ArrayList[]=new ArrayList[]?

[jljhwang]

ArrayList[] adUrls;
private void GetAdUrl(WebBrowser[] webs)
{
adUrls = new ArrayList[webs.Length];

for (int i = 0; i < webs.Length;i++ )
{
adUrls[i] = new ArrayList();
Regex r = new Regex(Reg(webs[i].Url.Host), RegexOptions.IgnoreCase | RegexOptions.Compiled);
Match m = r.Match(webs[i].DocumentText.ToLower());
while (m.Success)
{

if (!adUrls[i].Contains((webs[i].Url.ToString().Replace(GetSurf(webs[i].Url.Host), "")) + @"view.php?" + m.Value))
{
adUrl[i]s.Add((webs[i].Url.ToString().Replace(GetSurf(webs[i].Url.Host), "")) + @"view.php?" + m.Value);

}
else
{

}
m = m.NextMatch();
}
foreach (string str in adUrl[i])
{
listBox1.Items.Add(str);
}
}
}
listBox1中什么都没有。ArrayList[]可不可以这么用啊！

[孤剑]

ArrayList adUrls;
private void GetAdUrl(WebBrowser[] webs)
{
adUrls = new ArrayList(webs.Length);

for (int i = 0; i < webs.Length;i++ )
{
adUrls[i] = new ArrayList();
Regex r = new Regex(Reg(webs[i].Url.Host), RegexOptions.IgnoreCase | RegexOptions.Compiled);
Match m = r.Match(webs[i].DocumentText.ToLower());
while (m.Success)
{

if (!adUrls[i].Contains((webs[i].Url.ToString().Replace(GetSurf(webs[i].Url.Host), "")) + @"view.php?" + m.Value))
{
adUrls.Add((webs[i].Url.ToString().Replace(GetSurf(webs[i].Url.Host), "")) + @"view.php?" + m.Value);

}
else
{

}
m = m.NextMatch();
}
foreach (string str in adUrl)
{
listBox1.Items.Add(str);
}
}
}

[wdgphc]

当然可以这么用的.

你设断点看看
if (!adUrls[i].Contains((webs[i].Url.ToString().Replace(GetSurf(webs[i].Url.Host), "")) + @"view.php?" + m.Value))
{
adUrl[i]s.Add((webs[i].Url.ToString().Replace(GetSurf(webs[i].Url.Host), "")) + @"view.php?" + m.Value);

}
else
{

}
这里的if条件是否成立过.即adUrl[i]s.Add 是否添加进了内容.

[花落_]

foreach (string str in adUrl[i])
{
listBox1.Items.Add(str);
}
改为
foreach (object obj in adUrl[i])
{
string str=(string)obj;
listBox1.Items.Add(str);
}

这样，你再试试

[jljhwang]

if条件是不加入相同的元素，不使用ArrayList[] adUrls时成立