去掉重复行--100分

2008-12-20 08:07:32 155 阅读 AI 写同款 · GEO 优化AI 选题数据监测一键分发 ›

如何生成100个，1-100不重复的随机数列表。使用Python实现，获取100个不重复的，1-100的随机数列。首先我们使用的是Python语言来实现得到100个1-100的随机不重复的整数，这个在一些公司的笔试题目当中出现过，也是一个考验基础代码能力的一个练习题，下面我们就用代码的实现这个需求。实现思路 1.首先我们要引入Python自带的随机数的模块random，来实现获取随机数。 2.对获取到的随机数进行一个判断，产生的这个随机数是否与已有的随机数重复，对不重复的随机数进行添加。 3.判断随机数的个数是否达到100个。 4.对以上的三步进行一阅读详情

3个uid一样的,表1的id是自动增长的。按照时间排序
怎样去除表1重复的uid，按照表1的id排序

select mdate,y.uid,x.姓名
from 表1 y,表2 x,表3 z
where y.uid=x.uid and y.uid=z.uid
order by y.id desc

表1
id uid mdate
----------- ----------- ------------------------------------------------------
1 409 2003-10-08 08:55:41.983
2 327 2003-10-08 08:58:41.327
3 72 2003-10-09 14:51:36.013
4 549 2003-10-09 19:23:07.153
5 549 2003-10-11 19:23:07.153
6 549 2003-10-21 19:23:07.153
7 327 2003-10-22 08:58:41.327
8 327 2003-10-23 08:58:41.327

表2
uid 姓名部門
327 張三 a
549 李四 c
327 李四 b

表2
uid type
327 1
549 1

怎样去掉

...全文

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loveASUS

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切换为时间正序

dawugui 2008-12-20

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[Quote=引用 7 楼 loveASUS 的回复:]
表1
id uid mdate
----------- ----------- ------------------------------------------------------
1 409 2003-10-08 08:55:41.983
2 327 2003-10-08 08:58:41.327
3 72 2003-10-09 14:51:36.013
4 549 2003-10-09 19:23:07.153
5 549 2003-10-11 19:23:07.153
6 549 2003-10-21 19:23:07.153
7 327 2003-10-22 08:58:41.327
8 327 2003-10-23 08:58:41.327
. ......

表2
uid 姓名部門
327 張三 a
549 李四 c
327 李3 b
....

表3
uid type
327 1
549 1
550 2
....

3个表
表1 mdate 为用户登陆时间
表2 姓名
表3 type 为类型

检索出前20个登陆的用户（姓名和时间） type类型为1

[/Quote]
--你的表2有两个327,所以测试数据的结果有重复值,你自己更改以下,如果需要取前20个,加select top 20 * from ... order by ...

create table tb1(id int, uid int, mdate datetime)

insert into tb1 values( 1 , 409 , '2003-10-08 08:55:41.983') 

insert into tb1 values( 2 , 327 , '2003-10-08 08:58:41.327') 

insert into tb1 values( 3 , 72 , '2003-10-09 14:51:36.013') 

insert into tb1 values( 4 , 549 , '2003-10-09 19:23:07.153') 

insert into tb1 values( 5 , 549 , '2003-10-11 19:23:07.153') 

insert into tb1 values( 6 , 549 , '2003-10-21 19:23:07.153') 

insert into tb1 values( 7 , 327 , '2003-10-22 08:58:41.327') 

insert into tb1 values( 8 , 327 , '2003-10-23 08:58:41.327') 

create table tb2( uid int, 姓名 varchar(10) , 部門 varchar(10))

insert into tb2 values( 327 , '張三', 'a') 

insert into tb2 values( 549 , '李四', 'c') 

insert into tb2 values( 327 , '李3 ', 'b') 

create table tb3 (uid int, type int) 

insert into tb3 values( 327 , 1 )

insert into tb3 values( 549 , 1 ) 

insert into tb3 values( 550 , 2 )

go



select t1.* , t2.* , t3.* from

(select t.* from tb1 t where mdate = (select max(mdate) from tb1 where uid = t.uid)) t1,

tb2 t2 , tb3 t3

where t1.uid = t2.uid and t1.uid = t3.uid and t3.type = 1



drop table tb1 , tb2  , tb3



/*

id          uid         mdate                                                  uid         姓名         部門         uid         type        

