请教：用java编写将十六进制数转换为十进制数的方法

[zzjh_2008]

请教：用java编写将十六进制数转换为十进制数的方法，该方法通过参数形式接收待转换的十六进制数。转换后的输出格式为：十六进制数XXX；十进制数YYY。其中XXX代表待转换的十六进制数，YYY代表转换后的十进制数。运行程序时，待转换的十六进制数通过命令行参数输入。

[sunnylyy]

public static void main(String[] args){
		if(args.length != 1){
			System.out.println("please input a hex number");
			return;
		}
		try
		{
			int num = Integer.parseInt(args[0].substring(2), 16);
			System.out.println(num);
		}
		catch(Exception e){
		
			System.out.println("please input a correct hex number");
		}
	}

[ZiSheng]

System.out.println(Integer.parseInt("1F",16));

[fuyou001]

[Quote=引用 2 楼 sunnylyy 的回复:]
Java codepublic static void main(String[] args){
if(args.length != 1){
System.out.println("please input a hex number");
return;
}
try
{
int num = Integer.parseInt(args[0].substring(2), 16);
System.out.println(num);
}
catch(Exception e){

System.out.println("please input…
[/Quote]

[zzjh_2008]

[Quote=引用 2 楼 sunnylyy 的回复:]
Java codepublic static void main(String[] args){
if(args.length != 1){
System.out.println("please input a hex number");
return;
}
try
{
int num = Integer.parseInt(args[0].substring(2), 16);
System.out.println(num);
}
catch(Exception e){

System.out.println("please input…
[/Quote]
没有输入流，而且不符合要求，能不能写的详细一点啊？

[shenjie1989]

import java.awt.*;
public class d2x extends Frame
{
int decimalValue= 0;
String baseXValue = new String("0");
TextField dDisplay,xDisplay;
//d2x constructor
d2x()
{
super("Decimal Converter");//set the title of the frame
MenuBar mb = new MenuBar();
Button d2Binary = new Button("Binary");
Button d2Octal = new Button("Octal");
Button d2Hex = new Button("Hex");
Button d2Base36 = new Button("Base36");
Panel p1 = new Panel();
Panel p2 = new Panel();
Panel p3 = new Panel();

//add a simple menu
Menu m = new Menu("Application");
m.add(new CheckboxMenuItem("Base 36 Active"));
m.add(new MenuItem("Exit"));

//add menu to menubar
mb.add(m);
setMenuBar(mb);//install this menu bar in the frame

//Add buttons to their own panel
p3.setLayout(new FlowLayout());
p3.add(d2Binary);
p3.add(d2Octal);
p3.add(d2Hex);
p3.add(d2Base36);

//Add text fields
Label dLabel = new Label("Enter Deecimal: ");
Label xLabel = new Label("Converted Value: ");
dDisplay = new TextField(Integer.toString(decimalValue),7);
xDisplay = new TextField(baseXValue,32);
xDisplay.setEditable(false);
p1.setLayout(new FlowLayout(FlowLayout.LEFT));
p2.setLayout(new FlowLayout(FlowLayout.LEFT));
p1.add(dLabel);
p1.add(dDisplay);
p2.add(xLabel);
p2.add(xDisplay);

//Add the panels
add("North",p1);
add("Center",p2);
add("South",p3);
}//end d2x constructor

public void start()
{
resize(400,150);
show();
}

public void updateXDisplay()
{
xDisplay.setText(baseXValue);
}

public boolean handleEvent(Event evt)
{
if (evt.target instanceof MenuItem)
{
if ("Exit".equals(((MenuItem)evt.target).getLabel()))
{
hide();
dispose();
System.exit(0);
return false;
}
return true;
}
else if(evt.target instanceof Button)
{
String whick = ((Button)evt.target).getLabel();
if (whick.equals("Binary"))
{
decimalValue = Integer.parseInt(dDisplay.getText());
baseXValue = Integer.toString(decimalValue,2);
}
if (whick.equals("Octal"))
{
decimalValue = Integer.parseInt(dDisplay.getText());
baseXValue = Integer.toString(decimalValue,8);
}
if (whick.equals("Hex"))
{
decimalValue = Integer.parseInt(dDisplay.getText());
baseXValue = Integer.toString(decimalValue,16);
}
if (whick.equals("36"))
{
decimalValue = Integer.parseInt(dDisplay.getText());
baseXValue = Integer.toString(decimalValue,36);
}
updateXDisplay();
return true;
}
return false;
}


public static void main(String args[])
{
d2x m = new d2x();
m.start();
}
}

[sunnylyy]

输入流？

楼主搞什么，不是写着通过命令行输入么？

[yun00112300]

public static void main(String args[]) throws NumberFormatException, IOException{
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
System.out.println(Integer.parseInt(in.readLine().toString(), 16));
}

[KOOK_OKKO]

System.out.println(Integer.valueOf("ff",16));

[dreamhunter_lan]

好像根本就不用转
比如:
输入：0x12
输出：18

[renxws]

你写的方法很好但是有毛病！假如我输入“ssss”，将其转化成16进制 出现异常

[breezes2008]

2楼回答得好！支持。