quartz 配置问题 急

[一路长跑]

我用quartz管理线程，有个线程我想 tomcat启动后就启动，并且只启动一次。
我在spring配置文件里这样写：
<bean id="IcListenJobTrigger"
class="org.springframework.scheduling.quartz.SimpleTriggerBean">
<property name="jobDetail" ref="IceListenJob" />
<!-- <property name="cronExpression" value="* * * * * ?" />-->
<property name="startDelay" value="10"/>
<property name="repeatInterval" value="0L"/>

<property name="repeatCount" value="0"/>

<property name="jobDataAsMap">
<map>
<entry key="comPort" value="11111" />
</map>
</property>
</bean>


启动后报错：org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'startQuertz' defined in ServletContext resource [/WEB-INF/classes/applicationContext.xml]: Cannot resolve reference to bean 'IcListenJobTrigger' while setting bean property 'triggers' with key [1]; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'IceListenJobTrigger' defined in ServletContext resource [/WEB-INF/classes/applicationContext.xml]: Initialization of bean failed; nested exception is org.springframework.beans.TypeMismatchException: Failed to convert property value of type [java.lang.String] to required type [long] for property 'repeatInterval'; nested exception is java.lang.NumberFormatException: For input string: "L"

Caused by: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'IcListenJobTrigger' defined in ServletContext resource [/WEB-INF/classes/applicationContext.xml]: Initialization of bean failed; nested exception is org.springframework.beans.TypeMismatchException: Failed to convert property value of type [java.lang.String] to required type [long] for property 'repeatInterval'; nested exception is java.lang.NumberFormatException: For input string: "L"

Caused by: org.springframework.beans.TypeMismatchException: Failed to convert property value of type [java.lang.String] to required type [long] for property 'repeatInterval'; nested exception is java.lang.NumberFormatException: For input string: "L"

Caused by: java.lang.NumberFormatException: For input string: "L"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)


明显 不认识spring不拿OL来做数据转换了，肯定出错。 哪位大哥有好的办法不？

[一路长跑]

貌似可以哦，傻了，哈哈，还是谢谢了。

[Johnson_Hong]

value="0L" 用“0L”不能转化为long,写成“0”不就行了吗