----------- ----------- ------------------------------------------------------ ----------- ---------- ---------- ----------- ----------- 

8           327         2003-10-23 08:58:41.327                                327         張三         a          327         1

6           549         2003-10-21 19:23:07.153                                549         李四         c          549         1

8           327         2003-10-23 08:58:41.327                                327         李3         b          327         1



（所影响的行数为 3 行）



*/

mengxj85 2008-12-20

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Mark

百年树人 2008-12-20

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select top 20

  b.姓名,

  a.mdate as 时间

from 表1 a,表2 b,表3 c

where a.uid=b.uid and b.uid=c.uid

and c.type=1

and not exists(select * from 表1 where uid=a.uid and mdate>a.mdate)

order by a.id

loveASUS 2008-12-20

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最后一次登陆时间

百年树人 2008-12-20

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liangCK 2008-12-20

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如果是最早的.则将最后的ORDER BY A.mdate DESC中的DESC去掉即可.

liangCK 2008-12-20

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SELECT TOP 20

    A.uid,

    A.mdate,

    B.姓名,

    B.部门,

    C.type

FROM(

    SELECT *

    FROM tb1 AS A

    WHERE mdate=(SELECT MAX(mdate)

                 FROM tb1

                 WHERE A.uid=uid)

) AS A

    JOIN tb2 AS B

        ON A.uid=B.uid

    JOIN tb3 AS C

        ON A.uid=C.uid

           AND C.type=1

ORDER BY A.mdate DESC

loveASUS 2008-12-20

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表2写错了

表2
uid 姓名部門
327 張三 a
549 李四 c
550 唐三 b

loveASUS 2008-12-20

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表1
id uid mdate
----------- ----------- ------------------------------------------------------
1 409 2003-10-08 08:55:41.983
2 327 2003-10-08 08:58:41.327
3 72 2003-10-09 14:51:36.013
4 549 2003-10-09 19:23:07.153
5 549 2003-10-11 19:23:07.153
6 549 2003-10-21 19:23:07.153
7 327 2003-10-22 08:58:41.327
8 327 2003-10-23 08:58:41.327
. ......

表2
uid 姓名部門
327 張三 a
549 李四 c
327 李3 b
....

表3
uid type
327 1
549 1
550 2
....

3个表
表1 mdate 为用户登陆时间
表2 姓名
表3 type 为类型

检索出前20个登陆的用户（姓名和时间） type类型为1

liangCK 2008-12-20

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你想要什么样的结果?

loveASUS 2008-12-20

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select mdate,y.uid,x.姓名
from 表1 y,表2 x,表3 z
where y.uid=x.uid and y.uid=z.uid
order by y.id desc

百年树人 2008-12-20

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[Quote=引用 2 楼 loveASUS 的回复:]
就是检索出来的数据去掉重复行，

怎么写啊？

就是检索出来的数据去掉重复行，

怎么写啊？

就是检索出来的数据去掉重复行，

怎么写啊？

就是检索出来的数据去掉重复行，

怎么写啊？
[/Quote]

请说说原来的结果是什么，你要的结果是什么？

changjiangzhibin 2008-12-20

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--试一下

select distinct mdate,y.uid,x.姓名 

from 表1 y,表2 x,表3 z 

where y.uid=x.uid and y.uid=z.uid 

order by y.id desc 



--也可使用Group by 分组试一下

loveASUS 2008-12-20

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就是检索出来的数据去掉重复行，

怎么写啊？

就是检索出来的数据去掉重复行，

怎么写啊？

就是检索出来的数据去掉重复行，

怎么写啊？

就是检索出来的数据去掉重复行，

怎么写啊？

百年树人 2008-12-20

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--处理表重复记录(查询和删除)

