二个整数相除, 如何得到一个浮点数啊?

[CSharp_XinBing]

比如int iX = 300; int iY = 510;
得到浮点数, 应该如何, 谢谢!

[笺香]

double f=(double)iX/iY;强制转换

[猿敲月下码]

[Quote=引用 3 楼 pinyu 的回复:]
double db_result =ix*1.0/iy
[/Quote]

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[treesky]

            int m = 100;
            int x = 22;
            Console.WriteLine((double)m/x);
            Console.ReadLine();

[jerryzzf]

double f=(double)iX/(double)iY;

[guang555]

呵呵 简单，，

[jstzcl007]

double db_result=iX/iY就行了
结果变量要定义成浮点类型的

[aimeast]

double f=(double)iX/iY;

[pinyu]

double db_result =ix*1.0/iy

[bloodish]

[Quote=引用 2 楼 aimeast 的回复:]
C# codedouble f=(double)iX/iY;
[/Quote]

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[tang_fu]

double f=(double)iX/iY;

[public_private]

很简单嘛