-\d{2}\-\d{2})\s(\d{2}:\d{2}:\d{2}) ¦\s(\d)\s(.+)\s--\s(\d+)->\d+-\d+=(\d+)

2008-08-18 16:56:09 ¦ 5 X123 1_301 -- 第一次调用：5 X123 1_301->1219049769696-1219049769916=220 beans.service.out
(\d{4}\-\d{2}\-\d{2})\s(\d{2}:\d{2}:\d{2}) ¦\s(\d)\s(.+)\s(.+)--\s(.+\d)\s.+\s.+\->\d+\-\d+\=(\d+)

[Landor2004]

非要用写正则嘛，用split更简单！！

String regex = "2008-08-19 10:40:36 | 5 7_199258 -- 200->1219113635970-1219113636234=264";
		String arr[] = regex.split(" |->|=");
		for(int i=0;i<arr.length;i++){
			System.out.println(arr[i]);
		}

如果格式固定的话，那么可以直接取出
arr[0] = 2008-08-19
arr[1] = 10:40:36
arr[3] = 5
arr[4] = 7_199258
arr[6] = 200
arr[8] = 264

[zyb_8022]

[Quote=引用 4 楼 xq_zhang 的回复:]
2008-08-19 10:40:36 ¦ 5 7_199258 -- 200->1219113635970-1219113636234=264
(\d{4}\-\d{2}\-\d{2})\s(\d{2}:\d{2}:\d{2}) ¦\s(\d)\s(.+)\s--\s(\d+)->\d+-\d+=(\d+)

2008-08-18 16:56:09 ¦ 5 X123 1_301 -- 第一次调用：5 X123 1_301->1219049769696-1219049769916=220 beans.service.out
(\d{4}\-\d{2}\-\d{2})\s(\d{2}:\d{2}:\d{2}) ¦\s(\d)\s(.+)\s(.+)--\s(.+\d)\s.+\s.+\->\d+\-\d+\=(\d+)
[/Quote]


你真厉害，授人以鱼不如授人以渔，能不能教教你学正则的经验，我怎么就搞不懂呢？