/******************************************************************************************************************************************************

1、Num、Name相同的重复值记录,没有大小关系只保留一条

2、Name相同,ID有大小关系时,保留大或小其中一个记录

整理人：中国风(Roy)



日期:2008.06.06

******************************************************************************************************************************************************/



--1、用于查询重复处理记录(如果列没有大小关系时2000用生成自增列和临时表处理,SQL2005用row_number函数处理)



--> --> (Roy)生成測試數據

 

if not object_id('Tempdb..#T') is null

    drop table #T

Go

Create table #T([ID] int,[Name] nvarchar(1),[Memo] nvarchar(2))

Insert #T

select 1,N'A',N'A1' union all

select 2,N'A',N'A2' union all

select 3,N'A',N'A3' union all

select 4,N'B',N'B1' union all

select 5,N'B',N'B2'

Go





--I、Name相同ID最小的记录(推荐用1,2,3),方法3在SQl05时，效率高于1、2

方法1:

Select * from #T a where not exists(select 1 from #T where Name=a.Name and ID<a.ID)



方法2:

select a.* from #T a join (select min(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID



方法3:

select * from #T a where ID=(select min(ID) from #T where Name=a.Name)



方法4:

select a.* from #T a join #T b on a.Name=b.Name and a.ID>=b.ID group by a.ID,a.Name,a.Memo having count(1)=1 



方法5:

select * from #T a group by ID,Name,Memo having ID=(select min(ID)from #T where Name=a.Name)



方法6:

select * from #T a where (select count(1) from #T where Name=a.Name and ID<a.ID)=0



方法7:

select * from #T a where ID=(select top 1 ID from #T where Name=a.name order by ID)



方法8:

select * from #T a where ID!>all(select ID from #T where Name=a.Name)



方法9(注:ID为唯一时可用):

select * from #T a where ID in(select min(ID) from #T group by Name)



--SQL2005:



方法10:

select ID,Name,Memo from (select *,min(ID)over(partition by Name) as MinID from #T a)T where ID=MinID



方法11:



select ID,Name,Memo from (select *,row_number()over(partition by Name order by ID) as MinID from #T a)T where MinID=1



生成结果:

/*

ID          Name Memo

----------- ---- ----

1           A    A1

4           B    B1



(2 行受影响)

*/





--II、Name相同ID最大的记录,与min相反:

方法1:

Select * from #T a where not exists(select 1 from #T where Name=a.Name and ID>a.ID)



方法2:

select a.* from #T a join (select max(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID order by ID



方法3:

select * from #T a where ID=(select max(ID) from #T where Name=a.Name) order by ID



方法4:

select a.* from #T a join #T b on a.Name=b.Name and a.ID<=b.ID group by a.ID,a.Name,a.Memo having count(1)=1 



方法5:

select * from #T a group by ID,Name,Memo having ID=(select max(ID)from #T where Name=a.Name)



方法6:

select * from #T a where (select count(1) from #T where Name=a.Name and ID>a.ID)=0



方法7:

select * from #T a where ID=(select top 1 ID from #T where Name=a.name order by ID desc)



方法8:

select * from #T a where ID!<all(select ID from #T where Name=a.Name)



方法9(注:ID为唯一时可用):

select * from #T a where ID in(select max(ID) from #T group by Name)



--SQL2005:



方法10:

select ID,Name,Memo from (select *,max(ID)over(partition by Name) as MinID from #T a)T where ID=MinID



方法11:

select ID,Name,Memo from (select *,row_number()over(partition by Name order by ID desc) as MinID from #T a)T where MinID=1



生成结果2:

/*

ID          Name Memo

----------- ---- ----

3           A    A3

5           B    B2



(2 行受影响)

*/







--2、删除重复记录有大小关系时,保留大或小其中一个记录





--> --> (Roy)生成測試數據



if not object_id('Tempdb..#T') is null

    drop table #T

Go

Create table #T([ID] int,[Name] nvarchar(1),[Memo] nvarchar(2))

