java clone问题

[hscgr]

public Employee clone() throws CloneNotSupportedException{
//call Object.clone()
Employee cloned=(Employee)super.clone();

//clone mutable fields
cloned.hireDay=(Date)hireDay.clone();

return cloned;
}
这儿为什么是 super.clone() 而不是this.clone()？这儿不应该是employee 的克隆吗？

[okwei1117]

帮顶..

[xiao7cn]

先调用Object.clone()方法

完成基本的克隆对象，然后再进行其它的克隆操作。

[xiao7cn]

/**
* Indicates whether some other object is "equal to" this one.
* <p>
* The <code>equals</code> method implements an equivalence relation
* on non-null object references:
* <ul>
* <li>It is <i>reflexive</i>: for any non-null reference value
* <code>x</code>, <code>x.equals(x)</code> should return
* <code>true</code>.
* <li>It is <i>symmetric</i>: for any non-null reference values
* <code>x</code> and <code>y</code>, <code>x.equals(y)</code>
* should return <code>true</code> if and only if
* <code>y.equals(x)</code> returns <code>true</code>.
* <li>It is <i>transitive</i>: for any non-null reference values
* <code>x</code>, <code>y</code>, and <code>z</code>, if
* <code>x.equals(y)</code> returns <code>true</code> and
* <code>y.equals(z)</code> returns <code>true</code>, then
* <code>x.equals(z)</code> should return <code>true</code>.
* <li>It is <i>consistent</i>: for any non-null reference values
* <code>x</code> and <code>y</code>, multiple invocations of
* <tt>x.equals(y)</tt> consistently return <code>true</code>
* or consistently return <code>false</code>, provided no
* information used in <code>equals</code> comparisons on the
* objects is modified.
* <li>For any non-null reference value <code>x</code>,
* <code>x.equals(null)</code> should return <code>false</code>.
* </ul>
* <p>
* The <tt>equals</tt> method for class <code>Object</code> implements
* the most discriminating possible equivalence relation on objects;
* that is, for any non-null reference values <code>x</code> and
* <code>y</code>, this method returns <code>true</code> if and only
* if <code>x</code> and <code>y</code> refer to the same object
* (<code>x == y</code> has the value <code>true</code>).
* <p>
* Note that it is generally necessary to override the <tt>hashCode</tt>
* method whenever this method is overridden, so as to maintain the
* general contract for the <tt>hashCode</tt> method, which states
* that equal objects must have equal hash codes.
*
* @param obj the reference object with which to compare.
* @return <code>true</code> if this object is the same as the obj
* argument; <code>false</code> otherwise.
* @see #hashCode()
* @see java.util.Hashtable
*/
public boolean equals(Object obj) {
return (this == obj);
}

/**
* Creates and returns a copy of this object. The precise meaning
* of "copy" may depend on the class of the object. The general
* intent is that, for any object <tt>x</tt>, the expression:
* <blockquote>
* <pre>
* x.clone() != x</pre></blockquote>
* will be true, and that the expression:
* <blockquote>
* <pre>
* x.clone().getClass() == x.getClass()</pre></blockquote>
* will be <tt>true</tt>, but these are not absolute requirements.
* While it is typically the case that:
* <blockquote>
* <pre>
* x.clone().equals(x)</pre></blockquote>
* will be <tt>true</tt>, this is not an absolute requirement.
* <p>
* By convention, the returned object should be obtained by calling
* <tt>super.clone</tt>. If a class and all of its superclasses (except
* <tt>Object</tt>) obey this convention, it will be the case that
* <tt>x.clone().getClass() == x.getClass()</tt>.
* <p>
* By convention, the object returned by this method should be independent
* of this object (which is being cloned). To achieve this independence,
* it may be necessary to modify one or more fields of the object returned
* by <tt>super.clone</tt> before returning it. Typically, this means
* copying any mutable objects that comprise the internal "deep structure"
* of the object being cloned and replacing the references to these
* objects with references to the copies. If a class contains only
* primitive fields or references to immutable objects, then it is usually
* the case that no fields in the object returned by <tt>super.clone</tt>
* need to be modified.
以下是Object.clone方法的注释：

/**
* Indicates whether some other object is "equal to" this one.
* <p>
* The method <tt>clone</tt> for class <tt>Object</tt> performs a
* specific cloning operation. First, if the class of this object does
* not implement the interface <tt>Cloneable</tt>, then a
* <tt>CloneNotSupportedException</tt> is thrown. Note that all arrays
* are considered to implement the interface <tt>Cloneable</tt>.
* Otherwise, this method creates a new instance of the class of this
* object and initializes all its fields with exactly the contents of
* the corresponding fields of this object, as if by assignment; the
* contents of the fields are not themselves cloned. Thus, this method
* performs a "shallow copy" of this object, not a "deep copy" operation.
* <p>
* The class <tt>Object</tt> does not itself implement the interface
* <tt>Cloneable</tt>, so calling the <tt>clone</tt> method on an object
* whose class is <tt>Object</tt> will result in throwing an
* exception at run time.

[xiao7cn]

/**
* Creates and returns a copy of this object. The precise meaning
* of "copy" may depend on the class of the object. The general
* intent is that, for any object <tt>x</tt>, the expression:
* <blockquote>
* <pre>
* x.clone() != x</pre></blockquote>
* will be true, and that the expression:
* <blockquote>
* <pre>
* x.clone().getClass() == x.getClass()</pre></blockquote>
* will be <tt>true</tt>, but these are not absolute requirements.
* While it is typically the case that:
* <blockquote>
* <pre>
* x.clone().equals(x)</pre></blockquote>
* will be <tt>true</tt>, this is not an absolute requirement.
* <p>
* By convention, the returned object should be obtained by calling
* <tt>super.clone</tt>. If a class and all of its superclasses (except
* <tt>Object</tt>) obey this convention, it will be the case that
* <tt>x.clone().getClass() == x.getClass()</tt>.
* <p>
* By convention, the object returned by this method should be independent
* of this object (which is being cloned). To achieve this independence,
* it may be necessary to modify one or more fields of the object returned
* by <tt>super.clone</tt> before returning it. Typically, this means
* copying any mutable objects that comprise the internal "deep structure"
* of the object being cloned and replacing the references to these
* objects with references to the copies. If a class contains only
* primitive fields or references to immutable objects, then it is usually
* the case that no fields in the object returned by <tt>super.clone</tt>
* need to be modified.
* <p>
* The method <tt>clone</tt> for class <tt>Object</tt> performs a
* specific cloning operation. First, if the class of this object does
* not implement the interface <tt>Cloneable</tt>, then a
* <tt>CloneNotSupportedException</tt> is thrown. Note that all arrays
* are considered to implement the interface <tt>Cloneable</tt>.
* Otherwise, this method creates a new instance of the class of this
* object and initializes all its fields with exactly the contents of
* the corresponding fields of this object, as if by assignment; the
* contents of the fields are not themselves cloned. Thus, this method
* performs a "shallow copy" of this object, not a "deep copy" operation.
* <p>
* The class <tt>Object</tt> does not itself implement the interface
* <tt>Cloneable</tt>, so calling the <tt>clone</tt> method on an object
* whose class is <tt>Object</tt> will result in throwing an
* exception at run time.
*
* @return a clone of this instance.
* @exception CloneNotSupportedException if the object's class does not
* support the <code>Cloneable</code> interface. Subclasses
* that override the <code>clone</code> method can also
* throw this exception to indicate that an instance cannot
* be cloned.
* @see java.lang.Cloneable
*/