webwork 无法工作错误

ailijia365 2009-01-07 02:45:52

配置了webwork+spring+Hibernate框架，tomcat出现如下错误

异常

org.apache.jasper.JasperException: Could not create ActionMapper: WebWork will *not* work!
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:512)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:395)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)

起因

Could not create ActionMapper: WebWork will *not* work! - Class: com.opensymphony.xwork.spring.SpringObjectFactory
File: SpringObjectFactory.java
Method: buildBean
Line: 114 - com/opensymphony/xwork/spring/SpringObjectFactory.java:114:-1
com.opensymphony.webwork.dispatcher.mapper.ActionMapperFactory.getMapper(ActionMapperFactory.java:41)
com.opensymphony.webwork.views.jsp.TagUtils.buildNamespace(TagUtils.java:74)
com.opensymphony.webwork.components.Component.determineNamespace(Component.java:344)
com.opensymphony.webwork.components.Form.populateComponentHtmlId(Form.java:194)
com.opensymphony.webwork.components.UIBean.evaluateParams(UIBean.java:836)
com.opensymphony.webwork.components.UIBean.end(UIBean.java:591)
com.opensymphony.webwork.views.jsp.ComponentTagSupport.doEndTag(ComponentTagSupport.java:21)
org.apache.jsp.index_jsp._jspx_meth_ww_form_0(index_jsp.java:153)
org.apache.jsp.index_jsp._jspService(index_jsp.java:82)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:97)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:334)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)

页面代码：



<%@ page language="java" contentType="text/html; charset=UTF-8"%>

<%@ taglib uri="WEB-INF/webwork.tld" prefix="ww"%>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">

<html>

  <head>

    

    <title>增加图书</title>

<%

 System.out.println("request path: +++++++++======== "+request.getContextPath());

%>

  <script src='<%=request.getContextPath()%>/dwr/interface/dao.js'></script>

  <script src='<%=request.getContextPath()%>/dwr/engine.js'></script>

  <script src='<%=request.getContextPath()%>/dwr/util.js'></script>

  </head>

  

  <body>

  

  <ww:form action="addBook.action" method="post">

  

    <table width="505" height="327" border="1">

	  <tr>

	    <td width="146">p书名：<br></td>

	    <td width="343"><input type="text" name="name" id="name" /></td>

	  </tr>

	  <tr>

	    <td>作者：</td>

	    <td><input type="text" name="author" id="author" /></td>

	  </tr>

	  <tr>

	    <td>出版时间：</td>

	    <td><input type="text" name="publishtime" id="publishtime" /></td>

	  </tr>

	  <tr>

	    <td>出版社：</td>

	    <td><input type="text" name="publish" id="publish" /></td>

	  </tr>

	  <tr>

	    <td>简介：</td>

	    <td><input type="text" name="des" id="des" /></td>

	  </tr>

	  <tr>

	  	<input type="submit" name="tijiao" id="tijiao" value="增加图书" />

	  </tr>

	</table>

	</ww:form>

  </body>

</html>

xwork.xml是如下代码



<!DOCTYPE xwork PUBLIC "-//OpenSymphony Group//XWork 1.0//EN" "http://www.opensymphony.com/xwork/xwork-1.1.dtd">

<xwork>

   <include file="webwork-default.xml" />

   <package name="default" extends="webwork-default">

      

	  

	  <action name="addBook" class="com.zjrj.book.addBookAction">

       	  	<external-ref name="dao">dao</external-ref>

	  	<result name="success" type="dispatcher">

            <param name="location">/index.jsp</param>

         </result>

         <interceptor-ref name="defaultStack"/>       

	  </action>

	  

   </package>

</xwork>

这个到底该怎么解决的啊~~~~

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wsx324111 2009-01-08

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可能是你xwork里写错了

ailijia365 2009-01-08

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<!DOCTYPE xwork PUBLIC "-//OpenSymphony Group//XWork 1.0//EN" "http://www.opensymphony.com/xwork/xwork-1.1.dtd">

<xwork>

   <include file="webwork-default.xml" />

   <package name="default" extends="webwork-default"

   		externalReferenceResolver="com.atlassian.xwork.ext.SpringServletContextReferenceResolver">

	<interceptors>

<interceptor name="reference-resolver" class="com.opensymphony.xwork.interceptor.ExternalReferencesInterceptor"/>

<interceptor-stack name="myDefaultWebStack">

<interceptor-ref name="defaultStack"/>

<interceptor-ref name="reference-resolver"/>

</interceptor-stack>

</interceptors>

      

	  <default-interceptor-ref name="defaultStack" />

	  <action name="addBook" class="com.zjrj.book.addBookAction">

        <!-- 将spring中配置的javaBean(dao)注入到webwork的action类中-->

	  	<external-ref name="dao">Dao</external-ref>

	  	<result name="success" type="dispatcher">

            <param name="location">success.jsp</param>

         </result>

         <interceptor-ref name="reference-resolver"></interceptor-ref>

	  </action>

	  

	  <action name="hello" class="org.HelloAction">

      	<result name="error" type="dispatcher">MyJsp.jsp</result>

      	<result name="success" type="dispatcher">success2.jsp</result>

    	</action>

	  

   </package>

</xwork>

现在变成这样了的，可还是不行额。。。

不过在web.xml里面如果用servlet的话就是可以的额。。。用filter却不行，这个是什么原因啊，我用的webwork的包是2.2.5的

ailijia365 2009-01-07

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是的，我网上搜索，也有人是这样说的，但是该如何解决的呢？

ailijia365 2009-01-07

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web.xml中关于webwork的设置如下



<!--(BEGIN)WEBWORK框架配置-->

  <filter>

  	<filter-name>webwork</filter-name>

    <filter-class>com.opensymphony.webwork.dispatcher.FilterDispatcher</filter-class>

  </filter>

  

  <filter-mapping>

    <filter-name>webwork</filter-name>

    <url-pattern>*.action</url-pattern>

  </filter-mapping>

  <!--(END)WEBWORK框架配置-->

自己感觉是对的额。。。

pxcong007 2009-01-07