高手进来指点下

[fred_zhu]

要求：定义3个重载函数add（），分别实现两个整数，两个整分数的相加运算，以及两个字符串的合并运算
以下是小弟写的程序，但是感觉有点繁琐，欢迎大家来交流指证

#include <iostream>
#include <string.h>
using namespace std;
#define BUF_LEN 10


int add(int a, int b)
{
return a+b;
}


struct fraction
{
int son;
int mum;
};


void add(struct fraction *a,struct fraction *b)
{
a->son = (b->son * a->mum) + (a->son * b->mum);
a->mum *= b->mum;
}


void getLine(char* &p_data) //读入字符串函数
{
char char_buf[BUF_LEN],*p_temp=NULL;
int len=1;
cout < <"Type a line,press enter to end:\n";

do
{
cin.get(char_buf,BUF_LEN);
len += strlen(char_buf);
p_data = new char[len];

if(p_data == NULL)
{
cout < <"Not enough memory from the heap.\n";
return;
}

if(p_temp == NULL)
strcpy(p_data,char_buf);
else
{
strcpy(p_data,p_temp);
strcat(p_data,char_buf);
}
delete[]p_temp;
p_temp = p_data;

if(cin.peek() == '\n')
{
cin.get();
break;
}
}while(true);
}


void add(char *a,char *b) //连接字符串
{
strcat(a,b);
}


void main()

{

int a,b;
char *p_string1,*p_string2;
struct fraction struct1,struct2,*p_struct1,*p_struct2;


cout < <"input your integer numbers!\n";

cin>>a;

cin>>b;

cout < <add(a,b) < <endl;


p_struct1 = &struct1;
p_struct2 = &struct2;

cout < <"input two fractions!\n";

cin>>p_struct1->son;

cin>>p_struct1->mum;

cin>>p_struct2->son;

cin>>p_struct2->mum;

add(p_struct1,p_struct2);

cout < <"the sum of the fractions is" < <(float)p_struct1->son/p_struct1->mum < <endl;


getLine(p_string1);

cout < <p_string1 < <endl;

getLine(p_string2);

cout < <p_string2 < <endl;

add(p_string1,p_string2);

cout < <p_string1 < <endl;

delete[]p_string1;
delete[]p_string2;
}

[fred_zhu]

谁帮我看下啊

[霍大脚]

不套格式，没有注释，直接飘

[就呆在云上]

程序很简单啦，就是分配空间没有把握好，我修改了，就是注释的地方
你看看：

#include <iostream> 
#include <string.h> 
using namespace std; 
//10不够大，用100比较好
#define BUF_LEN 100

struct fraction 
{ 
	int son; 
	int mum; 
};

void add(struct fraction *a,struct fraction *b) 
{ 
	a->son = (b->son * a->mum) + (a->son * b->mum); 
	a->mum *= b->mum;  
} 

int add(int a, int b) 
{ 
	return a+b; 
} 

void add(char *a,char *b)    //连接字符串 
{ 
	strcat(a,b); 
} 

void getLine(char* &p_data)      //读入字符串函数 
{ 
	char char_buf[BUF_LEN],*p_temp=NULL; 
	int len=1; 
	cout <<"Type a line,press enter to end:\n"; 
	do 
	{ 
		cin.get(char_buf,BUF_LEN); 
		/////strlen 是0，因为这个时候没有空间是0，只要你写就会越界，修改之
		len += sizeof(char_buf); 
		p_data = new char[len]; 

		if(p_data == NULL) 
		{ 
			cout <<"Not enough memory from the heap.\n"; 
			return; 
		} 

		if(p_temp == NULL) 
			strcpy(p_data,char_buf); 
		else 
		{ 
			strcpy(p_data,p_temp); 
			strcat(p_data,char_buf); 
		} 
		delete[]p_temp; 
		p_temp = p_data; 

		if(cin.peek() == '\n') 
		{ 
			cin.get(); 
			break; 
		} 
	}while(true); 
} 

void main() 
{ 
	int a,b; 
	char *p_string1,*p_string2; 

	getLine(p_string1); 
	cout <<p_string1 <<endl; 
	getLine(p_string2); 
	cout <<p_string2 <<endl; 
	add(p_string1,p_string2);

	struct fraction struct1,struct2,*p_struct1,*p_struct2; 
	cout <<"input your integer numbers!\n"; 
	cin>>a; 
	cin>>b; 
	cout <<add(a,b) <<endl; 
	p_struct1 = &struct1; 
	p_struct2 = &struct2; 
	cout <<"input two fractions!\n";
	cin>>p_struct1->son; 
	cin>>p_struct1->mum; 
	cin>>p_struct2->son; 
	cin>>p_struct2->mum; 
	add(p_struct1,p_struct2); 
	cout <<"the sum of the fractions is" 
		<<(float)p_struct1->son/p_struct1->mum <<endl; 
 
	cout <<p_string1 <<endl;

 	delete[]p_string1; 
 	delete[]p_string2; 
}

[Qlaiaqu]

貌似我很无聊，给你参考一下

#include <iostream>
#include <string.h>
using namespace std;
#define BUF_LEN 10


int add(int a, int b)
{
	return a+b;
}


struct fraction
{
	int son;
	int mum;
};


void add(struct fraction *a,struct fraction *b)
{
	a->son = (b->son * a->mum) + (a->son * b->mum);
	a->mum *= b->mum; 
}


void getLine(char* &p_data)      //读入字符串函数
{
	char char_buf[BUF_LEN];
	cout <<"Type a line,press enter to end:\n";
	(cin>>char_buf).get();

	p_data = new char[strlen(char_buf)+1];
	if(p_data == NULL)
	{
		cout <<"Not enough memory from the heap.\n"; 
		exit(0);
	}

	for(int i = 0; i < strlen(p_data); i++)
		p_data[i] = char_buf[i];
}


void add(char* &a,char *b)    //连接字符串
{
	char *temp = new char[strlen(a)+strlen(b)+1];
	strcpy(temp,a);
	strcat(temp,b);
	a = temp;
}


int main()
{

	int a,b;
	char *p_string1,*p_string2;
	fraction *p_struct1 = new fraction ,*p_struct2 = new fraction;

	cout <<"input your integer numbers!\n";
	cin>>a>>b;
	cout <<add(a,b) <<endl;

	cout <<"input two fractions!\n";
	cin>>p_struct1->son>>p_struct1->mum>>p_struct2->son>>p_struct2->mum;
	add(p_struct1,p_struct2);
	cout <<"the sum of the fractions is" <<(float)p_struct1->son/p_struct1->mum <<endl;

	getLine(p_string1);
	cout <<p_string1 <<endl;
	getLine(p_string2);
	cout <<p_string2 <<endl;
	add(p_string1,p_string2);
	cout <<p_string1 <<endl;
	delete[] p_string1;
	delete[] p_string2;

	return 0;
}

[BaihowFF]

额...为什么不用模板写呢?
把整分数的类的加号重载一下就ok了啊...

[wangqi1357]

新手报到，学习中，大家帮助大家，新手提高中。