求将 CString 字符串 转换成 ASC 码后保存到一个 CString 中的代码

[aix8848]

求将 CString 字符串 转换成 ASC 码后保存到一个 CString 中的代码

如何ASCII码不够三位,前面补0 ,谢谢!!!

[aix8848]

字符串由数字与英文字母组成

[brightxu]

http://topic.csdn.net/u/20080510/08/82f729b8-a8ea-429a-86f4-37939bf2ecf5.html
seese,then find another!

[wudeshou82666]

CString 字符串 是HEX码的字符串吧

[wudeshou82666]

CString covert(CString s1)
{
char ch[2]={0};
int size = s1.GetLength();
char* pch = new char[size/2];
for(int i=0;i<size;i++)
{
ch[0]=s1.GetAt(2*i);
ch[1]=s1.GetAt(2*i+1);
pch[i]=strtol("%c",&ch,16);
}
CString s2(pch);
delete [] pch;
return s2;
}
不知道行不行

[wudeshou82666]

CString covert(CString s1)
{
char ch[2]={0};
int size = s1.GetLength();
char* pch = new char[size/2+1];
for(int i=0;i <size/2;i++)
{
ch[0]=s1.GetAt(2*i);
ch[1]=s1.GetAt(2*i+1);
pch[i]=strtol(ch,NULL,16);
}
CString s2(pch);
delete [] pch;
return s2;
}

[jia_xiaoxin]

写了一个转换函数

CString PrintAscII(CString m_str)
{
	CString m_Org;
	int nLen = m_str.GetLength();
	
	m_Org.Empty();
	for(int i = 0; i < nLen; i++)
	{
		char ch = m_str.GetAt(i);
		char buf[10];
		if(ch < 100)
			m_Org += "0";
		else if(ch < 10)
			m_Org += "00";			
		
		itoa(ch, buf, 10);
		m_Org += buf;
	}

	return m_Org;

}

[baihacker]

//仅以标准库中的string例
#include <iostream>
#include <string>
using namespace std;

int main()
{
	string str = "abcdefg0123456";
	string result = "";
	char buff[8];
	for (int i = 0; i < str.length(); ++i)
		result = result + itoa(str[i], buff, 10) + " ";//想要相连的话,直接去掉空格
	while (result.length() < 3) result = "0" + result;
	cout << result << endl;
	for (int j = 0; j < str.length(); ++j)
			cout << int(str[j]) << " "; //如果想要把元素要整数的形式访问,直接使用[]就行了
	cout << endl;
	return 0;
}