求一个SQL语句，如何获得每个班的分数第二名的姓名

[jane0228]

成绩表 A ：学号（Number）<主键>、成绩（Score）
学生表 B： 学号（Number）<主键>、姓名（Name）、班级（Class）
求出每个班的分数第二名的姓名。

[-狙击手-]

2005 ？

[zhouxu_hust]

.....

[csdyyr]

select distinct name
from a join b on a.number=b.number
where Score in (select top 2 Score from a where number=b.number order by Score desc)

[csdyyr]

[Quote=引用 3 楼 csdyyr 的回复:]
SQL codeselectdistinctnamefromajoinbona.number=b.numberwhereScorein(selecttop2Scorefromawherenumber=b.numberorderbyScoredesc)
[/Quote]

select distinct name
from a join b on a.number=b.number
where (select count(distinct Score) from a where number=a.number and Score>a.Score)=1

[csdyyr]

[Quote=引用 4 楼 csdyyr 的回复:]
引用 3 楼 csdyyr 的回复:
SQL codeselectdistinctnamefromajoinbona.number=b.numberwhereScorein(selecttop2Scorefromawherenumber=b.numberorderbyScoredesc)

SQL codeselectdistinctnamefromajoinbona.number=b.numberwhere(selectcount(distinctScore)fromawherenumber=a.numberandScore>a.Score)=1
[/Quote]

--别名错了
select distinct name
from a as t join b on t.number=b.number
where (select count(distinct Score) from a where number=t.number and Score>t.Score)=1

[-狙击手-]

select tb.Number,tb.Name,tb.Class,ta.Score
from a as ta
left join b as tb
on ta.Number = tb.Number
where (select count(1) from a,b where a.number = b.number and b.Class= tb.Class and a.Score >=ta.Score) = 2

[jimoshatan]

CREATE TABLE #A (S_NO VARCHAR(10),S_NUM INT)
INSERT INTO #A SELECT 101,80
INSERT INTO #A SELECT 102,65
INSERT INTO #A SELECT 103,80
INSERT INTO #A SELECT 104,75
INSERT INTO #A SELECT 105,95
INSERT INTO #A SELECT 106,88
INSERT INTO #A SELECT 107,90

CREATE TABLE #B (S_NO VARCHAR(10),S_NAME VARCHAR(10),S_CLASS VARCHAR(10))
INSERT INTO #B SELECT 101,'A','A01'
INSERT INTO #B SELECT 102,'B','A01'
INSERT INTO #B SELECT 103,'C','A01'
INSERT INTO #B SELECT 104,'D','A02'
INSERT INTO #B SELECT 105,'E','A02'
INSERT INTO #B SELECT 106,'F','A02'
INSERT INTO #B SELECT 107,'G','A01'


SELECT A.S_NO,B.S_NAME,B.S_CLASS,A.S_NUM INTO #C  FROM #A A LEFT JOIN #B B ON A.S_NO=B.S_NO

SELECT * FROM #C A
WHERE (SELECT COUNT(*) FROM #C WHERE S_CLASS=A.S_CLASS AND S_NUM>A.S_NUM)<2
AND  EXISTS (SELECT 1 FROM #C WHERE S_CLASS=A.S_CLASS AND S_NUM>A.S_NUM )


DROP TABLE #A,#B,#C


/**
S_NO       S_NAME     S_CLASS    S_NUM       
---------- ---------- ---------- ----------- 
101        A          A01        80
103        C          A01        80
106        F          A02        88

[jimoshatan]

分数有相同的时候，全部出来。没有相同的就出一条

[s_hluo]

select Name from B join A on B.Number = A.Number where A.Score = (
   select top 1 Score from (select distinct top 2 Score from A order by Score desc) as T order by Score
)

[中国风]

select
	*
from 
	(select a.Number,b.Name,b.Class,dense_rank()over(partition by b.Class order by a.Score desc) num from A join B on a.Number=b.Number)t
where
	num=2

05用rank/dense_rank區分並列排名

[ljhcy99]

select 姓名
from
(
select 姓名,Row_number()over(partition by 班级,学号 order by 成绩) as num
from
(select 学生表.学号 as 学号 ,学生表.班级 as 班级, 学生表.姓名 as 姓名, 成绩表.成绩 as 成绩
from 成绩表,学生表
where 学生表.学号=成绩表.学号 ) as AA ) AS Tab

where num = 2

[jimoshatan]

CREATE TABLE #A (S_NO VARCHAR(10),S_NUM INT)
INSERT INTO #A SELECT 101,80
INSERT INTO #A SELECT 102,65
INSERT INTO #A SELECT 103,80
INSERT INTO #A SELECT 104,75
INSERT INTO #A SELECT 105,95
INSERT INTO #A SELECT 106,88
INSERT INTO #A SELECT 107,90

CREATE TABLE #B (S_NO VARCHAR(10),S_NAME VARCHAR(10),S_CLASS VARCHAR(10))
INSERT INTO #B SELECT 101,'A','A01'
INSERT INTO #B SELECT 102,'B','A01'
INSERT INTO #B SELECT 103,'C','A01'
INSERT INTO #B SELECT 104,'D','A02'
INSERT INTO #B SELECT 105,'E','A02'
INSERT INTO #B SELECT 106,'F','A02'
INSERT INTO #B SELECT 107,'G','A01'


SELECT A.S_NO,B.S_NAME,B.S_CLASS,A.S_NUM INTO #C  FROM #A A LEFT JOIN #B B ON A.S_NO=B.S_NO

SELECT * 
FROM #C A
WHERE (SELECT COUNT(DISTINCT S_NUM) FROM #C WHERE  S_CLASS=A.S_CLASS AND S_NUM<A.S_NUM)=1


DROP TABLE #A,#B,#C

[jane0228]

第一次发贴，谢谢大家的帮忙了哈~