WinFrom 打开文件夹目录?

[zhaozhijun0207]

[C#]

WinFrom界面有个按钮,当我点击按钮"打开"时,就打开"E:\A文件夹"这样子.

如果有"相对路径"的打开方法就更好了."\项目\A文件夹"

sos...sos...

[zhaozhijun0207]

?

[lizhengnan]

        Process p = new Process();

        ProcessStartInfo pi = new ProcessStartInfo;

        pi.FileName = "E:\";
        pi.Verb = "Open";
        pi.CreateNoWindow = false;

        p.StartInfo = pi；
        p.Start()；

[zhaozhijun0207]

[Quote=引用 2 楼 lizhengnan 的回复:]
C# code

Process p = new Process();

ProcessStartInfo pi = new ProcessStartInfo;

pi.FileName = "E:\";
pi.Verb = "Open";
pi.CreateNoWindow = false;

p.StartInfo = pi；
p.Start()；
[/Quote]

3Q,可以做到了!

还有个问题想问下,我想打开我项目里面的文件夹,怎么获取相对路径呢?
我的项目可能今天放D盘,明天放E盘
pi.FileName = "\项目\A文件夹";

[lokiice]

[Quote=引用 3 楼 zhaozhijun0207 的回复:]
3Q,可以做到了!

还有个问题想问下,我想打开我项目里面的文件夹,怎么获取相对路径呢?
我的项目可能今天放D盘,…
[/Quote]

pi.FileName = "项目\\A文件夹";这样吧,我也不确定,直接访问运行路径下的文件是用"asd.txt"这样,所以我想运行路径后的相对路径也是没前导反杠的

[lizhengnan]

Application.ExecutablePath
程序的当前目录

[gomoku]

    // 要添加到System.Design的引用
    class FolderBrowser : System.Windows.Forms.Design.FolderNameEditor
    {
        public FolderBrowser(){dialog = new System.Windows.Forms.Design.FolderNameEditor.FolderBrowser(); }
        public string Description { get { return dialog.Description; } set { dialog.Description = value; } }
        public string DirectoryPath { get { return dialog.DirectoryPath; } }
        public DialogResult ShowDialog(){return dialog.ShowDialog();}
        public DialogResult ShowDialog(IWin32Window owner) {return dialog.ShowDialog(owner); }

        private System.Windows.Forms.Design.FolderNameEditor.FolderBrowser dialog;
    }

    void Test()
    {
        FolderBrowser browser = new FolderBrowser();
        if (browser.ShowDialog() == DialogResult.OK)
        {
            MessageBox.Show(browser.DirectoryPath);
        }
    }

[zhaozhijun0207]

System.Diagnostics.Process.Start("explorer.exe",url);