js里如何让一个数自动加1

bnabinge 2008-09-09 05:16:43
$Ary_fValue[0] = new Array()
$Ary_fValue[0][0] = "[*NewsSmallPicFile*]"
$Ary_fValue[0][1] = "[*URLAddress*]"
$Ary_fValue[0][2] = "[*NewsTitle*]"
$Ary_fValue[0][3] = "[*CurtTitle*]"
这个是循环部分

循环四次
要出现的代码是
$Ary_fValue[0] = new Array()
$Ary_fValue[0][0] = "[*NewsSmallPicFile*]"
$Ary_fValue[0][1] = "[*URLAddress*]"
$Ary_fValue[0][2] = "[*NewsTitle*]"
$Ary_fValue[0][3] = "[*CurtTitle*]"
$Ary_fValue[1] = new Array()
$Ary_fValue[1][0] = "[*NewsSmallPicFile*]"
$Ary_fValue[1][1] = "[*URLAddress*]"
$Ary_fValue[1][2] = "[*NewsTitle*]"
$Ary_fValue[1][3] = "[*CurtTitle*]"
$Ary_fValue[2] = new Array()
$Ary_fValue[2][0] = "[*NewsSmallPicFile*]"
$Ary_fValue[2][1] = "[*URLAddress*]"
$Ary_fValue[2][2] = "[*NewsTitle*]"
$Ary_fValue[2][3] = "[*CurtTitle*]"
$Ary_fValue[3] = new Array()
$Ary_fValue[3][0] = "[*NewsSmallPicFile*]"
$Ary_fValue[3][1] = "[*URLAddress*]"
$Ary_fValue[3][2] = "[*NewsTitle*]"
$Ary_fValue[3][3] = "[*CurtTitle*]"
请问如果做到.我只要在二维数组里的第一维中自己让变量加1

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剑心永远OK 2008-09-10
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无语,无语
一品梅 2008-09-10
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弄这些乱七八糟的符号干什么?混淆视听?
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[Quote=引用 12 楼 zhihuixiaole 的回复:]
学过for循环不
[/Quote]

都说了嘛
不行的话就是他的人品问题
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<script>
var $Ary_fValue=new Array()
for(var i=0;i<4;i++){
alert("$Ary_fValue["+i+"] = new Array()\n$Ary_fValue["+i+"][0] = [*NewsSmallPicFile*]\n$Ary_fValue["+i+"][1] = [*URLAddress*]\n$Ary_fValue["+i+"][2] = [*NewsTitle*]\n$Ary_fValue["+i+"][3] = [*CurtTitle*]")
}
</script>
自己保存运行看看输出的是

是不是你说的几种结果
zhihuixiaole 2008-09-10
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学过for循环不
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for(var i=0;i<4;i++){
$Ary_fValue[i] = new Array()
$Ary_fValue[i][0] = "[*NewsSmallPicFile*]"
$Ary_fValue[i][1] = "[*URLAddress*]"
$Ary_fValue[i][2] = "[*NewsTitle*]"
$Ary_fValue[i][3] = "[*CurtTitle*]"
}


难道你说这个输出的结果不是:

$Ary_fValue[0] = new Array()
$Ary_fValue[0][0] = "[*NewsSmallPicFile*]"
$Ary_fValue[0][1] = "[*URLAddress*]"
$Ary_fValue[0][2] = "[*NewsTitle*]"
$Ary_fValue[0][3] = "[*CurtTitle*]"
$Ary_fValue[1] = new Array()
$Ary_fValue[1][0] = "[*NewsSmallPicFile*]"
$Ary_fValue[1][1] = "[*URLAddress*]"
$Ary_fValue[1][2] = "[*NewsTitle*]"
$Ary_fValue[1][3] = "[*CurtTitle*]"
$Ary_fValue[2] = new Array()
$Ary_fValue[2][0] = "[*NewsSmallPicFile*]"
$Ary_fValue[2][1] = "[*URLAddress*]"
$Ary_fValue[2][2] = "[*NewsTitle*]"
$Ary_fValue[2][3] = "[*CurtTitle*]"
$Ary_fValue[3] = new Array()
$Ary_fValue[3][0] = "[*NewsSmallPicFile*]"
$Ary_fValue[3][1] = "[*URLAddress*]"
$Ary_fValue[3][2] = "[*NewsTitle*]"
$Ary_fValue[3][3] = "[*CurtTitle*]"


