关于lock 在线等啊？

[v41dugu]

namespace ConsoleApplication1
{

class MyClass
{
public int num;
public void Fun()
{
lock (this)
{
num = 555;
Console.WriteLine("线程一锁住this了{0}",num);
Thread.Sleep(6000);
Console.WriteLine("线程一锁解开this了");
}
}
public void Fun2()
{
lock (this)
{
num = 999;
Console.WriteLine("线程二锁住this了{0}", num);
Thread.Sleep(6000);
Console.WriteLine("线程二锁解开this了");
}
}
}

class Program
{
static MyClass obj = new MyClass();
static Thread t1 = new Thread(new ThreadStart(obj.Fun));
//static Thread t2 = new Thread(new ThreadStart(obj.Fun2));
static void Main(string[] args)
{
MyClass obj = new MyClass();
t1.Start();
Thread.Sleep(500);
obj.Fun2();
//t2.Start();
}

}
}为什么Fun已经锁了this, 而再调用obj.Fun2()， 也去lock， 还是可以访问this啊？ 如果改成下面这样（没有用obj调Fun2,也用的另开一个Thead调用） 为什么 Fun2就会等待Fun结束了之后再进行啊？ 不懂啊？？？？？ 这里lock的原理到底是什么啊？？
namespace ConsoleApplication1
{

class MyClass
{
public int num;
public void Fun()
{
lock (this)
{
num = 555;
Console.WriteLine("线程一锁住this了{0}",num);
Thread.Sleep(6000);
Console.WriteLine("线程一锁解开this了");
}
}
public void Fun2()
{
lock (this)
{
num = 999;
Console.WriteLine("线程二锁住this了{0}", num);
Thread.Sleep(6000);
Console.WriteLine("线程二锁解开this了");
}
}
}

class Program
{
static MyClass obj = new MyClass();
static Thread t1 = new Thread(new ThreadStart(obj.Fun));
static Thread t2 = new Thread(new ThreadStart(obj.Fun2));
static void Main(string[] args)
{
MyClass obj = new MyClass();
t1.Start();
Thread.Sleep(500);
//obj.Fun2();
t2.Start();
}

}
}

[minioreo]

你可以检查当前对象的GetHashCode（）来看是不是同一个对象 同一个对象的GetHashCode（）返回值是相同的

        public void Fun()
        {
            lock (this)
            {
                num = 555;
                Console.WriteLine("线程一锁住this了{0}", num);
                Console.WriteLine("当前对象:{0}",this.GetHashCode());
                Thread.Sleep(6000);
                Console.WriteLine("线程一锁解开this了");
            }
        }
        public void Fun2()
        {
            lock (this)
            {
                num = 999;
                Console.WriteLine("线程二锁住this了{0}", num);
                Console.WriteLine("当前对象:{0}", this.GetHashCode());
                Thread.Sleep(6000);
                Console.WriteLine("线程二锁解开this了");
            }
        }

方法改成这样就很明显了 局部变量和外部Static变量重名的时候 内部对象就覆盖外部对象的名称了 所以此OBJ1非彼OBJ1

[v41dugu]

疯了 晕 thanks.

[minioreo]

呵呵

[林g]

学习了！

[minioreo]

你的Static的obj1和Main里的obj1不是同一个对象