direct中怎样将3d模型的坐标转换为屏幕的坐标???

[sun2985]

我导入了一个3d模型,就是一个正方体,按住右键拖动可以使其自由旋转,然后我想做到左键点击屏幕时判断如果点在模型的某个面(能看到的)内,就使这个面变亮,请问如何做到?

[zzz822163]

看选取的章节,有详细的介绍,就是那个计算射线

[sun2985]

能不能稍加叙述一下?

[zzz822163]

directx 的例子下面有个Pick,你可以看看

const D3DXMATRIX *pmatProj = g_Camera.GetProjMatrix();

        POINT ptCursor;
        GetCursorPos( &ptCursor );
        ScreenToClient( DXUTGetHWND(), &ptCursor );

        // Compute the vector of the pick ray in screen space
        D3DXVECTOR3 v;
        v.x =  ( ( ( 2.0f * ptCursor.x ) / pd3dsdBackBuffer->Width  ) - 1 ) / pmatProj->_11;
        v.y = -( ( ( 2.0f * ptCursor.y ) / pd3dsdBackBuffer->Height ) - 1 ) / pmatProj->_22;
        v.z =  1.0f;

        // Get the inverse view matrix
        const D3DXMATRIX matView = *g_Camera.GetViewMatrix();
        const D3DXMATRIX matWorld = *g_Camera.GetWorldMatrix();
        D3DXMATRIX mWorldView = matWorld * matView;
        D3DXMATRIX m;
        D3DXMatrixInverse( &m, NULL, &mWorldView );

        // Transform the screen space pick ray into 3D space
        vPickRayDir.x  = v.x*m._11 + v.y*m._21 + v.z*m._31;
        vPickRayDir.y  = v.x*m._12 + v.y*m._22 + v.z*m._32;
        vPickRayDir.z  = v.x*m._13 + v.y*m._23 + v.z*m._33;
        vPickRayOrig.x = m._41;
        vPickRayOrig.y = m._42;
        vPickRayOrig.z = m._43;

[zzz822163]

你去找DirectX 9 3D游戏设计入门这本书看看吧,讲的很详细了,找不到的话告诉我，我发给你吧

[sun2985]

好啊,我找不到..............
我的邮箱:[e-mail]
要不就qq:896566785

[sun2985]

找到了..................

[sun2985]

没给成分????