如果不是,还是变量i的话,那还不是人品问题袄??
bnabinge 2008-09-10
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[Quote=引用 8 楼 chinmo 的回复:]
如果说那样不行就是你人品问题了

只给一部分代码
[/Quote]

怎么能这么说人呀

$Ary_fValue[0] = new Array()
$Ary_fValue[0][0] = "[*NewsSmallPicFile*]"
$Ary_fValue[0][1] = "[*URLAddress*]"
$Ary_fValue[0][2] = "[*NewsTitle*]"
$Ary_fValue[0][3] = "[*CurtTitle*]"
$Ary_fValue[1] = new Array()
$Ary_fValue[1][0] = "[*NewsSmallPicFile*]"
$Ary_fValue[1][1] = "[*URLAddress*]"
$Ary_fValue[1][2] = "[*NewsTitle*]"
$Ary_fValue[1][3] = "[*CurtTitle*]"
$Ary_fValue[2] = new Array()
$Ary_fValue[2][0] = "[*NewsSmallPicFile*]"
$Ary_fValue[2][1] = "[*URLAddress*]"
$Ary_fValue[2][2] = "[*NewsTitle*]"
$Ary_fValue[2][3] = "[*CurtTitle*]"
$Ary_fValue[3] = new Array()
$Ary_fValue[3][0] = "[*NewsSmallPicFile*]"
$Ary_fValue[3][1] = "[*URLAddress*]"
$Ary_fValue[3][2] = "[*NewsTitle*]"
$Ary_fValue[3][3] = "[*CurtTitle*]"
我要的是输出结果是这样子.你可的那东西.我早就已经自己写过了.根本就不管用.

我要上面的结果是数字.而不是变量
cgisir 2008-09-10
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猜!
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如果说那样不行就是你人品问题了

只给一部分代码
bnabinge 2008-09-10
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我试了一个都不行哇
strife013 2008-09-09
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[Quote=引用 4 楼 bhtfg538 的回复:]
引用 2 楼 chinmo 的回复:
汗!!
JScript code
for(var i=0;i <3;i++){
$Ary_fValue[i] = new Array()
$Ary_fValue[i][0] = "[*NewsSmallPicFile*]"
$Ary_fValue[i][1] = "[*URLAddress*]"
$Ary_fValue[i][2] = "[*NewsTitle*]"
$Ary_fValue[i][3] = "[*CurtTitle*]"
}


这样的意思??
[/Quote]
fosjos 2008-09-09
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var array = [ "[*NewsSmallPicFile*]","[*URLAddress*]","[*NewsTitle*]","[*CurtTitle*]" ];
for(var i=0; i<4; ++i){
$Ary_fValue[i] = new Array(array.length);
for(var j=0; j<array.length; ++j)
$Ary_fValue[i][j] = array[j];
}
bhtfg538 2008-09-09
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[Quote=引用 2 楼 chinmo 的回复:]
汗!!
JScript code
for(var i=0;i<3;i++){
$Ary_fValue[i] = new Array()
$Ary_fValue[i][0] = "[*NewsSmallPicFile*]"
$Ary_fValue[i][1] = "[*URLAddress*]"
$Ary_fValue[i][2] = "[*NewsTitle*]"
$Ary_fValue[i][3] = "[*CurtTitle*]"
}



这样的意思??
[/Quote]
jackyBody 2008-09-09
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全市星星,没有看懂 呵呵~帮你顶了 呵呵~
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汗!!
for(var i=0;i<3;i++){
$Ary_fValue[i] = new Array()
$Ary_fValue[i][0] = "[*NewsSmallPicFile*]"
$Ary_fValue[i][1] = "[*URLAddress*]"
$Ary_fValue[i][2] = "[*NewsTitle*]"
$Ary_fValue[i][3] = "[*CurtTitle*]"
}


这样的意思??
mrshelly 2008-09-09
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$Ary_fValue[$Ary_fValue.length] = new Array();

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