Insert #T

select 1,N'A',N'A1' union all

select 2,N'A',N'A2' union all

select 3,N'A',N'A3' union all

select 4,N'B',N'B1' union all

select 5,N'B',N'B2'

Go



--I、Name相同ID最小的记录(推荐用1,2,3),保留最小一条

方法1:

delete a from #T a where  exists(select 1 from #T where Name=a.Name and ID<a.ID)



方法2:

delete a  from #T a left join (select min(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID where b.Id is null



方法3:

delete a from #T a where ID not in (select min(ID) from #T where Name=a.Name)



方法4(注:ID为唯一时可用):

delete a from #T a where ID not in(select min(ID)from #T group by Name)



方法5:

delete a from #T a where (select count(1) from #T where Name=a.Name and ID<a.ID)>0



方法6:

delete a from #T a where ID<>(select top 1 ID from #T where Name=a.name order by ID)



方法7:

delete a from #T a where ID>any(select ID from #T where Name=a.Name)







select * from #T



生成结果:

/*

ID          Name Memo

----------- ---- ----

1           A    A1

4           B    B1



(2 行受影响)

*/





--II、Name相同ID保留最大的一条记录:



方法1:

delete a from #T a where  exists(select 1 from #T where Name=a.Name and ID>a.ID)



方法2:

delete a  from #T a left join (select max(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID where b.Id is null



方法3:

delete a from #T a where ID not in (select max(ID) from #T where Name=a.Name)



方法4(注:ID为唯一时可用):

delete a from #T a where ID not in(select max(ID)from #T group by Name)



方法5:

delete a from #T a where (select count(1) from #T where Name=a.Name and ID>a.ID)>0



方法6:

delete a from #T a where ID<>(select top 1 ID from #T where Name=a.name order by ID desc)



方法7:

delete a from #T a where ID<any(select ID from #T where Name=a.Name)





select * from #T

/*

ID          Name Memo

----------- ---- ----

3           A    A3

5           B    B2



(2 行受影响)

*/











--3、删除重复记录没有大小关系时，处理重复值





--> --> (Roy)生成測試數據

 

if not object_id('Tempdb..#T') is null

    drop table #T

Go

Create table #T([Num] int,[Name] nvarchar(1))

Insert #T

select 1,N'A' union all

select 1,N'A' union all

select 1,N'A' union all

select 2,N'B' union all

select 2,N'B'

Go



方法1:

if object_id('Tempdb..#') is not null

    drop table #

Select distinct * into # from #T--排除重复记录结果集生成临时表#



truncate table #T--清空表



insert #T select * from #    --把临时表#插入到表#T中



--查看结果

select * from #T



/*

Num         Name

----------- ----

1           A

2           B



(2 行受影响)

*/



--重新执行测试数据后用方法2

方法2:



alter table #T add ID int identity--新增标识列

go

delete a from  #T a where  exists(select 1 from #T where Num=a.Num and Name=a.Name and ID>a.ID)--只保留一条记录

go

alter table #T drop column ID--删除标识列



--查看结果

select * from #T



/*

Num         Name

----------- ----

1           A

2           B



(2 行受影响)



*/



--重新执行测试数据后用方法3

方法3:

declare Roy_Cursor cursor local for

select count(1)-1,Num,Name from #T group by Num,Name having count(1)>1

declare @con int,@Num int,@Name nvarchar(1)

open Roy_Cursor

fetch next from Roy_Cursor into @con,@Num,@Name

while @@Fetch_status=0

begin 

    set rowcount @con;

    delete #T where Num=@Num and Name=@Name

    set rowcount 0;

    fetch next from Roy_Cursor into @con,@Num,@Name

end

close Roy_Cursor

deallocate Roy_Cursor



--查看结果

select * from #T

/*

Num         Name

----------- ----

1           A

2           B



(2 行受影响)

*/

去掉重复行--100分

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