c++程序逆向输出一整数

[meetyu]

#include <iostream.h>
#include <math.h>

int main()
{ int a;
long dvin=0;
long mc;
long ini_val;
int preset=0;

do{cout < <"Please enter a integer between 99999 to 1:"
< <endl;
cin>>ini_val;
} while(ini_val <0||ini_val>99999);
mc=ini_val;
while(mc)
{++preset;
mc/=10;
}
mc=ini_val;
for(int i;i <preset;i++)
{a=mc%10;
dvin+=a*pow(10,(preset-i-1));
mc/=10;
}
cout < <preset < <endl;
cout < <"The begin_value is:" < <ini_val < <endl;
cout < <"The dvin_value is:" < <dvin;
return 0;
}
这程序错在那里..
cout < <"the dvin_value is:dvin;输出结果为0.

[meetyu]

犯了错误啦..多谢大家指出...中文表达不好..哈哈..是123,求出结果是321的意思

[lbh2001]

for(int i;i <preset;i++) -----> for(int i = 0;i <preset;i++)

[sunhuanwen]

如一楼

另外问一下，“逆向输出一整数”是什么意思啊？

[nullah]

[Quote=引用 2 楼 sunhuanwen 的回复:]
如一楼

另外问一下，“逆向输出一整数”是什么意思啊？
[/Quote]
4321---->1234

#include <iostream> 
#include <cmath> 
using namespace std;

int main() 
{  
    int a; 
    long dvin = 0; 
    long mc; 
    long ini_val; 
    int  preset=0; 

    do
    {
        cout <<"Please enter a integer between 99999 to 1:" <<endl; 
        cin >> ini_val; 
    }
    while(ini_val <0||ini_val>99999); 
    mc=ini_val; 
    while(mc) 
    {
        ++preset; 
        mc/=10; 
    } 
    mc=ini_val; 
    for(int i=0;i<preset;i++) //局部变量未初始值
    {
        a=mc%10; 
        dvin+=a*pow((float)10,(float)(preset-i-1)); ///pow
        mc/=10; 
    } 
    cout << preset <<endl; 
    cout <<"The begin_value is:" <<ini_val <<endl; 
    cout <<"The dvin_value is:" <<dvin; 
    return 0; 
} 

[china_west]

不错[Quote=引用 3 楼 nullah 的回复:]
引用 2 楼 sunhuanwen 的回复:
如一楼

另外问一下，“逆向输出一整数”是什么意思啊？

4321---->1234


C/C++ code
#include <iostream>
#include <cmath>
using namespace std;

int main()
{
int a;
long dvin = 0;
long mc;
long ini_val;
int preset=0;

do
{
cout <<"Please enter a integer between 99999 to 1:" <<endl;
cin >> …
[/Quote]

[davelv]

直接把输入的数字当字符处理就OK~~

[bennyyyyy]

#include <iostream.h>
#include <math.h>

int main()
{ int a;
long dvin=0;
long mc;
long ini_val;
int preset=0;

do{cout < <"Please enter a integer between 99999 to 1:"
< <endl;
cin>>ini_val;
} while(ini_val <0||ini_val>99999);
mc=ini_val;
while(mc)
{++preset;
mc/=10;
}
mc=ini_val;
for(int i=0;i <preset;i++) //这里错
{a=mc%10;
dvin+=a*pow(10,(preset-i-1));
mc/=10;
}
cout < <preset < <endl;
cout < <"The begin_value is:" < <ini_val < <endl;
cout < <"The dvin_value is:" < <dvin;
return 0;
}

[booksky508]

一楼正解。

[bennyyyyy]

#include "stdafx.h"
#include<iostream>
#include<cmath>
using namespace std;


int _tmain(int argc, _TCHAR* argv[])
{
int a;
long dvin=0;
long mc;
long ini_val;
int preset=0;

cout <<"Please enter a integer between 99999 to 1:" <<endl;
cin>>ini_val;

mc=ini_val;
while(mc)
{++preset;
mc/=10;
}
mc=ini_val;
for(int i=0;i <preset;i++)
{a=mc%10;
dvin+=a*pow((double)10,(preset-i-1));
mc/=10;
}
cout <<preset <<endl;
cout <<"The begin_value is:" <<ini_val <<endl;
cout <<"The dvin_value is:" <<dvin;
cin>>a;
return 0;

}