jquery 问题,进来吧！

[jerk_op]

function jf(){
$.ajax({
type: "POST",
url: "jf.do",
data: "name=j.fei",
success: function(msg){
alert( "Data Saved: " + msg );
}
});
}
就这样一个简单的请求，为什么不走success这个方法呢？
jf.do
response.setHeader("Cache-Control", "no-store");
response.setDateHeader("Expires", 0);
response.setContentType("text/xml; charset=UTF-8");
for (int i = 1, j = 1; j <= 9; i++) {
System.out.print(i + "*" + j + "=" + i * j + " ");
if (i == j) {
i = 0;
j++;
System.out.println();
}
}

try {
System.out.println(request.getParameter("name"));
PrintWriter outi = response.getWriter();
outi.print(request.getParameter("name"));
} catch (Exception e) {
e.printStackTrace();
}
return null;

[tony-杨]

你数据提交成功呢？
是否成功返回数据？