ajax 处理返回值的问题

Kangkang1314 2008-12-29 03:31:20

返回值：
HTTP/1.1 200 OK
Connection: close
Date: Mon, 29 Dec 2008 06:38:41 GMT
Server: Microsoft-IIS/6.0
X-Powered-By: ASP.NET
X-Powered-By: PHP/5.1.4
Content-type: text/html

 <br />
<b>Notice </b>: Undefined index: txtBackDate in <b>E:\web\ibe\ibe_service\index.php </b> on line <b>68 </b> <br />
<br />
<b>Notice </b>: Undefined index: radio in <b>E:\web\ibe\ibe_service\index.php </b> on line <b>71 </b> <br />
<html>
<head>
<body>
<form ...>
<input type="hidden" name="tt[]" value="xxxxxxxxxxxx" />
<input type="hidden" name="tt[]" value="xxxxxxxxttt" />
<input type="hidden" name="tt[]" value="xxxxxxaaaaa" />
<input type="hidden" name="tt[]" value="xxxxxxxxyyyy" />
请问，如何得到这个返回值中的 tt 表单数组的值

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LIHY70 2008-12-29

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var re = new RegExp("name=\"tt(.*) value=\"(.*)\"","g");





var str = xmlHttp.responseText;

var arr= str.match(re);



for(var i=0;i< arr.length;i++){

	alert(arr[i].replace(re,"$2"));

}