关于XML的读写问题!!

[whhitli]

<?xml version="1.0" encoding="utf-8" ?>
<book>
<lovel>
<name>jim</name>
<author>罗曼罗兰</author>
</lovel>
<lovel>
<name>lucy</name>
<author>杰克逊</author>
</lovel>
</book>

我可以根据"jim"找到"罗曼罗兰"这个信息吗?
要是有的话，怎么的一个读法，还有就是怎么添加节点！！！

我刚刚接触XML，急着用，没办法，请各位帮忙！！！！！

[jhdxhj]

<?xml version="1.0" encoding="utf-8" ?>
<configuration>
<MotherTongue lalTitle = "24小时天气预报"
lalWeatherType = "天气类型"
lalMax = "最高温度"
lalMin = "最低温度"
btnSet="设置"
title="天气预报"
btnCancel="取消"
>
</MotherTongue>
<English lalTitle = "24-hour weather forecast"
lalWeatherType = "weather type"
lalMax = "maximum temperature"
lalMin = "minimum temperature"
btnSet="set"
title="weather forecast"
btnCancel="cancel"
>
</English>
</configuration>
void LoadCfgFile()
{

XmlDocument x = new XmlDocument();
x.Load("LanguageXml/WeatherForm.xml");
switch (MainForm._nLanguage)
{
case 1:
XmlNodeList xnl = x.SelectNodes("/configuration/MotherTongue");
this.lalMax.Text = xnl[0].Attributes["lalMax"].InnerText;
this.lalMin.Text = xnl[0].Attributes["lalMin"].InnerText;
this.lalTitle.Text = xnl[0].Attributes["lalTitle"].InnerText;
this.btnSet.Text = xnl[0].Attributes["btnSet"].InnerText;
this.btnCancel.Text = xnl[0].Attributes["btnCancel"].InnerText;
this.lalWeatherType.Text = xnl[0].Attributes["lalWeatherType"].InnerText;
this.Text = xnl[0].Attributes["title"].InnerText;




break;
case 2:
XmlNodeList xnl1 = x.SelectNodes("/configuration/English");
this.lalMax.Text = xnl1[0].Attributes["lalMax"].InnerText;
this.lalMin.Text = xnl1[0].Attributes["lalMin"].InnerText;
this.lalTitle.Text = xnl1[0].Attributes["lalTitle"].InnerText;
this.btnSet.Text = xnl1[0].Attributes["btnSet"].InnerText;
this.btnCancel.Text = xnl1[0].Attributes["btnCancel"].InnerText;
this.lalWeatherType.Text = xnl1[0].Attributes["lalWeatherType"].InnerText;
this.Text = xnl1[0].Attributes["title"].InnerText;
break;

}
}

[Hertz_liu]

用我这个，包你搞定，接分~~

static string Search()
        {
            string author="";
            XmlDocument doc = new XmlDocument();
            doc.Load(@"你XML文件的路径");
            XmlNodeList nodelist = doc.SelectSingleNode("book").ChildNodes;
            foreach (XmlNode xn in nodelist)
            {               
                string name = node.SelectSingleNode("name").InnerText;
                if(name.equal("jim"))
                {
                    author= node.SelectSingleNode("author").InnerText;
                }
            }
            return author;
       }

[HDNGO]

[Quote=引用 2 楼 liu2008hz 的回复:]
用我这个，包你搞定，接分~~

C# code
static string Search()
{
string author="";
XmlDocument doc = new XmlDocument();
doc.Load(@"你XML文件的路径");
XmlNodeList nodelist = doc.SelectSingleNode("book").ChildNodes;
foreach (XmlNode xn in nodelist)
{
string name = node.SelectSingl…
[/Quote]

hehe ~

[孟子E章]

XmlNode node = doc.SelectSingleNode("/book/lovel[name='jim']/author");
node.InnerText就是

[wb186]

都学习啦 呵呵

[bingbingw]

呵呵~

[ws_hgo]

[Quote=引用 4 楼 net_lover 的回复:]


XmlNode node = doc.SelectSingleNode("/book/lovel[name='jim']/author");
node.InnerText就是
[/Quote]
用老大的

[whhitli]

二楼的大虾请回答：
说node没有定义，应该是什么类型的？

还有就是你的一点错误，String中不含equal()而是Equals()

[claymore1114]

ding

[whhitli]

12楼正解，不过还是要改一个地方：
name.equal("jim") 改为 name.Equals("jim")



谢谢各位的热心帮忙

结贴，散分喽！！！！
哈哈哈

[whhitli]

static string Search()
{

string author = "";
XmlDocument doc = new XmlDocument();
doc.Load("I:\\book.xml");
XmlNodeList nodelist = doc.SelectSingleNode("book").ChildNodes;
XmlNode node = doc.SelectSingleNode("/book/lovel[name='jim']/author");
foreach (XmlNode xn in nodelist)
{
string name = node.SelectSingleNode("name").InnerText;
if (Object.Equals(name, "jim"))
{
author = node.SelectSingleNode("author").InnerText;
}
}
return author;
}

string name = node.SelectSingleNode("name").InnerText;
这句话老出错！！
说什么"new"关键字创建对象实例；调用前检查确定对象是否为空！！

我把它先定义String name = "name";
还是不行！！

怎么回事？？？

[lvg]

up

[hangang7403]

static string Search()
{
string author="";
XmlDocument doc = new XmlDocument();
doc.Load("你XML文件的路径");
XmlNodeList nodelist = doc.SelectSingleNode("book").ChildNodes;
foreach (XmlNode xn in nodelist)
{
string name = xn.SelectSingleNode("name").InnerText;
if(name.equal("jim"))
{
author= xn.SelectSingleNode("author").InnerText;
}
}
return author;
}

[daxiaxl]

ding