C#中异常处理问题

[jojogh]

小弟遇到一个问题，就是如何对某个代码进行异常处理，代码如下：

public class Normal
{
//double mu;
//double sigma;

public static double NormalPDF(double mu, double sigma, double x)
{
return Math.Pow(2 * Math.PI * sigma * sigma, -0.5) * Math.Exp(-(x - mu) * (x - mu) / 2 * sigma * sigma);
}
}

这里的sigma必须大于零，我想自定义一个异常处理，不知道这一块该如何写？请大家给予帮助，谢谢！

[eynStudio]

自定义
public class myException : Exception
{
private string msg;
public myException(string Msg)
: base()
{
msg = Msg;
}
public override string ToString()
{
return msg;
}
}

引用
public class Normal
{
//double mu;
//double sigma;

public static double NormalPDF(double mu, double sigma, double x)
{
if(!sigma>0)
throw new myException("sigma必须大于零");
return Math.Pow(2 * Math.PI * sigma * sigma, -0.5) * Math.Exp(-(x - mu) * (x - mu) / 2 * sigma * sigma);
}
}

[宝_爸]

可以直接使用系统定义的异常:ArgumentOutOfRangeException

参见:
ms-help://MS.MSDNQTR.v90.en/fxref_mscorlib/html/aaf07529-5d87-324a-1a9c-55c86d78f952.htm


Sample Code:

using System;

class Program
{
	static void Main(string[] args)
	{
		Guest guest1 = new Guest("Ben", "Miller", 17);
		Console.WriteLine(guest1.GuestInfo());
	}
}

class Guest
{
	private string FirstName;
	private string LastName;
	private int Age;

	public Guest(string fName, string lName, int age)
	{
		FirstName = fName;
		LastName = lName;
		if (age < 21)
			throw new ArgumentOutOfRangeException("age","All guests must be 21-years-old or older.");
		else
			Age = age;
	}

	public string GuestInfo()
	{
		string gInfo = FirstName + " " + LastName + ", " + Age.ToString();
		return(gInfo);
	}
}

[jojogh]

我试试！

[wenrenhua08]

[Quote=引用 1 楼 eynStudio 的回复:]
自定义
public class myException : Exception
{
private string msg;
public myException(string Msg)
: base()
{
msg = Msg;
}
public override string ToString()
{
return msg;
}
}

引用
public class Normal

{
//double mu;
//double sigma;

…
[/Quote]
这位兄台的就很简洁

[jojogh]

结贴给分！