STL,编译时出错....

[aa806525280]

函数功能；排序后删除重复的值
#include<iostream>
#include<vector>
#include<functional>
#include<algorithm>
using namespace std;
int reduce ( int ar[],int n);
int main(){
int n=9;
int a[]={9,8,7,6,5,4,3,2,1};
reduce(a[],n);
return 0;
}
int reduce ( int ar[],int n)
{vector<int>svec(ar,ar+n);
vector<int> ::iterator pointer;
vector<int> ::iterator end;
sort(svec.begin(),svec.end()); //排序
end= unique(svec.begin(),svec.end());//连续相同的只留一个
int i=end-svec.begin();剩下元素个数
cout<<i<<endl;
for(pointer=svec.begin();pointer!=end;pointer)
cout<<*pointer<<endl;


}

[Non_Recursive]

reduce(a[],n); //reduce(a,n)

还有，请发一下错误信息

[aa806525280]

按一楼改过后，
Linking...
LINK : fatal error LNK1168: cannot open Debug/0000.exe for writing
执行 link.exe 时出错.

[wangkangsoldier]

编译时出什么错误？

将vector<int>svec(ar,ar+n)改成vector<int>svec(ar,ar+n-1)试试
将试试将reduce函数中的数组形参改成指针传递

[gccdy]

#include<iostream> 
#include<vector> 
#include<functional> 
#include<algorithm>

using namespace std; 

int reduce( int ar[],int n);

int main(){
    int n=9; 
    int a[]={9,8,7,6,5,4,3,2,1}; 
    reduce(a,n); 
    return  0; 
} 
int reduce ( int ar[],int  n) {
    vector<int> svec(ar,ar+n); 
    vector<int>::iterator  pointer; 
    vector<int>::iterator  end; 
    sort(svec.begin(),svec.end());  //排序 
    end= unique(svec.begin(),svec.end());//连续相同的只留一个 
    //int i = end - svec.begin();剩下元素个数 
    //cout << i <<endl; 
    for(pointer=svec.begin();pointer!=svec.end();pointer++) 
        cout <<*pointer <<endl; 
    
    system("pause");
    return 0;
} 

[gccdy]

#include<iostream> 
#include<vector> 
#include<functional> 
#include<algorithm>

using namespace std; 

int reduce( int ar[],int n);

int main(){
    int n=9; 
    int a[]={9,8,7,6,5,4,3,2,1}; 
    reduce(a,n); 
    return  0; 
} 
int reduce ( int ar[],int  n) {
    vector<int> svec(ar,ar+n); 
    vector<int>::iterator  pointer; 
    vector<int>::iterator  end; 
    sort(svec.begin(),svec.end());  //排序 
    end= unique(svec.begin(),svec.end());//连续相同的只留一个 
    int i = end - svec.begin();//剩下元素个数 
    cout << i <<endl; 
    for(pointer=svec.begin();pointer!=svec.end();pointer++) 
        cout <<*pointer <<endl; 
    
    system("pause");
    return 0;
} 

[aa806525280]

谢谢！我真是粗心，向你们学习 】
#include<iostream>
#include<vector>
#include<functional>
#include<algorithm>

using namespace std;

int reduce( int ar[],int n);

int main(){
int n=9;
int a[]={9,8,7,6,5,4,3,2,1};
reduce(a,n);
return 0;
}
int reduce ( int ar[],int n) {
vector<int> svec(ar,ar+n);
vector<int>::iterator pointer;
vector<int>::iterator end;
sort(svec.begin(),svec.end()); //排序
end= unique(svec.begin(),svec.end());//连续相同的只留一个
int i = end - svec.begin();//剩下元素个数
cout << i <<endl;
for(pointer=svec.begin();pointer!= end ;pointer++)
cout <<*pointer <<endl;

system("pause");
return 0;
}

[mujiok2003]

#include<iostream>
#include<vector>
//#include<functional>
#include<iterator>
#include<algorithm>

using namespace std;

void reduce(int [],int);

int main(){
int n=9;
int a[]={9,8,7,6,5,4,3,2,1};
reduce(a,n);
return 0;
}
void reduce ( int ar[],int n) {
sort(ar,ar+n);
int * end = unique(ar,ar+n);
cout << distance(ar,end) <<endl;
copy(ar, ar+n, ostream_iterator<int>(cout,"\n"));
}

[太乙]

upup~~~~~~

[aa806525280]

请问一下，上面说的是不是都是一个意思？有点迷茫...

[SearchLife]

up