C++图形输出问题

[lengmozaixian]

编程实现输出以下图形：
n=1 1
4 5 2
3
n=2 1 2
8 9 10 3
7 12 11 4
6 5
n=3 1 2 3
12 13 14 15 4
11 20 21 16 5
10 19 18 17 6
9 8 7
n=4 1 2 3 4
16 17 18 19 20 5
15 28 29 30 21 6
14 27 32 31 22 7
13 26 25 24 23 8
12 11 10 9

[arong1234]

这种题目要是教你可不是害了你？作业还是自己做吧

[glacier3d]

n^2+4n个数转圈，
直观的方法：分配各2维数组，利用i、j两个索引的不断变换，转圈填入数字即可

[太乙]

int n ;
int num;
int cols = 1, rows = 0;
while (num != (n+2)*(n+2)-4)
{
   arr[rows][cols] = num;
   决定rows,cols;
   num++;
}

[liubuweiright]

up

[jieao111]

用c++做，可惜了

[星羽]

#include "stdafx.h"

#include <iostream>
#include <iomanip>
using namespace std;

enum {lft, up, rigt, down};

int main()
{
    int n = 0;

    cout<<"n = ";
    cin>>n;
    
    int m = n + 2;
    int* data = new int[m * m];
    int x = 0;
    int y = 1;
    int v = 1;
    int f = rigt;

    memset(data, 0, sizeof(int) * m * m);

    while (data[x * m + y] == 0)
    {
        data[x * m + y] = v++;

        switch (f)
        {
        case lft :
            {
                if (data[x * m + y - 1] != 0 || y == 0 || (x == m - 1 && y == 1))
                {
                    if (x == m - 1 && y == 1)
                        --y;
                    --x;                 
                    f = up;
                }
                else
                    --y;
            }
            break;
        case up :
            {
                if (data[(x - 1) * m + y] != 0 || x == 0 || (x == 1 && y == 0))
                {
                    ++y;
                    f = rigt;
                }
                else
                    --x;
            }
            break;
        case rigt :
            {
                if (data[x * m + y + 1] != 0 || y == m - 1 || (x == 0 && y == m - 2))
                {
                    if (x == 0 && y == m - 2)
                        ++y;
                    ++x;
                    f = down;
                }
                else
                    ++y;
            }
            break;
        case down :
            {
                if (data[(x + 1) * m + y] != 0 || x == m - 1 || (x == m - 2 && y == m - 1))
                {
                    if (x == m - 2 && y == m - 1)
                        ++x;
                    --y;                 
                    f = lft;
                }
                else
                    ++x;
            }
            break;
        default :
            break;
        }
    }

    cout<<endl;

    for (int x = 0; x < m; ++x)
    {
        for (int y = 0; y < m; ++y)
        {
            if ((x == 0 && y == 0) ||
                (x == m - 1 && y == 0) ||
                (x == 0 && y == m - 1) ||
                (x == m - 1 && y == m - 1) 
                )
                cout<<setw(3)<<" ";
            else
                cout<<setw(3)<<data[x * m + y];
        }
        cout<<endl;
    }

    delete data;

    return 0;
}

-------------------


n = 4

     1  2  3  4
 16 17 18 19 20  5
 15 28 29 30 21  6
 14 27 32 31 22  7
 13 26 25 24 23  8
    12 11 10  9


n = 8

     1  2  3  4  5  6  7  8
 32 33 34 35 36 37 38 39 40  9
 31 60 61 62 63 64 65 66 41 10
 30 59 80 81 82 83 84 67 42 11
 29 58 79 92 93 94 85 68 43 12
 28 57 78 91 96 95 86 69 44 13
 27 56 77 90 89 88 87 70 45 14
 26 55 76 75 74 73 72 71 46 15
 25 54 53 52 51 50 49 48 47 16
    24 23 22 21 20 19 18 17

[fiyaa]

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