make 如何处理同名目标（target）

[linlan999]

请具体解释：
LIBDIR_MODULES = $(RPC_DIST)/lib/linux/st40

modules modules_install : $(LIBDIR_MODULES)/Makefile
$(MAKE) -C $(KERNELDIR) M=$(LIBDIR_MODULES) $@

modules : kbuild_wrapper
-@$(ECHO) "WE ARE IN R3.1.1/makefile now!!!!!!!"
kbuild_wrapper :
$(MAKE) KBUILD_WRAPPER=1 \
KERNELDIR_ST40_LINUX_KO=$(KERNELDIR) \
DISABLE_IA32_LINUX=1 \
DISABLE_ST20_OS20=1 \
DISABLE_ST40_OS21=1 \
DISABLE_ST40_LINUX=1 \
DISABLE_ST40_WINCE=1 \
DISABLE_ST220_OS21=1 \
DISABLE_ST231_OS21=1 \
install

[linlan999]

哥们，你强！！ FC6下

[root@jim home]# vi makefile

all:lab1

@echo "bellow all:lab1 start! "
@echo "bellow all:lab1 end!"

all:lab2

@echo "bellow all:lab2 start"
@echo "bellow all:lab2 end!!!"


lab1:
@echo "bellow lab1 start "
@echo "bellow lab1 end"
lab2:
@echo "bellow lab2 start"
@echo "bellow lab2 end "


end:
@echo "the end!"~
~
"makefile" 27L, 300C written
[root@jim home]# make 2>/dev/null
bellow lab2 start
bellow lab2 end
bellow lab1 start
bellow lab1 end
bellow all:lab2 start
bellow all:lab2 end!!!
[root@jim home]#

[fierygnu]

依赖关系会被merge

[rzsheng]

写一个测试程序验证一下就知道了，
等待楼主的验证结果，