用正则表达式截取字符串

[sissoko]

将指定字符串中以M开头以N结尾的子串截取出来
这个正则表达式怎么写

[mayuanfei]

	  public static void main(String[] args) {
		  String[] strs = {"mn","mon","mea","moon","meeeeen","cmon","mona"};
		  Pattern pattern = Pattern.compile("^m[a-zA-Z]*n$");
		  for(String str : strs) {
			  Matcher m = pattern.matcher(str);
			  System.out.println(m.find());
		  }
	  }

[mayuanfei]

上面的正则不能批评汉字还有一些标点等，下面是非空格的字符都可以。

	  public static void main(String[] args) {
		  String[] strs = {"mn","mon","mea","moon","meeeeen","cmon","mona","m n","m好好好n"};
		  Pattern pattern = Pattern.compile("^m[^ ]*n$");
		  for(String str : strs) {
			  Matcher m = pattern.matcher(str);
			  System.out.println(m.find());
		  }
	  }

[sissoko]

谢谢了
我其实是要在JS里用这个正则表达式
但你已经给了我足够的信息了 万分感谢

[刘振锋]

public static void main(String[] args) {
String input = "ihaomdkinkkmkkkiihiinkkoh" ;
String regex = "(m[^n]*n)" ;
Pattern pattern = Pattern.compile(regex);
Matcher m = pattern.matcher(input) ;
while(m.find()){
System.out.println(m.group(1));
}
}

输出结果是:
mdkin
mkkkiihiin