十六进制数怎么转化为十进制数？

[jukyy]

小问题一个，谢谢！

[tokens]

HexToInt

[jimzj]

StrToInt

[tokens]

错了。。好象只有IntToHex,没有HexToInt.sorry

[chifengwatch]

void __fastcall TForm1::Button1Click(TObject *Sender)
{
int i = 0x65 ;
Button1->Caption = IntToStr( i ) ;
}
//---------------------------------------------------------------------------

[jukyy]

的确没有HexToInt的。
chifengwatch(chifengwatch) 什么意思呀，看不明白。

[猎人66]

AnsiString Str="0x65";
int i=StrToInt(Str);

[jukyy]

有了，我自己写了一个函数。

[lyzq]

struct DateTimeB
{
byte YearLow;
byte YearHigh;
byte Month;
byte Day;
byte Hour;
byte Minute;
byte Second;
};
struct DateTimeI
{
int Year;
int Month;
int Day;
int Hour;
int Minute;
int Second;
};
TimeBg.Year=256*BeginTime.YearHigh+BeginTime.YearLow;
TimeBg.Month=BeginTime.Month;
TimeBg.Day=BeginTime.Day;
TimeBg.Hour=BeginTime.Hour;
TimeBg.Minute=BeginTime.Minute;
TimeBg.Second=BeginTime.Second;
这是我刚写的,没来得及改就抄到这里了其中TimeBg里的所有成员都是INT型
BeginTime中的所有成员都是byte型,直接赋值就可以拉,你看适合不适合你的需要?

[fleamboy]

这样最简单：

String sHex="FE";
sHex = "0x" + sHex;
int nDec=StrToInt(sHex);

[POLOM]

用这个函数：（stdlib.h中）
long strtol(const char *s, char **endptr, int radix);

对参数radix的解释：
If radix is between 2 and 36, the long integer is expressed in base radix. If radix is 0, the first few characters of s determine the base of the value being converted.

First character Second character String interpreted as...

0 1 - 7 Octal
0 x or X Hexadecimal
1 - 9 Decimal

If radix is 1, it is considered to be an invalid value. If radix is less than 0 or greater than 36, it is considered to be an invalid value.

Any invalid value for radix causes the result to be 0 and sets the next character pointer *endptr to the starting string pointer.

[POLOM]

#include <stdlib.h>
#include <stdio.h>

int main(void)
{
char *string = "ABC123", *endptr;
long lnumber;

/* strtol converts string to long integer */
lnumber = strtol(string, &endptr, 16);
printf("string = %s long = %ld\n", string, lnumber);

return 0;
}