正则表达式 替换

[coley]

string strOld ="Case When (UserMoney<5000 and WorkAge<= 100) then (UserMoney * 0.92) When (WorkAge> 15) then (UserMoney * 0.95) End ";
如何用正则替换 then............when|end 之间的"UserMoney"字符,替换为"NewMoney"
谢谢

[liuyeede]

你直接找到“*”之前的UserMoney后换成NewMoney就可以了吧？

[coley]

呵呵,不行.strOld 是可变的,只能替换 then ...... when|end之间的

[cppfaq]

直接不行么？

str.Replace("oldValue","newValue")

[cppfaq]

[Quote=引用 2 楼 coley 的回复:]
呵呵,不行.strOld 是可变的,只能替换 then ...... when|end之间的
[/Quote]
那就先str.Substring(str.IndexOf("then"))再Replace呢？

[liuyeede]

.+(?=*)

[coley]

[Quote=引用 4 楼 cppfaq 的回复:]
引用 2 楼 coley 的回复:
呵呵,不行.strOld 是可变的,只能替换 then ...... when|end之间的

那就先str.Substring(str.IndexOf("then"))再Replace呢？
[/Quote]
也要考虑效率,所以想正则一次就替换了,不用去拆分字符串处理.谢谢

[liuyeede]

(\bThen\b)(\w+(?=*))(?(\1)\bWhen\b)|(\bThen\b)(\w+(?=*))(?(\4)\bEnd\b)

[king19840811]

strOld 是可变的太难了。。

[CutBug]

string strOld = "Case  When (UserMoney >0 and WorkAge <= 100) then (UserMoney * 0.91) Case  When (UserMoney <5000 and WorkAge <= 100) then (UserMoney * 0.92) When (WorkAge> 15) then (UserMoney * 0.95) End ";
string p = @"(?<![\s\S]+when[\s\S]+)(When[\s\S]+)(UserMoney)(?=[\s\S]+End)";
strOld = Regex.Replace(strOld, p, "${1}aaa",RegexOptions.IgnoreCase);
Console.WriteLine(strOld);

输出
Case When (UserMoney >0 and WorkAge <= 100) then (UserMoney * 0.91) Case When
(UserMoney <5000 and WorkAge <= 100) then (UserMoney * 0.92) When (WorkAge> 15)
then (aaa * 0.95) End
请按任意键继续. . .

[-过客-]

正则委托典型应用...

string strOld = "Case  When (UserMoney <5000 and WorkAge <= 100) then (UserMoney * 0.92) When (WorkAge> 15) then (UserMoney * 0.95) End ";
string result = Regex.Replace(strOld, @"then((?!then|when|end)[\s\S])*(when|end)", delegate(Match m) { return m.Value.Replace("UserMoney", "NewMoney"); }, RegexOptions.IgnoreCase);
richTextBox2.Text = result;

[a6225822]

sadasd

[a6225822]

ddd