求高手帮忙解决一个很实用的问题

[king4323210]

如果将用户从控制台输入的
52531.12
转换输出
伍万贰千伍佰叁拾壹元壹角贰分

不求算法
只求解题思路 谢谢！

[rugaoason]

准备2个数组
String[] a = new String[]{"分","角","元".....}；
String[] b = new String[]{"十","百","千".....};

[justinavril]

肯定要有个一个方法，去匹配阿拉伯数字和中文的壹...用switch.case做
然后就是取每一位的数字和他的位数了 我觉得不用拿这个数去整除什么10000啊什么的 直接拿字符串做处理 比如第5位的就是“万”

[king4323210]

不好做啊！
要几个循环啊？

[king4323210]

步骤能再详细点吗
一步一步的
谢谢！

[xwguan]

a[]={"壹","贰","叁"...."九"}
b[]={"角","分","元"}
c[]={"拾","百","千","万","百万","千万","亿"...}
将你的数据转换成字符串，然后以.分成两部份。

[king4323210]

谢谢你的思路！
不太明白！

[一头头]

import java.util.*;

public class Change {

	/**
	 * @param args
	 */
	long e;
	int FirstDigit;
	int SecondDigit;
	int ThirdDigit;
	int FourthDigit;
	int FifthDigit;
	int Digit;
	public Change (long e){
		this.e = e;
	}
	public String GargeDigit(){
		String a5,a4,a3,a2,a1;
		Contain a = new Contain();
		if(e/100000>0)
		{   String g = "错误,数字必须小于十万";
			return g;
			}
		else if (e/10000>0) {
			FirstDigit = (int)e/10000;
			SecondDigit = (int)((e/1000)%10);
			ThirdDigit = (int)((e/100)%10);
			FourthDigit = (int) ((e/10)%10);
			FifthDigit = (int) ((e/1)%10);
			Digit = 5;
			if (FirstDigit != 0) a5 = String.valueOf(FirstDigit);
			else a5= "";
			if (SecondDigit != 0) a4 = String.valueOf(SecondDigit);
			else a4 = "";
			if (ThirdDigit != 0) a3 = String.valueOf(ThirdDigit);
			else a3 = "";
			if(FourthDigit != 0) a2 = String.valueOf(FourthDigit);
			else a2 = "";
			a1 = String.valueOf(FifthDigit);
			String result = a.map2.get(a5) + a.map1.get("1") + a.map2.get(a4) + a.map1.get("2") + a.map2.get(a3) + a.map1.get("3")+ a.map2.get(a2) + a.map1.get("4") + a.map2.get(a1);
			return result;
			}
		else return "a";
	/*	else if (e/1000>0) {
			FirstDigit = 0;
			SecondDigit = (int)e/1000; 
			ThirdDigit = (int)(e/100)%10;
			FourthDigit = (int) ((e/10)%10);
			FifthDigit = (int) ((e/1)%10);
			Digit = 4;
			}
		else if (e/100>0) { 
			FirstDigit = 0;
			SecondDigit = 0;
			ThirdDigit =(int)e/100; 
			FourthDigit = (int) ((e/10)%10);
			FifthDigit = (int) ((e/1)%10);
			Digit =3;
			}
		else if (e/10>0) {
			FirstDigit = 0;
			SecondDigit = 0;
			ThirdDigit = 0;
			FourthDigit =(int)e/100; 
			FifthDigit = (int) ((e/1)%10);
			Digit =2;
			}
		else if (e>0) { 
			FirstDigit = 0;
			SecondDigit = 0;
			ThirdDigit = 0;
			FourthDigit = 0;
			FifthDigit = (int) ((e/1)%10); 
			Digit =1;
			}*/
	}
	public static void main(String[] args) {
		// TODO Auto-generated method stub
		Change a = new Change(75432);
		System.out.println(a.GargeDigit());
		System.out.println("Digit = " + a.Digit);
		System.out.println("FirstDigit = " + a.FirstDigit);
		System.out.println("SecondDigit = " + a.SecondDigit);
		System.out.println("ThirdDigit = " + a.ThirdDigit);
		System.out.println("FourthDigit = " + a.FourthDigit);
		System.out.println("FifthDigit = " + a.FifthDigit);
		
		
	}

}
class Contain{
	Map<String,String> map1 = new HashMap<String,String>();
	Map<String,String> map2 = new HashMap<String,String>();
	public Contain(){	
		
		map1.put("1", "万");
		map1.put("2", "千");
		map1.put("3", "百");
		map1.put("4", "十");
		map1.put("", "");
		
		map2.put("1", "壹");
		map2.put("2", "貳");
		map2.put("3", "叁");
		map2.put("4", "肆");
		map2.put("5", "伍");
		map2.put("6", "陆");
		map2.put("7", "柒");
		map2.put("8", "捌");
		map2.put("9", "玖");
		map2.put("0", "");
		
}
	
}

// 只能输入5位数
// 第一个问题 当50000的时候 千百十也有输出
// 第二个问题 当50001的时候 输出不对

/*

我自己写的 还有很多很多bug LZ跟我一起优化下好吗

[xiaolvlm]

把数分为整数部分和小数部分,然后写算法 一位一位取出来 配上相应的大写壹....