关于数组函数

iamhejianke 2008-10-23 12:34:37

有一数组array("0"=>array("Position"=>"1","CupID"=>"11"),"1"=>array("Position"=>"2","CupID"=>"11"),"2"=>array("Position"=>"31","CupID"=>"15"),"3"=>array("Position"=>"32","CupID"=>"15"));
如何转换为
array("11"=>array("1"=>array(Position"=>"1","CupID"=>"11"),"2"=>array(Position"=>"2","CupID"=>"11")),"15"=>array("31"=>array(Position"=>"31","CupID"=>"15"),"32"=>array(Position"=>"32","CupID"=>"15")))

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切换为时间正序

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cuidenghong123 2008-10-23

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先遍历后重新生成

程序猿之殇 2008-10-23

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$arrTmp = array();

foreach($arrTest as $key=> $value)

{

	$cupId = $value['CupID'];

	$arrTmp[$cupId][] = $value;

}

print_r($arrTmp);

结帖吧．

iamhejianke 2008-10-23

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最后的数组形式是array["$CupID"]["$Position"][..]

程序猿之殇 2008-10-23

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遍历数组，获取cupID值后，重新生成新的数组．

程序猿之殇 2008-10-23

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思路有了，自己去实践吧．

iamhejianke 2008-10-23

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谢谢!
我的本来意思系,有无一个通用的函数,把一个二维的数组,生成多维的数组,
如array("0"=>array("Position"=>"1","CupID"=>"11","ID"=>""),"1"=>array("Position"=>"2","CupID"=>"11","ID"=>""),"2"=>array("Position"=>"31","CupID"=>"15","ID"=>""),"3"=>array("Position"=>"32","CupID"=>"15","ID"=>""));

传入参数array("CupID","Position")=>可以生成 array["$CupID"]["$Position"][..]
传入参数array("CupID","Position","ID")=>可以生成 array["$CupID"]["$Position"]["$ID"][..]