读xml返回dataset问题

[mdh_zl]

<env:Envelope xmlns:env="http://schemas.xmlsoap.org/soap/envelope/"><env:Header></env:Header><env:Body><com:locationSearchResponse xmlns:com="com.hrs.soap.hrs"><locationSearchResponse><responseTimeMillis>40</responseTimeMillis><resultCode>0</resultCode><locations><locationName>北京火车站</locationName><locationISO3Language>chn</locationISO3Language><iso3Country>chn</iso3Country><locationId>48979</locationId><poiId>18375</poiId><geoPosition><latitude>39.90289</latitude><longitude>116.4207</longitude></geoPosition></locations><locations><locationName>北京首都国际机场</locationName><locationISO3Language>chn</locationISO3Language><iso3Country>chn</iso3Country><locationId>48979</locationId><poiId>18373</poiId><geoPosition><latitude>40.07941</latitude><longitude>116.58707</longitude></geoPosition></locations><locations><locationName>北京展览馆</locationName><locationISO3Language>chn</locationISO3Language><iso3Country>chn</iso3Country><locationId>48979</locationId><poiId>18374</poiId><geoPosition><latitude>39.93774</latitude><longitude>116.33805</longitude></geoPosition></locations></locationSearchResponse></com:locationSearchResponse></env:Body></env:Envelope>

xml文章是这样的
我想把locations读到dataset中 望大家帮忙

[chuxue1342]

    ''' <summary>
    ''' 根据XML文件返回表
    ''' </summary>
    ''' <param name="id"></param>
    ''' <param name="path"></param>
    ''' <returns></returns>
    ''' <remarks></remarks>
    Public Function getdata(ByVal path As String) As DataView
        Dim dt As DataTable = New DataTable()
        Dim dv As DataView = New DataView()
        Dim stream As FileStream = New FileStream(Server.MapPath(path), FileMode.Open)
        Dim doc As XmlDataDocument = New XmlDataDocument
        doc.DataSet.ReadXml(New StreamReader(stream))
        dt = doc.DataSet.Tables(0)
        dv = dt.DefaultView
        stream.Close()
        Return dv
    End Function

[pgameli]

DataSet.ReadXml(文件名)
DataTable=DataSet.table[0]

这样简单点

[chuxue1342]

写个C#的!

DataSet getds(string path)
{
FileSteam fs=New FileStrea(Server.MapPath(path),FileMode.Open);
XmlDataDocument doc=New XmlDataDocument();
doc.DataSet.ReadXml(New StreamReader(fs));
DataSet ds=New DataSet();
ds=doc.DataSet;
Return ds;
}

[wuyq11]

public static DataSet GetDataSetByXml(string strXmlPath)
{
try
{
DataSet ds = new DataSet();
ds.ReadXml(GetXmlFullPath(strXmlPath));
if(ds.Tables.Count > 0)
{
return ds;
}
return null;
}
catch(Exception)
{
return null;
}
}

[BernardSun]

DataSet xmlDataSet = new DataSet();
        xmlDataSet.ReadXml(Server.MapPath("~/App_Data/locations.xml"));

        DataTable dt = xmlDataSet.Tables[0];

[jiang_jiajia10]

[Quote=引用 3 楼 chuxue1342 的回复:]
写个C#的!

C# code
DataSet getds(string path)
{
FileSteam fs=New FileStrea(Server.MapPath(path),FileMode.Open);
XmlDataDocument doc=New XmlDataDocument();
doc.DataSet.ReadXml(New StreamReader(fs));
DataSet ds=New DataSet();
ds=doc.DataSet;
Return ds;
}
[/Quote]
强

[HDNGO]

ReadXml~

[mengxj85]

System.Data.DataSet ds = new DataSet();
ds.ReadXml(Server.MapPath("phonebook.xml"));
gv.DataSource = ds;
gv.DataBind();

[yefengzhixia]

学习。。
恩 顶了 ！！ 虽然我不知道为什么。。。。呵呵呵 欢迎加入c#新群 63242231 共同学习

[antiking]

DataSet dsXml = new DataSet(); try
{
dsXml.ReadXml(new System.IO.MemoryStream(System.Text.Encoding.UTF8.GetBytes(strXml)));
}
catch (Exception ex)
{
throw new Exception("读取XML出错!");
return;
}

[gongsun]

没话说了，凑个热闹。

[zhnzzy]

[Quote=引用 2 楼 pgameli 的回复:]
DataSet.ReadXml(文件名)
DataTable=DataSet.table[0]

这样简单点
[/Quote]

这个就可以，很简单

[wuxyu]

我就是用的这个方法,读xml中几十条还可以,但是读一个1千条记录的XML,只读了244条,就不反应了,是不是性能的问题啊?