重载后缀++不明白的地方

[zwlzwlzwl]

返回const：
const Byte Byte::operator++(int)----------------//第一种写法
{
Byte Before(*this);
++(*this)
return Before;
}
返回非const：
Byte Byte::operator++(int)-------------------//第二种写法
{
Byte Before(*this);
++(*this)
return Before;
}

在c++编程思想的P279页中对后缀重载返回值有说明，operator++（int）返回临时对象，临时对象自动为常量。
调用方式：
Byte a;
(a++).func() ///func为非const成员
对于第一种写法编译器肯定会报错，但对于第二种写法编译器并没报错，按照c++编程思想的说法，编译器会阻止，是编译器的原因吗？
我知道第二种写法会导致a++++的问题，违背了++++的语义，不建议使用，所以返回const。

[boys2002]

还真没接触过 这个~~~

顶一下 占个SOFA


别忘记给点分啊 楼上 ~~~

[matrixdwy]

LZ请看第八章：Constants--Returning by const value--Temporaries一节，英文版是第348页

However, notice the expressions that are legal:
f5() = X(1);
f5().modify();
Although these pass muster for the compiler, they are actually
problematic. f5( ) returns an X object, and for the compiler to satisfy
the above expressions it must create a temporary to hold that
return value. So in both expressions the temporary object is being
modified, and as soon as the expression is over the temporary is
cleaned up. As a result, the modifications are lost so this code is
probably a bug – but the compiler doesn’t tell you anything about
it. Expressions like these are simple enough for you to detect the
problem, but when things get more complex it’s possible for a bug
to slip through these cracks.

也就是说这种错误编译器是不会报警的。这种错误是比较明显的，所以你应该自己去
发现解决。

[帅得不敢出门]

看看此贴 说的好热烈 可能对你有帮助
http://topic.csdn.net/t/20031209/21/2546246.html

[thecrypig]

嗯，我得学好英文，得考四级.....

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