数组比较

[gonguui1982]

两个数组如何比较是否相同,忽略元素的顺序.
例如{a,b} 和{b,a} 这2个数组怎么比能比较出他们是相同的.有现成的方法吗?

[wwmwenzhu]

没有，排序后比较每一个元素！！

[CloneCenter]

1楼说的没错，建议排序后比较每个元素。

[GTX280]

1楼正解

[gonguui1982]

谢谢,我正在冒泡呢,呵呵

[vrhero]

值类型数组可以用Linq...

return a.Except(b).Count==0 && b.Except(a).Count==0;

引用类型只有排序后循环比对了...

[非凡之臂]

int memcmp(
const void* buf1,
const void* buf2,
size_t count
);

inline int wmemcmp(
const wchar_t* buf1,
const wchar_t* buf2,
size_t count
);

#include <string.h>
#include <stdio.h>

void main( void )
{
char first[] = "12345678901234567890";
char second[] = "12345678901234567891";
int result;

printf( "Compare '%.19s' to '%.19s':\n", first, second );
result = memcmp( first, second, 19 );
if( result < 0 )
printf( "First is less than second.\n" );
else if( result == 0 )
printf( "First is equal to second.\n" );
else if( result > 0 )
printf( "First is greater than second.\n" );
printf( "Compare '%.20s' to '%.20s':\n", first, second );
result = memcmp( first, second, 20 );
if( result < 0 )
printf( "First is less than second.\n" );
else if( result == 0 )
printf( "First is equal to second.\n" );
else if( result > 0 )
printf( "First is greater than second.\n" );
}
Output
Compare '1234567890123456789' to '1234567890123456789':
First is equal to second.
Compare '12345678901234567890' to '12345678901234567891':
First is less than second.