spring+hibernate+mysql 急

[shirleygu119]

Caused by: com.mysql.jdbc.exceptions.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '.link link0_' at line 1

public List<Links> getLinksVOS() throws DataAccessException {
List list = null;
StringBuffer hql = new StringBuffer();
hql.append(" from Link");
list = getHibernateTemplate().find(hql.toString());
return list;
}
}

有Link.java

[zidasine]

Link ?? Links ??
确定一下是哪个
你list里用泛型规定是Links
而hql语句中却用Link

[shirleygu119]

List list = null;
StringBuffer hql = new StringBuffer();
hql.append("select Link");
list = getHibernateTemplate().find(hql.toString());
return list;

java.lang.NullPointerException
at org.hibernate.hql.ast.util.SessionFactoryHelper.findSQLFunction(SessionFactoryHelper.java:342)
at org.hibernate.hql.ast.tree.IdentNode.getDataType(IdentNode.java:266)
at org.hibernate.hql.ast.tree.SelectClause.initializeExplicitSelectClause(SelectClause.java:143)
at org.hibernate.hql.ast.HqlSqlWalker.useSelectClause(HqlSqlWalker.java:712)
at org.hibernate.hql.ast.HqlSqlWalker.processQuery(HqlSqlWalker.java:536)
....发不上去了

[zidasine]

public List <Link> getLinksVOS() throws DataAccessException { 
List list = null; 
StringBuffer hql = new StringBuffer(); 
hql.append("from Link"); 
list = getHibernateTemplate().find(hql.toString()); 
return list; 
} 

[shirleygu119]

又报一开始的错了，谁帮我啊。。。。