InitList_Sq(SqList &L);与InitList_Sq(&L);的区别？

[sunxlbutu]

这是实现顺序表的初始化c程序：
#include "stdio.h"
#include "stdlib.h"

#define OVERFLOW 0
#define OK 1

#define LIST_INIT_SIZE 100
#define LISTINCREMENT 10

typedef struct {
int *elem;
int length;
int listsize;
}SqList;

int InitList_Sq(SqList *L);

int main()
{
SqList L;

InitList_Sq(SqList &L);

system("pause");
return 0;

};

int InitList_Sq(SqList *L)
{
L->elem = (int *)malloc(LIST_INIT_SIZE * sizeof(int));
if(!L->elem) exit(OVERFLOW);

L->length = 0;
L->listsize = LIST_INIT_SIZE;

return OK;
}
其中 InitList_Sq(SqList &L); 出错：
--------------------Configuration: 线性表的顺序表示 - Win32 Debug--------------------
Compiling...
线性表的顺序表示.cpp
F:\MyProject\线性表的顺序表示\线性表的顺序表示.cpp(22) : error C2275: 'SqList' : illegal use of this type as an expression
F:\MyProject\线性表的顺序表示\线性表的顺序表示.cpp(14) : see declaration of 'SqList'
Error executing cl.exe.

线性表的顺序表示.obj - 1 error(s), 0 warning(s)

如果把 InitList_Sq(SqList &L); 改为 InitList_Sq(&L); 后编译就不会出错，这是为什么呢？

[雪鹰翔天]

    SqList L; //这里定义了

    InitList_Sq(SqList &L); 

[爱摸鱼de老邪]

[Quote=引用 1 楼 freedomzcd 的回复:]
C/C++ codeSqList L;//这里定义了InitList_Sq(SqList&L);
[/Quote]
如楼上所言，你重复定义了

[雪鹰翔天]

int InitList_Sq(SqList *L);//形参是个指针,只需要赋指针(地址)给它就可以了

[雪鹰翔天]

函数调用弄明白了就好了....

int InitList_Sq(SqList *L); //函数声明.形参为指针

int main() 
{ 
    SqList L; 

    InitList_Sq(SqList &L); //此处是函数调用,传递实参,需要赋指针或地址,即&L

    system("pause"); 
    return 0; 

}; 

int InitList_Sq(SqList *L) 
{ 
    L->elem = (int *)malloc(LIST_INIT_SIZE * sizeof(int)); 
    if(!L->elem) exit(OVERFLOW); 

    L->length = 0; 
    L->listsize = LIST_INIT_SIZE; 

    return OK; 
}

[daodan988]

1楼正解

[sunxlbutu]

这么一回事啊
谢谢啦